树链剖分裸题。

。。

又要扩栈又要输入挂还卡格式。。。。真无语

Tree

Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)

Total Submission(s): 1538    Accepted Submission(s): 261

Problem Description
You are given a tree (an acyclic undirected connected graph) with N nodes. The tree nodes are numbered from 1 to N



There are N - 1 edges numbered from 1 to N - 1.



Each node has a value and each edge has a value. The initial value is 0.



There are two kind of operation as follows:



● ADD1 u v k: for nodes on the path from u to v, the value of these nodes increase by k.



● ADD2 u v k: for edges on the path from u to v, the value of these edges increase by k.



After finished M operation on the tree, please output the value of each node and edge.
 
Input
The first line of the input is T (1 ≤ T ≤ 20), which stands for the number of test cases you need to solve.



The first line of each case contains two integers N ,M (1 ≤ N, M ≤105),denoting the number of nodes and operations, respectively.



The next N - 1 lines, each lines contains two integers u, v(1 ≤ u, v ≤ N ), denote there is an edge between u,v and its initial value is 0.



For the next M line, contain instructions “ADD1 u v k” or “ADD2 u v k”. (1 ≤ u, v ≤ N, -105 ≤ k ≤ 105)
 
Output
For each test case, print a line “Case #t:”(without quotes, t means the index of the test case) at the beginning.



The second line contains N integer which means the value of each node.



The third line contains N - 1 integer which means the value of each edge according to the input order.
 
Sample Input
2
4 2
1 2
2 3
2 4
ADD1 1 4 1
ADD2 3 4 2
4 2
1 2
2 3
1 4
ADD1 1 4 5
ADD2 3 2 4
 
Sample Output
Case #1:
1 1 0 1
0 2 2
Case #2:
5 0 0 5
0 4 0
 
Source
 

posted on
2017-05-05 10:11 
lxjshuju 
阅读(...) 
评论(...) 
编辑 
收藏

HDOJ 5044 Tree的更多相关文章

  1. HDU 5044 Tree(树链剖分)

    HDU 5044 Tree field=problem&key=2014+ACM%2FICPC+Asia+Regional+Shanghai+Online&source=1&s ...

  2. hdoj 2682 Tree

    Tree Time Limit: 6000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submis ...

  3. HDOJ 3516 Tree Construction

    四边形优化DP Tree Construction Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/32768 K (Jav ...

  4. HDU 5044 Tree 树链剖分+区间标记

    Tree Problem Description You are given a tree (an acyclic undirected connected graph) with N nodes. ...

  5. HDOJ 2682 Tree(最小生成树prim算法)

    Tree Time Limit: 6000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submi ...

  6. 树形DP+DFS序+树状数组 HDOJ 5293 Tree chain problem(树链问题)

    题目链接 题意: 有n个点的一棵树.其中树上有m条已知的链,每条链有一个权值.从中选出任意个不相交的链使得链的权值和最大. 思路: 树形DP.设dp[i]表示i的子树下的最优权值和,sum[i]表示不 ...

  7. HDU 5044 Tree --树链剖分

    题意:给一棵树,两种操作: ADD1: 给u-v路径上所有点加上值k, ADD2:给u-v路径上所有边加上k,初始值都为0,问最后每个点和每条边的值,输出. 解法:树链剖分可做,剖出来如果直接用线段树 ...

  8. HDU 5044 TREE

    题意:一棵树上两种操作,操作1,改变u到v的每一点的值增加k,操作2,改变u到v每一条边值增加k.最后结束时问,每一点和每一条边的值. 初始时,点和边的值都为0. 分析: 很显然要用树链剖分,将点和边 ...

  9. HDOJ 3516 Tree Construction 四边形优化dp

    原题链接:http://acm.hdu.edu.cn/showproblem.php?pid=3516 题意: 大概就是给你个下凸包的左侧,然后让你用平行于坐标轴的线段构造一棵树,并且这棵树的总曼哈顿 ...

随机推荐

  1. 倍福TwinCAT(贝福Beckhoff)常见问题(FAQ)-如何配置虚拟轴 TC2

    右击NC- Configuration,然后Append Task,然后右击Axis,Append Axis   轴的类型可以分为:Continuous Axis,默认的类型,NC可以连续闭环控制该轴 ...

  2. python 页面信息抓取

    1. 特点 在python 解析html这篇文章中已经做了初步的介绍,接下来再坐进一步的说明.python抓取页面信息有下面两个特点: 依赖于HTML的架构. 微小的变化可能会导致抓取失败,这取决于你 ...

  3. loadrunner两个函数:取参数长度和时间戳函数

    出自中国IT实验室2014-05-23 00:01 1.web_save_param_length 函数 函数原型:int web_save_param_length( const char *Par ...

  4. 《让LoadRunner走下神坛》

    这几天碰到这么几件事情,觉得挺有意思的:1.        有个朋友问了我一个问题:LoadRunner的缺点在哪?然后我反问她:LoadRunner的优点在哪?她一时语塞,后来说:感觉都是优点没有什 ...

  5. where 泛型类型参数及约束

    private void InsertData<TRowMetadata, TFieldMetadata, TCellMetadata>(IMetadataReader<TRowMe ...

  6. internet与Internet的区别

    internet是用一个共同的协议族把多个网络连接在一起.而Internet指的是世界范围内通过TCP/IP互相通信的所有主机集合(超过1 0 0万台).Internet是一个internet,但in ...

  7. VS代码注释插件GhostDoc

    http://community.submain.com/blogs/tutorials/archive/2013/03/28/how-to-access-ghostdoc-pro-features. ...

  8. Atitit..状态机与词法分析  通用分词器 分词引擎的设计与实现 attilax总结

    Atitit..状态机与词法分析  通用分词器 分词引擎的设计与实现 attilax总结 1. 状态机 理论参考1 2. 词法分析理论1 3. 词法分析实例2 4. ---code fsm 状态机通用 ...

  9. ModelSim 使用笔记1

    ModelSim 使用笔记1   ModelSim提供了简单仿真方式,还有一种要建立project,目前这种方式暂时够我用了. 总结了以下,做了一个简单的<modelsim quick star ...

  10. Xilinx下载方式(具体可以参考配置MCS文件时右下角help调出的doc)

    1.两者都属高速并行配置模式.SelectMAP是早期的FPGA两类配置模式之一,是相对于串行(Serial)配置而言的,与主串(Master Serial)和从串(Slave Serial)模式对应 ...