Vowel Counting

Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other)
Total Submission(s) : 58   Accepted Submission(s) : 18
Problem Description
The "Vowel-Counting-Word"(VCW), complies with the following conditions. Each vowel in the word must be uppercase. Each consonant (the letters except the vowels) must be lowercase. For example, "ApplE" is the VCW of "aPPle", "jUhUA" is the VCW of "Juhua". Give you some words; your task is to get the "Vowel-Counting-Word" of each word.
 
Input
The first line of the input contains an integer T (T<=20) which means the number of test cases. For each case, there is a line contains the word (only contains uppercase and lowercase). The length of the word is not greater than 50.
 
Output
For each case, output its Vowel-Counting-Word.
 
Sample Input
4 XYz application qwcvb aeioOa
 
Sample Output
xyz ApplIcAtIOn qwcvb AEIOOA
 
Author
AppleMan
 
Source
HDU 2nd “Vegetable-Birds Cup” Programming Open Contest

 #include <stdio.h>
#include <stdlib.h>
#include <string.h> int main()
{
int T,L,i;
char a[];
scanf("%d",&T);
while(T--)
{
scanf("%s",a);
L=strlen(a);
for(i=;i<L;i++)
{
if(a[i]=='a'||a[i]=='e'||a[i]=='i'||a[i]=='o'||a[i]=='u')
{
a[i]-=;
continue;
}
else if(a[i]=='A'||a[i]=='E'||a[i]=='I'||a[i]=='O'||a[i]=='U')
{
continue;
}
else
{
if(a[i]>='A'&&a[i]<='Z')
{
a[i]+=;
continue;
}
}
}
printf("%s\n",a);
}
return ;
}

Vowel Counting的更多相关文章

  1. 杭电oj 3079 Vowel Counting

    Tips:可以先将输入的字符串全部转化为小写字母,然后再将元音字母变为大写,时间复杂度O(n) #include<stdio.h> #include<string.h> #in ...

  2. HDU 3079 Vowel Counting (水题。。。判断元音)

    题意:n个字符串,如果元音就是输出大写,否则输出小写. 析:没啥可说的,只要判断AEIOU就OK了. 代码如下: #include <iostream> #include <cstd ...

  3. 杭电OJ(HDU)-ACMSteps-Chapter Two-《An Easy Task》《Buildings》《decimal system》《Vowel Counting》

    http://acm.hdu.edu.cn/game/entry/problem/list.php?chapterid=1§ionid=2 1.2.5 #include<stdio.h> ...

  4. 萌新笔记——Cardinality Estimation算法学习(二)(Linear Counting算法、最大似然估计(MLE))

    在上篇,我了解了基数的基本概念,现在进入Linear Counting算法的学习. 理解颇浅,还请大神指点! http://blog.codinglabs.org/articles/algorithm ...

  5. POJ_2386 Lake Counting (dfs 错了一个负号找了一上午)

    来之不易的2017第一发ac http://poj.org/problem?id=2386 Lake Counting Time Limit: 1000MS   Memory Limit: 65536 ...

  6. ZOJ3944 People Counting ZOJ3939 The Lucky Week (模拟)

    ZOJ3944 People Counting ZOJ3939 The Lucky Week 1.PeopleConting 题意:照片上有很多个人,用矩阵里的字符表示.一个人如下: .O. /|\ ...

  7. find out the neighbouring max D_value by counting sort in stack

    #include <stdio.h> #include <malloc.h> #define MAX_STACK 10 ; // define the node of stac ...

  8. 1004. Counting Leaves (30)

    1004. Counting Leaves (30)   A family hierarchy is usually presented by a pedigree tree. Your job is ...

  9. 6.Counting Point Mutations

    Problem Figure 2. The Hamming distance between these two strings is 7. Mismatched symbols are colore ...

随机推荐

  1. date,datetime,timestamp 的区别

    date 表示年月日,如YY-MM-DD datetime 表示年月日和时间信息,如YY-MM-DD HH:MM:SS datestamp 和datetime表示的信息相同,但时间范围不同 时间范围 ...

  2. ubuntu tips

    1.ibus-setup 2.tips:

  3. intellij idea 12 搭建maven web项目 freemarker + spring mvc

    配置spring mvc ,写这篇文章的时候spring已经出了4.0 这里还是用稳定的3.2.7.RELEASE,先把spring和freemarker配置好 1.spring mvc配置 在web ...

  4. ubuntu 安装python mysql模块

    Installation Starting with a vanilla Lucid install , install pip and upgrade to the latest version: ...

  5. 《Windows编程循序渐进》——MFC封装机制详解

    单文档

  6. mobiscroll 插件札记(一)

    mobiscroll 插件笔记(一) 文章参照  http://www.cnblogs.com/headwolf/archive/2013/12/23/3487207.html 最近切一个移动页面,需 ...

  7. @Transactional注解详解

    默认遇到throw new RuntimeException("...");会回滚   需要捕获的throw new Exception("...");不会回滚 ...

  8. Java Object 对象拷贝答疑

    Java Object 对象拷贝答疑 @author ixenos 摘要:在对象的clone过程需要注意的几点.关于关键字this.super 关于clone[对象拷贝] 在实际编程过程,有时候我们会 ...

  9. 浙大 pat 1007题解

    Given a sequence of K integers { N1, N2, ..., NK }. A continuous subsequence is defined to be { Ni, ...

  10. 禁止使用test类的就是禁止使用本来的$this对象.可以调用父类的对象

    public function __construct() { parent::__construct( ); parent::__construct( ); if(!APP_DEBUG ) die( ...