Suppose you have a random list of people standing in a queue. Each person is described by a pair of integers (h, k), where h is the height of the person and k is the number of people in front of this person who have a height greater than or equal to h. Write an algorithm to reconstruct the queue.

Note:
The number of people is less than 1,100.

Example:

Input:
[[7,0], [4,4], [7,1], [5,0], [6,1], [5,2]]

Output:
[[5,0], [7,0], [5,2], [6,1], [4,4], [7,1]]

一开始我的思路是根据k值从小到大排,如果k值相同则h值从大到小排。然后再遍历排序过后的数组,进行按值插入。看过别人的分析后,更好的方式是先根据h值从大到小排,如果h值相同则k值从小到大排。然后将数组按顺序插入到ArrayList中,经过第二种排序方式的数组,当前即将被插入的数组的k值就是它在list中应有的位置。这是因为数组先按照h值从大到小排序过,因此已经在list中的数组的h值都是大于或者等于当前数组的h值的。代码如下:

Queue Reconstruction by Height的更多相关文章

  1. sort学习 - LeetCode #406 Queue Reconstruction by Height

    用python实现多级排序,可以像C语言那样写个my_cmp,然后在sort的时候赋给参数cmp即可 但实际上,python处理cmp 是很慢的,因为每次比较都会调用my_cmp:而使用key和rev ...

  2. LN : leetcode 406 Queue Reconstruction by Height

    lc 406 Queue Reconstruction by Height 406 Queue Reconstruction by Height Suppose you have a random l ...

  3. LeetCode 406. 根据身高重建队列(Queue Reconstruction by Height) 46

    406. 根据身高重建队列 406. Queue Reconstruction by Height 题目描述 假设有打乱顺序的一群人站成一个队列.每个人由一个整数对 (h, k) 表示,其中 h 是这 ...

  4. LC 406. Queue Reconstruction by Height

    Suppose you have a random list of people standing in a queue. Each person is described by a pair of ...

  5. [LeetCode] Queue Reconstruction by Height 根据高度重建队列

    Suppose you have a random list of people standing in a queue. Each person is described by a pair of ...

  6. 406. Queue Reconstruction by Height

    一开始backtrack,设计了很多剪枝情况,还是TLE了 ..后来用PQ做的. 其实上面DFS做到一半的时候意识到应该用PQ做,但是不确定会不会TLE,就继续了,然后果然TLE了.. PQ的做法和剪 ...

  7. LeetCode_406. Queue Reconstruction by Height解题思路

    题目如下: Suppose you have a random list of people standing in a queue. Each person is described by a pa ...

  8. [Swift]LeetCode406. 根据身高重建队列 | Queue Reconstruction by Height

    Suppose you have a random list of people standing in a queue. Each person is described by a pair of ...

  9. LeetCode406. Queue Reconstruction by Height Add to List

    Description Suppose you have a random list of people standing in a queue. Each person is described b ...

随机推荐

  1. 移动APP的开发迭代离不开测试,你搞清楚其中的关键点了吗?

    App测试的一个要求是一个beta测试环境.为此,操作系统制造商要么提供他们自己的测试环境,比如:Testflight (iOS),要么可以使用任一商用工具,如:HockeyApp (Android) ...

  2. Android进程绝杀技--forceStop

    一.概述 1.1 引言 话说Android开源系统拥有着App不计其数,百家争鸣,都想在这"大争之世"寻得系统存活的一席之地.然则系统资源有限,如若都割据为王,再强劲的CPU也会忙 ...

  3. java.lang.Comparable<T> 接口

    package java.lang; import java.util.*; public interface Comparable<T> { public int compareTo(T ...

  4. ionic overflow:auto失效

    事情的起因是 同事上传一个很宽的table文件,因为手机屏幕宽度有限,因此要求 用户可以水平滚动页面,这样table的内容通过滚动就可以实现啦. 当时感觉很简单 给table外面的容器加个overfl ...

  5. text-transform属性

    text-transform -- 定义文本的大小写状态,此属性对中文无意义 取值:capitalize | uppercase | lowercase | none | inherit capita ...

  6. TypeError: coercing to Unicode: need string or buffer, ChatRoom found

    在用django框架中遇到一个错误,是模型编写中出的错误 TypeError: coercing to Unicode: need string or buffer, ChatRoom found 解 ...

  7. selenium ide脚本回放出现element not found

    原因: 点击按钮,没有设置时间延迟,而页面加载,需要时间:当页面元素未加载完全,执行点击事件,就会报错:element... not found. 解决方案: 在点击事件前添加新的COMMAND.设置 ...

  8. C++ 消息中间件(MQ4CPP)

    MQ4CPP支持: MultiThreading Sockets Cluster Encription Compression Service lookup Message routing 看到MQ4 ...

  9. Bootstrap网格系统

    一.网格系统 响应式网格系统随着屏幕或视口(viewport)尺寸的增加,系统会自动分为最多12列. 二.基本结构 <div class="container"> &l ...

  10. SQL经典面试题及答案

    1.一道SQL语句面试题,关于group by表内容:2005-05-09 胜2005-05-09 胜2005-05-09 负2005-05-09 负2005-05-10 胜2005-05-10 负2 ...