A. Vasya and Football

题目连接:

http://codeforces.com/contest/493/problem/A

Description

Vasya has started watching football games. He has learned that for some fouls the players receive yellow cards, and for some fouls they receive red cards. A player who receives the second yellow card automatically receives a red card.

Vasya is watching a recorded football match now and makes notes of all the fouls that he would give a card for. Help Vasya determine all the moments in time when players would be given red cards if Vasya were the judge. For each player, Vasya wants to know only the first moment of time when he would receive a red card from Vasya.

Input

The first line contains the name of the team playing at home. The second line contains the name of the team playing away. Both lines are not empty. The lengths of both lines do not exceed 20. Each line contains only of large English letters. The names of the teams are distinct.

Next follows number n (1 ≤ n ≤ 90) — the number of fouls.

Each of the following n lines contains information about a foul in the following form:

first goes number t (1 ≤ t ≤ 90) — the minute when the foul occurs;
then goes letter "h" or letter "a" — if the letter is "h", then the card was given to a home team player, otherwise the card was given to an away team player;
then goes the player's number m (1 ≤ m ≤ 99);
then goes letter "y" or letter "r" — if the letter is "y", that means that the yellow card was given, otherwise the red card was given.

The players from different teams can have the same number. The players within one team have distinct numbers. The fouls go chronologically, no two fouls happened at the same minute.

Output

For each event when a player received his first red card in a chronological order print a string containing the following information:

The name of the team to which the player belongs;
the player's number in his team;
the minute when he received the card.

If no player received a card, then you do not need to print anything.

It is possible case that the program will not print anything to the output (if there were no red cards).

Sample Input

MC

CSKA

9

28 a 3 y

62 h 25 y

66 h 42 y

70 h 25 y

77 a 4 y

79 a 25 y

82 h 42 r

89 h 16 y

90 a 13 r

Sample Output

MC 25 70

MC 42 82

CSKA 13 90

Hint

题意

有两个球队在打比赛,然后现在给你每个球队的惩罚情况,让你输出拿红牌的情况。

题解:

模拟题

代码

#include<bits/stdc++.h>
using namespace std; int H[2][105];
vector<string> ans1;
vector<int> ans2,ans3;
int vis[2][105];
int main()
{
string s1,s2;
cin>>s1>>s2;
int n;
scanf("%d",&n);
for(int i=0;i<n;i++)
{
int a,b;
string a1,b1;
cin>>a>>a1>>b>>b1;
int id;
if(a1=="a")id=0;
else id=1;
if(b1=="y")
{
H[id][b]++;
if(H[id][b]==2&&!vis[id][b])
{
if(id==0)ans1.push_back(s2);
else ans1.push_back(s1);
ans2.push_back(b);
ans3.push_back(a);
vis[id][b]=1;
}
}
else
{
H[id][b]=2;
if(H[id][b]==2&&!vis[id][b])
{
if(id==0)ans1.push_back(s2);
else ans1.push_back(s1);
ans2.push_back(b);
ans3.push_back(a);
vis[id][b]=1;
}
}
}
for(int i=0;i<ans1.size();i++)
cout<<ans1[i]<<" "<<ans2[i]<<" "<<ans3[i]<<endl;
}

Codeforces Round #281 (Div. 2) A. Vasya and Football 模拟的更多相关文章

  1. Codeforces Round #281 (Div. 2) A. Vasya and Football(模拟)

    简单题,却犯了两个错误导致WA了多次. 第一是程序容错性不好,没有考虑到输入数据中可能给实际已经罚下场的人再来牌,这种情况在system测试数据里是有的... 二是chronologically这个词 ...

  2. Codeforces Round #281 (Div. 2) A. Vasya and Football 暴力水题

    A. Vasya and Football time limit per test 2 seconds memory limit per test 256 megabytes input standa ...

  3. Codeforces Round #281 (Div. 2) A. Vasya and Football 暴力

    A. Vasya and Football   Vasya has started watching football games. He has learned that for some foul ...

  4. Codeforces Round #281 (Div. 2) B. Vasya and Wrestling 水题

    B. Vasya and Wrestling 题目连接: http://codeforces.com/contest/493/problem/B Description Vasya has becom ...

  5. Codeforces Round #281 (Div. 2) D. Vasya and Chess 水

    D. Vasya and Chess time limit per test 2 seconds memory limit per test 256 megabytes input standard ...

  6. Codeforces Round #281 (Div. 2) C. Vasya and Basketball 二分

    C. Vasya and Basketball time limit per test 2 seconds memory limit per test 256 megabytes input stan ...

  7. Codeforces Round #281 (Div. 2) D. Vasya and Chess 镜面对称 博弈论

    D. Vasya and Chess time limit per test 2 seconds memory limit per test 256 megabytes input standard ...

  8. Codeforces Round #281 (Div. 2) C. Vasya and Basketball 暴力水题

    C. Vasya and Basketball time limit per test 2 seconds memory limit per test 256 megabytes input stan ...

  9. Codeforces Round #281 (Div. 2) D. Vasya and Chess 博弈

    D. Vasya and Chess   Vasya decided to learn to play chess. Classic chess doesn't seem interesting to ...

  10. Codeforces Round #281 (Div. 2) C. Vasya and Basketball 排序

    C. Vasya and Basketball   Vasya follows a basketball game and marks the distances from which each te ...

随机推荐

  1. bzoj千题计划238:bzoj3668: [Noi2014]起床困难综合症

    http://www.lydsy.com/JudgeOnline/problem.php?id=3668 这..一位一位的来就好了呀 #include<cstdio> #include&l ...

  2. Java获取时间,将当前时间减一年,减一天,减一个月

    在Java中操作时间的时候,需要计算某段时间开始到结束的区间日期,常用的时间工具 Date date = new Date();//获取当前时间 Calendar calendar = Calenda ...

  3. Docker CE的安装 与镜像加速

    Docker CE 的安装与镜像加速 Docker CE是docker的开源版本 CENTOS 安装Docker CE 系统要求: 操作系统需要使用centos7() centos-extras库 必 ...

  4. HDU 1431 素数回文 离线打表

    题目描述:给定一个区间,将这个区间里所有既是素数又是回文数的数输出来. 题目分析:这题的这个数据范围比较大,达到了10^8级别,而且输入的数据有多组,又因为判断一个数是否是回文数貌似只有暴力判断,时间 ...

  5. MongoDB 之 "$" 的奇妙用法 MongoDB - 5

    在MongoDB中有一个非常神奇的符号 "$" "$"  在 update 中 加上关键字 就 变成了 修改器 其实 "$" 字符 独立出现 ...

  6. js 判断日期大小、是否在时间范围内等处理

    var beginval="2015-09-01";//这个时间可以是日期控件选择的,也可以是其他的任何日期时间 var endval="2015-09-01" ...

  7. git与代码托管工具

    1.git初识 git是一个版本管理工具,用来管理项目的不同的版本,记录下不同的提交记录,git还可以构建不同的分支,用来给不同的人来推送使用. 推荐的git教程:https://www.cnblog ...

  8. 「Android 开发」入门笔记

    「Android 开发」入门笔记(界面编程篇) ------每日摘要------ DAY-1: 学习笔记: Android应用结构分析 界面编程与视图(View)组件 布局管理器 问题整理: Andr ...

  9. linux服务器账号密码正确无法登录

    登录服务器时,发现密码错误,输入后还是错误不能登录 最后发现登录日志中有pam_tally2(sshd:auth): user root (0) tally 53, deny 6 less /var/ ...

  10. Ansible Tower系列 二(安装 Tower)【转】

    文档:http://docs.ansible.com/ansible-tower/ 安装前检查 python版本为2.6 保持网络畅通 内存预留充足 安装用户为root 软件下载 下载地址:http: ...