(Problem 49)Prime permutations
The arithmetic sequence, 1487, 4817, 8147, in which each of the terms increases by 3330, is unusual in two ways: (i) each of the three terms are prime, and, (ii) each of the 4-digit numbers are permutations of one another.
There are no arithmetic sequences made up of three 1-, 2-, or 3-digit primes, exhibiting this property, but there is one other 4-digit increasing sequence.
What 12-digit number do you form by concatenating the three terms in this sequence?
题目大意:
1487, 4817, 8147这个序列,每个比前一个递增3330,而且这个序列有两个特点:1. 序列中的每个数都是质数。2. 每个四位数都是其他数字的一种排列。
1,2,3位组成的三个质数的序列中没有具有以上性质的。但是还有另外一个四位的递增序列满足这个性质。
如果将这另外一个序列的三个数连接起来,组成的12位数字是多少?
//(Problem 49)Prime permutations
// Completed on Thu, 13 Feb 2014, 15:35
// Language: C
//**********************************************
// 版权所有(C)acutus (mail: acutus@126.com)
// 博客地址:http://www.cnblogs.com/acutus///**********************************************
#include<stdio.h>
#include<stdbool.h>
#include<stdlib.h>
#include<string.h>
int a[]; bool prim(int n)
{
int i;
for(i = ; i * i <= n; i++) {
if(n % i ==) return false;
}
return true;
} int cmp(const void *a, const void *b)
{
return (*(char*)a - *(char*)b);
} void init()
{
int i, j;
i = ;
j = ;
a[] = ;
while(j < ) {
if(prim(i)) {
a[j++] = i;
}
i += ;
}
} bool judge(int a, int b, int c)
{
char A[], B[], C[];
sprintf(A, "%d", a);
qsort(A, , sizeof(char), cmp);
sprintf(B, "%d", b);
qsort(B, , sizeof(char), cmp);
sprintf(C, "%d", c);
qsort(C, , sizeof(char), cmp);
if(strcmp(A, B)== && strcmp(A, C) == )
return true;
return false;
} void solve()
{
int i, b, c, d;
i = ;
init();
while(a[i++] < );
for(; i < ; i++) {
b = a[i]; c = a[i] + ; d = a[i] + ;
if(d < ) {
if(prim(b) && prim(c) && prim(d)) {
if(judge(b, c, d)) {
printf("%d %d %d\n", b, c, d);
}
}
}
} } int main()
{
solve();
return ;
}
Answer:
|
296962999629 |
(Problem 49)Prime permutations的更多相关文章
- (Problem 62)Cubic permutations(待续)
The cube, 41063625 (3453), can be permuted to produce two other cubes: 56623104 (3843) and 66430125 ...
- (Problem 41)Pandigital prime
We shall say that an n-digit number is pandigital if it makes use of all the digits 1 to n exactly o ...
- (Problem 70)Totient permutation
Euler's Totient function, φ(n) [sometimes called the phi function], is used to determine the number ...
- (Problem 46)Goldbach's other conjecture
It was proposed by Christian Goldbach that every odd composite number can be written as the sum of a ...
- (Problem 47)Distinct primes factors
The first two consecutive numbers to have two distinct prime factors are: 14 = 2 7 15 = 3 5 The fi ...
- (Problem 37)Truncatable primes
The number 3797 has an interesting property. Being prime itself, it is possible to continuously remo ...
- (Problem 35)Circular primes
The number, 197, is called a circular prime because all rotations of the digits: 197, 971, and 719, ...
- (Problem 33)Digit canceling fractions
The fraction 49/98 is a curious fraction, as an inexperienced mathematician in attempting to simplif ...
- (Problem 29)Distinct powers
Consider all integer combinations ofabfor 2a5 and 2b5: 22=4, 23=8, 24=16, 25=32 32=9, 33=27, 34=81, ...
随机推荐
- 【OpenCV新手教程之十二】OpenCV边缘检測:Canny算子,Sobel算子,Laplace算子,Scharr滤波器合辑
本系列文章由@浅墨_毛星云 出品,转载请注明出处. 文章链接:http://blog.csdn.net/poem_qianmo/article/details/25560901 作者:毛星云(浅墨) ...
- android开发利器--站在巨人肩膀上前行
本文主要介绍有助于android开发的三方平台和站点. 一:开发阶段 1:SVN(一个开放源码的版本号控制系统) 团队开发没有server,代码管理就没那么方便了,推荐taocode阿里开源站点,方便 ...
- java自己主动生成验证码
代码结构: web.xml <? xml version="1.0" encoding="UTF-8"?> <web-app version= ...
- android-带进度条的系统通知栏消息
效果图: 主界面只有一个按钮就不上文件了 通知栏显示所用到的布局文件content_view.xml <?xml version="1.0" encoding="u ...
- 开源ceph管理平台inkscope部署手册
一.前情提要 关于inkscope就不做过多介绍了,就是ceph的一个开源管理控制平台,跟ceph官方的calamary以及intel的VSM差不多一类,只是各自侧重点不一样. 相对而言,因为inks ...
- CSS定位深入理解 完全掌握CSS定位 相对定位和绝对定位
其实前面的标准流和浮动流都很理解,就是定位不太好理解,特别是相对定位和绝对定位,很多刚开始学的同学不好区分.因此这里,小强老师和大家一起分享CSS定位的学习. 通过我们前面的学习,我们网页布局方法: ...
- Convert Sorted List to Balanced Binary Search Tree (BST)
(http://leetcode.com/2010/11/convert-sorted-list-to-balanced-binary.html) Given a singly linked list ...
- Windows下提升进程权限(转)
from: http://www.oschina.net/code/snippet_222150_19533 windows的每个用户登录系统后,系统会产生一个访问令牌(access token) , ...
- RTTI-CLASS
package com.xt.test; interface Test1Interface { } interface Test2Interface { } class Test1 implement ...
- 理解angular中的module和injector,即依赖注入
理解angular中的module和injector,即依赖注入 依赖注入(DI)的好处不再赘言,使用过spring框架的都知道.angularjs作为前台js框架,也提供了对DI的支持,这是java ...