怎样将Arranged_2压入General_Polygon_set_2中
Thursday, March 14, 2013
How to Jam an Arrangement_2 into a General_polygon_set_2
昨天我花了近3个小时追踪一个怪异的CGAL的bug——我写那个程序是为了从arrangement中构建出多边形的集合,然后导出这些多边形,而奇怪的多边形
To my annoyance, I discovered today as I went to write the bug up that I knew about this bug...over three
years ago. :-( I get annoyed when I search for the answer to an obscure OpenGL problem and find my own post (e.g. I'm not going to find anything I didn't already know), but it's even more annoying to waste hours on the bug and then have that happen.
让我气愤只是的是,我今天去记录这个问题是发现我事实上在三年前就遇到过了。:-(当我搜索明显的OpengGL问题然后发现了自己的博文(我不会找到不论什么我不知道的)。可是更令人火大的是我居然花了数小时调代码并产生这个错误。
Basically if you are going to build a general polygon set by providing a pre-built arrangement, there are two things you must do:
- Remove redundant edges - the GPS code assumes that the arrangement doesn't have needless edges (which will screw up traversal). Fortunately, the GPS code has a utility to do this, which I just call.
- Then you have to ensure that the direction of the underlying curves along the various edges are consistent - that is, for a given counter-clockwise boundary, every underlying curve goes either with or against the edge.
(After redundant edge removal, the arrangement will contain no antennas, so it will always be possible to get consistency on both sides of a CCB.)
基本上,假设你要从一个预先构建的arrangement中拿出通用多边形集合。有两件事必须做:
With this, polygon set operations work on arbitrary map input.
Why Did You Try This?
It also requires your arrangement to have the containment flag on the face data mixed in. Why go to the trouble? I did this for two reasons:
- Sometimes the polygonal set data I want to process came from an arrangement, and that arrangement is fairly huge. Having to construct the arrangement out of polygons the normal way requires geometry tests - topology data would be lost and rediscovered.
For big maps this is really performance-painful. - I have some operations that work on arrangements that are precursors to boolean sets. For example, the airport surface area data are fundamentally polygon sets (e.g. in the set is the airport surface area) but some of the constructive processing (e.g. simplifying
the contour) run on arrangements.
When an arrangement is turned into a polygon set, one of the results is a rather drastic map cleaning. Since the polygon set cares only about containment (what points are in, what are out), random features like roads tend to get blown away.
PM
怎样将Arranged_2压入General_Polygon_set_2中的更多相关文章
- 面试 16:栈的压入压出队列(剑指 Offer 第 22 题)
我们今天继续来看看周五留下的习题: 面试题:输入两个整数序列,第一个序列表示栈的压入顺序,请判断二个序列是否为该栈的弹出顺序.假设压入栈的所有数字均不相等.例如:压入序列为{1,2,3,4,5},那{ ...
- 剑指offer(21)栈的压入、弹出序列
题目描述 输入两个整数序列,第一个序列表示栈的压入顺序,请判断第二个序列是否为该栈的弹出顺序.假设压入栈的所有数字均不相等.例如序列1,2,3,4,5是某栈的压入顺序,序列4,5,3,2,1是该压栈序 ...
- 《剑指offer》-栈的压入、弹出序列
输入两个整数序列,第一个序列表示栈的压入顺序,请判断第二个序列是否为该栈的弹出顺序.假设压入栈的所有数字均不相等.例如序列1,2,3,4,5是某栈的压入顺序,序列4,5,3,2,1是该压栈序列对应的一 ...
- 剑指offer-第四章解决面试题的思路(栈的压入和弹出序列)
题目:输入两个整数序列,第一个序列表示栈的压入序列,请判断第二个序列是否为弹出序列. 思路:定义两个指针sPush和sPop分别指向两个整数序列的开头,借助一个辅助的栈,将第一个序列的数据依次压入栈中 ...
- 【剑指Offer】21、栈的压入、弹出序列
题目描述: 输入两个整数序列,第一个序列表示栈的压入顺序,请判断第二个序列是否可能为该栈的弹出顺序.假设压入栈的所有数字均不相等.例如序列1,2,3,4,5是某栈的压入顺序,序列4,5,3,2 ...
- 剑指Offer-21.栈的压入、弹出序列(C++/Java)
题目: 输入两个整数序列,第一个序列表示栈的压入顺序,请判断第二个序列是否可能为该栈的弹出顺序.假设压入栈的所有数字均不相等.例如序列1,2,3,4,5是某栈的压入顺序,序列4,5,3,2,1是该压栈 ...
- 剑指offer31----栈的压入、弹出序列
题目:输入两个整数序列,第一个序列表示栈的压入顺序,请判断第二个序列是否为该栈的弹出顺序.假设压入栈的所有数字均不相等.例如序列1,2,3,4,5是某栈的压入顺序,序列4,5,3,2,1是该压栈序列对 ...
- 剑指Offer面试题:20.栈的压入、弹出序列
一.题目:栈的压入.弹出序列 题目:输入两个整数序列,第一个序列表示栈的压入顺序,请判断第二个序列是否为该栈的弹出顺序.假设压入栈的所有数字均不相等.例如序列1.2.3.4.5是某栈的压栈序列,序列4 ...
- 剑指Offer:面试题22——栈的压入,弹出序列(java实现)
题目描述: 输入两个整数序列,第一个序列表示栈的压入顺序,请判断第二个序列是否为该栈的弹出顺序.假设压入栈的所有数字均不相等.例如序列1,2,3,4,5是某栈的压入顺序,序列4,5,3,2,1是该压栈 ...
随机推荐
- 华为/中兴 3G 语音的调试
1 microcom -s 9600 /dev/ttyUSB2(/dev/ttyUSB2不能错) 2 AT(看是否有OK输出) 3 AT+CREG?(0,1代表GSM网络注册成功) 4 AT+CSQ? ...
- QQ会员活动运营平台架构设计实践——高效自动化运营
QQ会员活动运营平台(AMS),是QQ会员增值运营业务的重要载体之一,承担海量活动运营的Web系统.在过去四年的时间里,AMS日请求量从200-500万的阶段,一直增长到日请求3-5亿,最高CGI日请 ...
- python 人脸识别
"""Performs face alignment and calculates L2 distance between the embeddings of image ...
- dlib python 人脸检测与关键点标记
http://blog.csdn.net/sunmc1204953974/article/details/49976045 人脸检测 #coding=utf-8 # -*- coding: utf-8 ...
- 学习:在Eclipse中用TODO标签管理任务(Task)。
1.Windows->Perferences->Java->Compile->Task Tags,我们就可以自定义任务标签,Eclipse中可以支持HIgh,Normal,Lo ...
- JQuery获取和设置select下拉框的值
获取Select : 获取select 选中的 text : $("#sid").find("option:selected").text(); 获取selec ...
- es6 javascript的class的静态方法、属性和实例属性
http://blog.csdn.net/qq_30100043/article/details/53542966
- string类(三、string.format格式字符串)
参考连接: http://www.cnblogs.com/luluping/archive/2009/04/30/1446665.html http://blog.csdn.net/samsone/a ...
- 编程之美 set 7 求数组中的最长递增子序列
解法 1. 假设在目标数组 array[] 的前 i 个元素中, 最长递增子序列的长度为 LIS[i] 那么状态转移方程为 LIS[i] = max(1, LIS[k]+1) array[i+1] & ...
- linux命令之rpm
1.查询一个包是否被安装的命令rpm -q < rpm package name> 2.列出所有被安装的rpm package 命令rpm -qa