bzoj1752 [Usaco2005 qua]Til the Cows Come Home
Description
<= N <= 1000) landmarks in it, uniquely numbered 1..N. Landmark 1 is the barn; the apple tree grove in which Bessie stands all day is landmark N. Cows travel in the field using T (1 <= T <= 2000) bidirectional cow-trails of various lengths between the landmarks.
Bessie is not confident of her navigation ability, so she always stays on a trail from its start to its end once she starts it. Given the trails between the landmarks, determine the minimum distance Bessie must walk to get back to the barn. It is guaranteed
that some such route exists.
Input
Output
Sample Input
5 5
1 2 20
2 3 30
3 4 20
4 5 20
1 5 100
INPUT DETAILS:
There are five landmarks.
Sample Output
90
OUTPUT DETAILS:
Bessie can get home by following trails 4, 3, 2, and 1.
这题各种单源最短路都能过
#include<cstdio>
#include<cstring>
int n,m,x,y,z,cnt,t,w=1;
int head[10001];
struct edge{
int to,next,v;
}e[50001];
int q[50001];
bool mark[50001];
int dist[50001];
inline void ins(int u,int v,int w)
{
e[++cnt].v=w;
e[cnt].to=v;
e[cnt].next=head[u];
head[u]=cnt;
}
void insert(int u,int v,int w)
{
ins(u,v,w);
ins(v,u,w);
}
inline int read()
{
int x=0,f=1;char ch=getchar();
while(ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}
while(ch>='0'&&ch<='9'){x=x*10+ch-'0';ch=getchar();}
return x*f;
}
inline void spfa()
{
q[1]=1;
mark[1]=1;
dist[1]=0;
while (t<w)
{
int now=q[++t];
for (int i=head[now];i;i=e[i].next)
if (dist[now]+e[i].v<dist[e[i].to])
{
dist[e[i].to]=dist[now]+e[i].v;
if (!mark[e[i].to])q[++w]=e[i].to;
}
mark[now]=0;
}
}
int main()
{
m=read();n=read();
memset(dist,127/3,sizeof(dist));
for(int i=1;i<=m;i++)
{
x=read();y=read();z=read();
insert(x,y,z);
}
spfa();
printf("%d",dist[n]);
}
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