POJ 1129 Channel Allocation DFS 回溯
Time Limit: 1000MS | Memory Limit: 10000K | |
Total Submissions: 15546 | Accepted: 7871 |
Description
Since the radio frequency spectrum is a precious resource, the number of channels required by a given network of repeaters should be minimised. You have to write a program that reads in a description of a repeater network and determines the minimum number of channels required.
Input
Following the number of repeaters is a list of adjacency relationships. Each line has the form:
A:BCDH
which indicates that the repeaters B, C, D and H are adjacent to the repeater A. The first line describes those adjacent to repeater A, the second those adjacent to B, and so on for all of the repeaters. If a repeater is not adjacent to any other, its line has the form
A:
The repeaters are listed in alphabetical order.
Note that the adjacency is a symmetric relationship; if A is adjacent to B, then B is necessarily adjacent to A. Also, since the repeaters lie in a plane, the graph formed by connecting adjacent repeaters does not have any line segments that cross.
Output
Sample Input
2
A:
B:
4
A:BC
B:ACD
C:ABD
D:BC
4
A:BCD
B:ACD
C:ABD
D:ABC
0
Sample Output
1 channel needed.
3 channels needed.
4 channels needed.
POJ 1129 Channel Allocation DFS 回溯的更多相关文章
- poj 1129 Channel Allocation ( dfs )
题目:http://poj.org/problem?id=1129 题意:求最小m,使平面图能染成m色,相邻两块不同色由四色定理可知顶点最多需要4种颜色即可.我们于是从1开始试到3即可. #inclu ...
- 迭代加深搜索 POJ 1129 Channel Allocation
POJ 1129 Channel Allocation Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 14191 Acc ...
- POJ 1129 Channel Allocation(DFS)
Channel Allocation Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 13173 Accepted: 67 ...
- POJ 1129 Channel Allocation 四色定理dfs
题目: http://poj.org/problem?id=1129 开始没读懂题,看discuss的做法,都是循环枚举的,很麻烦.然后我就决定dfs,调试了半天终于0ms A了. #include ...
- poj 1129 Channel Allocation(图着色,DFS)
题意: N个中继站,相邻的中继站频道不得相同,问最少需要几个频道. 输入输出: Sample Input 2 A: B: 4 A:BC B:ACD C:ABD D:BC 4 A:BCD B:ACD C ...
- poj 1129 Channel Allocation
http://poj.org/problem?id=1129 import java.util.*; import java.math.*; public class Main { public st ...
- poj 1154 letters (dfs回溯)
http://poj.org/problem?id=1154 #include<iostream> using namespace std; ]={},s,r,sum=,s1=; ][]; ...
- PKU 1129 Channel Allocation(染色问题||搜索+剪枝)
题目大意建模: 一个有N个节点的无向图,要求对每个节点进行染色,使得相邻两个节点颜色都不同,问最少需要多少种颜色? 那么题目就变成了一个经典的图的染色问题 例如:N=7 A:BCDEFG B:ACDE ...
- POJ 1321 棋盘问题 (DFS + 回溯)
题目链接:http://poj.org/problem?id=1321 题意:中文题目,就不多说了...... 思路: 解题方法挺多,刚开始想的是先从N行中选择出来含有“#”的K行,再在这K行中放置K ...
随机推荐
- hihocoder 1671 反转子串
时间限制:10000ms 单点时限:1000ms 内存限制:256MB 描述 给定一个只包含括号和小写字母的字符串S,例如S="a(bc(de)fg)hijk". 其中括号表示将里 ...
- 【POJ 3076】 Sudoku
[题目链接] http://poj.org/problem?id=3076 [算法] 将数独问题转化为精确覆盖问题,用Dancing Links求解 [代码] #include <algorit ...
- leetcode树相关
目录 144前序遍历 94中序遍历(98验证二叉搜索树.230二叉搜索树中第K小的元素) 145后序遍历 102/107层次遍历(104二叉树最大深度.103 105从前序与中序遍历序列构造二叉树 1 ...
- WebService常用技术及术语
一.Web Service是什么? 1. 基于Web的服务:服务器端整出一些资源让客户端应用访问(获取数据) 2. 一个跨语言.跨平台的规范(抽象) 3. 多个跨平台.跨语言的应用间通信整合的方案(实 ...
- python实践
https://www.cnblogs.com/smallSevens/p/10016045.html --二手房交易记录 https://www.cnblogs.com/xiangyuecn/p/1 ...
- 编写linux 命令行实用工具 shell命令
今天我想以带着问题的方法学习新的技术. 问题1: 编写一个命令 语法: command options path expressions
- VS2015 右侧导航插件地址
右侧导航插件: https://marketplace.visualstudio.com/items?itemName=VisualStudioProductTeam.ProductivityPowe ...
- # --with-http_stub_status_module模块
作用: 查看nginx的客户端状态 环境检测 nginx -V 查看nginx已经编译的模块中是否包含--with-http_stub_status_module 语法: 效果
- Java 自定义线程池
Java 自定义线程池 https://www.cnblogs.com/yaoxiaowen/p/6576898.html public ThreadPoolExecutor(int corePool ...
- intellij 创建java web项目(maven管理的SSH)
intellij 创建java web项目(maven管理的SSH) 环境intellij IDEA14.MAVEN.Spring.Struts2.Hibernate.Java Web.工程搭建. 1 ...