PTA(Advanced Level)1065.A+B and C

Given three integers A, B and C in [−263,263], you are supposed to tell whether A+B>C.

Input Specification:

The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line Case #X: true if A+B>C, or Case #X: false otherwise, where X is the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false

思路

• 看a,b,c的范围就知道就算使用long long也是要溢出的，这里我尝试取巧地使用了long double，double在我的codeblock上是8字节，而long double是12字节，不知道OJ上的是怎么样的，试着用一下还过了…

代码

#include<bits/stdc++.h>
using namespace std;

int main()
{
	int n;
	long double  a,b,c;
	cin >> n;
	for(int i=1;i<=n;i++)
	{
		cin >> a >> b >> c;
		if(a + b >  c)
			cout << "Case #" << i <<": true" << endl;
		else
			cout << "Case #" << i <<": false" << endl;
	}
	return 0;
}

引用

https://pintia.cn/problem-sets/994805342720868352/problems/994805406352654336