477. Total Hamming Distance
class Solution {
public:
int totalHammingDistance(vector<int>& nums) {
int res = ;
for (int i = ; i < ; i++) {
int ones = ;
for (int n : nums) {
if (n & ( << i)) {
ones++;
}
}
res += ones * (nums.size()-ones);
}
return res;
}
};
477. Total Hamming Distance的更多相关文章
- [LeetCode] 477. Total Hamming Distance 全部汉明距离
The Hamming distance between two integers is the number of positions at which the corresponding bits ...
- 477. Total Hamming Distance总的二进制距离
[抄题]: The Hamming distance between two integers is the number of positions at which the correspondin ...
- [LeetCode] 477. Total Hamming Distance(位操作)
传送门 Description The Hamming distance between two integers is the number of positions at which the co ...
- 【LeetCode】477. Total Hamming Distance 解题报告(Python & C++)
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 位运算 日期 题目地址:https://leetco ...
- 461. Hamming Distance and 477. Total Hamming Distance in Python
题目: The Hamming distance between two integers is the number of positions at which the corresponding ...
- 461. Hamming Distance + 477. Total Hamming Distance
▶ 与 Hamming 距离相关的两道题. ▶ 461. 求两个数 x 与 y 的哈夫曼距离. ● 代码,4 ms,对 x 和 y 使用异或,然后求值为 1 的位的个数. class Solutio ...
- LeetCode "477. Total Hamming Distance"
Fun one.. the punch line of this problem is quite common in Bit related problems on HackerRank - vis ...
- 477 Total Hamming Distance 汉明距离总和
两个整数的 汉明距离 指的是这两个数字的二进制数对应位不同的数量.计算一个数组中,任意两个数之间汉明距离的总和.示例:输入: 4, 14, 2输出: 6解释: 在二进制表示中,4表示为0100,14表 ...
- [LeetCode] Total Hamming Distance 全部汉明距离
The Hamming distance between two integers is the number of positions at which the corresponding bits ...
随机推荐
- Hibernate课程 初探一对多映射3-1 单向多对一简介
多对一的关系和关系数据库中的外键参照关系最匹配,即在己方的表中的一个外键参照另一个表中的主键! 通过在多方持有一方的引用来实现,需要在多的一方使用<many-to-one>来配置
- agc027D - Modulo Matrix(构造 黑白染色)
题意 题目链接 构造一个\(n * n\)的矩阵,要求任意相邻的两个数\(a,b\),使得\(max(a,b) \% min(a,b) \not = 0\) Sol 我的思路: 假设\(mod = 1 ...
- NFS笔记(二)NFS服务器配置实例
一.NFS服务器配置实例实验拓扑 二.实验要求及环境 2.1实验环境 NFS服务器 IP:192.168.8.5环境:[root@server7 ~]# uname -aLinux server7.c ...
- canvas 绘制八卦图
绘制要点: 1.getContext('2d'); -->绘图环境,2维空间 2.fillRect(x,y,w,h); -->矩形:实心(黑色背景) 3.strokeRect(x,y,w, ...
- April 9 2017 Week 15 Sunday
In the evening one may praise the day. 入夜方能赞美白昼. I think that could be understand in different ways, ...
- do..while(false)的用法总结
首先要注意: do..while(0) 代表do里面的东西至少被执行一次,在这里仅仅执行一次. 此种用法有三个用处: 代替{}代码块,实现局部作用域.在某些宏定义时非常有用: #define f(x) ...
- SAP S4CRM和C4C的技术比较
如果您对SAP S/4HANA for Customer Management(以下简称S4CRM)和SAP Cloud for Customer(以下简称C4C)不甚熟悉,那我建议您可以先浏览我之前 ...
- TeXstudio安装后提示no LaTeX distribution found on this system
应该是设置一下用户变量,而非系统变量,用TeXLive 2015和MikTeX都不好使,最后设置了用户变量好使了 S:\TeX\MiKTeX 2.9\miktex\bin\x64\ 也是醉醉的 不过等 ...
- hdu-3584 Cube---三维树状数组+区域更新单点查询
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=3584 题目大意: 给定一个N*N*N多维数据集A,其元素是0或是1.A[i,j,k]表示集合中第 i ...
- 高精度进位制转换,Poj(1220)
转自ACdream. #include <stdio.h> #include <string.h> #include <stdlib.h> #define MAXS ...