题目链接:https://vjudge.net/contest/242578#problem/B

Dasha decided to bake a big and tasty layer cake. In order to do that she went shopping and bought n rectangular cake layers. The length and the width of the i-th cake layer were ai and bi respectively, while the height of each cake layer was equal to one.

From a cooking book Dasha learned that a cake must have a form of a rectangular parallelepiped constructed from cake layers of the same sizes.

Dasha decided to bake the biggest possible cake from the bought cake layers (possibly, using only some of them). It means that she wants the volume of the cake to be as big as possible. To reach this goal, Dasha can cut rectangular pieces out of the bought cake layers. She always cuts cake layers in such a way that cutting lines are parallel to the edges of that cake layer. Dasha isn't very good at geometry, so after cutting out a piece from the original cake layer, she throws away the remaining part of it. Also she can rotate a cake layer in the horizontal plane (swap its width and length).

Dasha wants her cake to be constructed as a stack of cake layers of the same sizes. Each layer of the resulting cake should be made out of only one cake layer (the original one or cut out from the original cake layer).

Help Dasha to calculate the maximum possible volume of the cake she can bake using given cake layers.

Input

The first line contains an integer n (1 ≤ n ≤ 4000) — the number of cake layers that Dasha can use.

Each of the following n lines contains two integer numbers ai and bi (1 ≤ ai, bi ≤ 106) — the length and the width of i-th cake layer respectively.

Output

The first line of the output should contain the maximum volume of cake that can be baked using given layers.

The second line of the output should contain the length and the width of the resulting cake. If there are many solutions with maximum possible volume, print any of them.

Examples

Input
5
5 12
1 1
4 6
6 4
4 6
Output
96
6 4
Input
2
100001 900000
900001 100000
Output
180000000000
900000 100000

Note

In the first example Dasha doesn't use the second cake layer. She cuts 4 × 6 rectangle from the first cake layer and she uses other cake layers as is.

In the second example Dasha cuts off slightly from the both cake layers.

题目大意:输入n,代表蛋糕有n层,接下来n行代表每层蛋糕的长度宽度,每层蛋糕的高度都是1 ,长宽可以交换位置,问你长宽取值为多少时,切得的蛋糕体积最大

个人思路:由题可知,长宽的取值一定在已有的长宽中得到,这题其实就是暴力,枚举每一个长和每一个宽,取最大的那个就是答案了

看代码

#include<iostream>
#include<cstdio>
#include<cstring>
#include<stdio.h>
#include<string.h>
#include<cmath>
#include<math.h>
#include<algorithm>
#include<set>
#include<queue>
#include<map>
typedef long long ll;
using namespace std;
const ll mod=1e9+;
const int maxn=4e3+;
const int maxk=+;
const int maxx=1e4+;
const ll maxe=+;
#define INF 0x3f3f3f3f3f3f
struct cake
{
int w,l;
}a[maxn];
bool cmp(const cake a,const cake b)
{
return a.w<b.w;
}
int main()
{
ll n,ans=,answ,ansl;
int c[maxn];
cin>>n;
for(int i=;i<n;i++)
{
cin>>a[i].w>>a[i].l;
if(a[i].w>a[i].l)
swap(a[i].w,a[i].l);
}
sort(a,a+n,cmp);
for(int i=;i<n;i++)
{
int sum=;
for(int j=;j<n;j++)
{
if(a[j].l>=a[i].l)
{
c[sum++]=a[j].w;
}
}
for(int j=;j<sum;j++)
{
ll res;
res=(ll)a[i].l*c[j]*(sum-j);
if(res>ans)
{
ans=res;
answ=c[j];
ansl=a[i].l;
}
}
}
cout<<ans<<endl;
cout<<answ<<" "<<ansl<<endl;
return ;
}

CodeForces - 589B的更多相关文章

  1. CodeForces - 589B(暴力)

    题目链接:http://codeforces.com/problemset/problem/589/B 题目大意:告诉你n 个矩形,知道矩形的长度和宽度(长和宽可以互换),每个矩形的长度可以剪掉一部分 ...

  2. CodeForces 589B Layer Cake (暴力)

    题意:给定 n 个矩形是a*b的,问你把每一块都分成一样的,然后全放一块,高度都是1,体积最大是多少. 析:这个题,当时并没有完全读懂题意,而且也不怎么会做,没想到就是一个暴力,先排序,先从大的开始选 ...

  3. CodeForces - 589B(暴力+排序)

    Dasha decided to bake a big and tasty layer cake. In order to do that she went shopping and bought n ...

  4. python爬虫学习(5) —— 扒一下codeforces题面

    上一次我们拿学校的URP做了个小小的demo.... 其实我们还可以把每个学生的证件照爬下来做成一个证件照校花校草评比 另外也可以写一个物理实验自动选课... 但是出于多种原因,,还是绕开这些敏感话题 ...

  5. 【Codeforces 738D】Sea Battle(贪心)

    http://codeforces.com/contest/738/problem/D Galya is playing one-dimensional Sea Battle on a 1 × n g ...

  6. 【Codeforces 738C】Road to Cinema

    http://codeforces.com/contest/738/problem/C Vasya is currently at a car rental service, and he wants ...

  7. 【Codeforces 738A】Interview with Oleg

    http://codeforces.com/contest/738/problem/A Polycarp has interviewed Oleg and has written the interv ...

  8. CodeForces - 662A Gambling Nim

    http://codeforces.com/problemset/problem/662/A 题目大意: 给定n(n <= 500000)张卡片,每张卡片的两个面都写有数字,每个面都有0.5的概 ...

  9. CodeForces - 274B Zero Tree

    http://codeforces.com/problemset/problem/274/B 题目大意: 给定你一颗树,每个点上有权值. 现在你每次取出这颗树的一颗子树(即点集和边集均是原图的子集的连 ...

随机推荐

  1. linux下mysql配置查询

    1.查看mysql的数据文件存放位置 show variables; 显示结果中的: datadir的值即是. 2.查看mysql是否支持表分区 SHOW VARIABLES LIKE '%parti ...

  2. 代码实现跟控制器跳转到storyBoard

  3. CentOS6和CentOS7服务开机启动

    CentOS 6和CentOS 7都可以定义开机启动哪些服务,但CentOS 6的命令是chkconfig,CentOS 7是systemctl. 本文将介绍两种命令的实现方式. 一.CentOS 6 ...

  4. TreeSet 和TreeMap 排序

    TreeSet 有两种排序方式 1. Java.lang.Comparble+compareTo new TreeSet() 用这种方法必须要求实体类实现Comparable接口,也就是说要求添加到T ...

  5. 可定制的分词库——Yaha(哑哈)分词

    可定制的分词库——Yaha(哑哈)分词在线测试地址:http://yaha.v-find.com/ 部署于GAE yahademo.appspot.comYaha分词主要特点是把分词过程分成了4个阶段 ...

  6. 关于overflow:hidden (转)

    关于overflow:hidden   (本文只针对hidden这个值的用处进行阐述) 关于overflow:hidden;很多人都知道他是溢出隐藏的一个属性,但是并不是很多人知道它的一些神奇的地方! ...

  7. Servlet包介绍

    ----------------siwuxie095                         首先到 Tomcat 的官网下载 Tomcat 的 API 帮助文档     Tomcat 官网: ...

  8. console (控制台)

    console 模块提供了一个简单的调试控制台,类似于 Web 浏览器提供的 JavaScript 控制台. 该模块导出了两个特定的组件: 一个 Console 类,包含 console.log()  ...

  9. Java Learning 000 搭建开发环境

    Java Learning 000 搭建开发环境 你需要两个软件: * JDK (Java Develop Kit :Java开发工具包) * eclipse (eclipse 集成开发环境软件) 安 ...

  10. 《精通Spring4.X企业应用开发实战》读后感第六章(引用Bean的属性值)