【遍历二叉树】06二叉树曲折(Z字形)层次遍历II【Binary Tree Zigzag Level Order Traversal】
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给定一个二叉树,返回他的Z字形层次遍历的节点的values。(提示,从左到右,然后下一层从右到左,然后再变化方向,就是这样一层一层的遍历)
例如:
给定一个二叉树 {3,9,20,#,#,15,7},
3
/ \
9 20
/ \
15 7
返回的层次遍历的结果是:
[
[3],
[20,9],
[15,7]
]
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
Given a binary tree, return the zigzag level order traversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between).
For example:
Given binary tree {3,9,20,#,#,15,7},
3
/ \
9 20
/ \
15 7
return its zigzag level order traversal as:
[
[3],
[20,9],
[15,7]
]
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
test.cpp:
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#include <iostream>
#include <cstdio> #include <stack> #include <vector> #include "BinaryTree.h" using namespace std; /** vector<int> temp; vector<TreeNode *> path; int count = 1; while(!path.empty()) path.erase(path.begin()); if(count == 0 && path.size()) lefttoright = true; // 树中结点含有分叉, ConnectTreeNodes(pNodeA1, pNodeA2, pNodeA3); PrintTree(pNodeA1); vector<vector<int> > ans = zigzagLevelOrder(pNodeA1); for (int i = 0; i < ans.size(); ++i) DestroyTree(pNodeA1); |
输出结果:
题目ac了,但是测试用例没有通过
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#ifndef _BINARY_TREE_H_
#define _BINARY_TREE_H_ struct TreeNode TreeNode *CreateBinaryTreeNode(int value); #endif /*_BINARY_TREE_H_*/ |
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#include <iostream>
#include <cstdio> #include "BinaryTree.h" using namespace std; /** //创建结点 return pNode; //连接结点 //打印节点内容以及左右子结点内容 if(pNode->left != NULL) if(pNode->right != NULL) printf("\n"); //前序遍历递归方法打印结点内容 if(pRoot != NULL) if(pRoot->right != NULL) void DestroyTree(TreeNode *pRoot) delete pRoot; DestroyTree(pLeft); |
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