HDU_1027_Ignatius and the Princess II_全排列
Ignatius and the Princess II
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 6701 Accepted Submission(s):
3964
He opens the door and finds feng5166 is about to kill our pretty Princess. But
now the BEelzebub has to beat our hero first. feng5166 says, "I have three
question for you, if you can work them out, I will release the Princess, or you
will be my dinner, too." Ignatius says confidently, "OK, at last, I will save
the Princess."
"Now I will show you the first problem." feng5166 says,
"Given a sequence of number 1 to N, we define that 1,2,3...N-1,N is the smallest
sequence among all the sequence which can be composed with number 1 to N(each
number can be and should be use only once in this problem). So it's easy to see
the second smallest sequence is 1,2,3...N,N-1. Now I will give you two numbers,
N and M. You should tell me the Mth smallest sequence which is composed with
number 1 to N. It's easy, isn't is? Hahahahaha......"
Can you help Ignatius
to solve this problem?
consists of two numbers, N and M(1<=N<=1000, 1<=M<=10000). You may
assume that there is always a sequence satisfied the BEelzebub's demand. The
input is terminated by the end of file.
sequence satisfied the BEelzebub's demand. When output a sequence, you should
print a space between two numbers, but do not output any spaces after the last
number.
11 8
1 2 3 4 5 6 7 9 8 11 10
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<iostream>
using namespace std; int a[];
int main()
{
int n,m;
while(scanf("%d%d",&n,&m)!=EOF)
{
for(int i=;i<n;i++)
a[i]=i+;
m--;
while(m--)
{
next_permutation(a,a+n);
}
for(int i=;i<n;i++)
{
if(i!=n-)
printf("%d ",a[i]);
else
printf("%d\n",a[i]);
}
}
return ;
}
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