UVA-11292Dragon of Loowater
/*
The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem.
The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predators, the geese population was out of control. The people of Loowater mostly kept clear of the geese. Occasionally, a goose would attack one of the people, and perhaps bite off a finger or two, but in general, the people tolerated the geese as a minor nuisance. One day, a freak mutation occurred, and one of the geese spawned a multi-headed fire-breathing dragon. When the dragon grew up, he threatened to burn the Kingdom of Loowater to a crisp. Loowater had a major problem. The king was alarmed, and called on his knights to slay the dragon and save the kingdom. The knights explained: "To slay the dragon, we must chop off all its heads. Each knight can chop off one of the dragon's heads. The heads of the dragon are of different sizes. In order to chop off a head, a knight must be at least as tall as the diameter of the head. The knights' union demands that for chopping off a head, a knight must be paid a wage equal to one gold coin for each centimetre of the knight's height." Would there be enough knights to defeat the dragon? The king called on his advisors to help him decide how many and which knights to hire. After having lost a lot of money building Mir Park, the king wanted to minimize the expense of slaying the dragon. As one of the advisors, your job was to help the king. You took it very seriously: if you failed, you and the whole kingdom would be burnt to a crisp! Input Specification: The input contains several test cases. The first line of each test case contains two integers between 1 and 20000 inclusive, indicating the number n of heads that the dragon has, and the number m of knights in the kingdom. The next n lines each contain an integer, and give the diameters of the dragon's heads, in centimetres. The following m lines each contain an integer, and specify the heights of the knights of Loowater, also in centimetres. The last test case is followed by a line containing: 0 0
Output Specification: For each test case, output a line containing the minimum number of gold coins that the king needs to pay to slay the dragon. If it is not possible for the knights of Loowater to slay the dragon, output the line: Loowater is doomed!
Sample Input: 2 3
5
4
7
8
4
2 1
5
5
10
0 0
Output for Sample Input: 11
Loowater is doomed!
Ondřej Lhoták
题意:
恶龙有n个头,每个头直径x,国王可以雇佣m个骑士,每个骑士能力为y,
能砍半径y的头,雇佣金为y,不能重复雇佣,问最少能花费多少金币
*/
#include <iostream>
#include<algorithm>
#include<queue>
#include<stack>
#include<cmath>
#include<string.h>
#include<stdio.h>
#include<stdlib.h>
using namespace std;
#define maxn 26000
int a[maxn],b[maxn];
int main()
{
int x,y,i,j,sum;
while(~scanf("%d%d",&x,&y),x||y)
{
for(i=; i<x; i++)
scanf("%d",&a[i]);
for(i=; i<y; i++)
scanf("%d",&b[i]);
sort(a,a+x);
sort(b,b+y);
if(x>y)
{
printf("Loowater is doomed!\n");
continue;
}
sum=;
for(i=,j=;i<x&&j<y;j++)
{
if(a[i]<=b[j])
{
sum+=b[j];
i++;
}
}
if(i<x&&j==y)
printf("Loowater is doomed!\n");
else
printf("%d\n",sum);
}
return ;
}
UVA-11292Dragon of Loowater的更多相关文章
- UVA 11292-Dragon of Loowater (贪心)
Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem. The shor ...
- UVA 11292 - The Dragon of Loowater (water)
http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=24&page=sh ...
- UVA它11292 - Dragon of Loowater
Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...
- UVA 11292 Dragon of Loowater(简单贪心)
Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...
- 贪心/思维题 UVA 11292 The Dragon of Loowater
题目传送门 /* 题意:n个头,m个士兵,问能否砍掉n个头 贪心/思维题:两个数组升序排序,用最弱的士兵砍掉当前的头 */ #include <cstdio> #include <c ...
- cogs 1405. 中古世界的恶龙[The Drangon of Loowater,UVa 11292]
1405. 中古世界的恶龙[The Drangon of Loowater,UVa 11292] ★ 输入文件:DragonUVa.in 输出文件:DragonUVa.out 简单对比时间 ...
- UVa 11292 Dragon of Loowater
简单贪心 龙头的直径和人的佣金排序,价值小的人和直径小的配 #include<iostream> #include<cstdio> #include<cmath> ...
- [ACM_水题] UVA 11292 Dragon of Loowater [勇士斗恶龙 双数组排序 贪心]
Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem. The shor ...
- UVa 11292 The Dragon of Loowater 勇者斗恶龙
你的王国里有一条n个头的恶龙,你希望雇佣一些骑士把它杀死(也就是砍掉所有的头).村里有m个骑士可以雇佣,一个能力值为 x 的骑士可以砍掉恶龙一个直径不超过 x 的头,且需要支付 x 个金币.如何雇佣骑 ...
- uva 11292 Dragon of Loowater (勇者斗恶龙)
Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...
随机推荐
- vs 添加第三方库lib的两种方法
方法一1.代码: 方法二2.配置: 首先包含头文件 #include “../DuiLib/UIlib.h” 连接器->常规-->附加库目录.即是将lib所在的目录,千万要记得,还要写一处 ...
- Vue(2) : Vue for Gank.io
简介 最近学习Vue2.0,由于不懂前端知识,学习过程比较缓慢.文档学习过程如下: 通读vue官文 通读vue-router 2中文指南 学习axios 通读vuex官文 数据接口 再次感谢代码家的G ...
- 【剑指offer】找出数组中任意重复的数字(不修改数组),C++实现
原创博文,转载请注明出处! # 题目 在一个长度为n+1的数组里的所有数字都在1~n的范围内,所以数组中至少有一个数字是重复的.请找出数组中任意一个重复的数字,但不能修改输入的数组.例如,如果输入长度 ...
- SpringMVC和Freemarker整合,带自定义标签的使用方法
SpringMVC和Freemarker整合,带自定义标签的使用方法. [参考来源:http://www.360doc.com/content/14/1225/14/1007797_435663342 ...
- ResultSet.TYPE_SCROLL_SENSITIVE到底发生了什么?
转自:https://blog.csdn.net/axman/article/details/3984103 这个问题我在几年前说过,但今天再次从CSDN上看到有人问这个问题,可以看出,真正懂这个问题 ...
- 常用的SQL语句大全
一.基础 1.说明:创建数据库CREATE DATABASE database-name 2.说明:删除数据库drop database dbname3.说明:备份sql server--- 创建 备 ...
- 《DSP using MATLAB》示例Example7.5
代码: h = [-4, 1, -1, -2, 5, 6, 6, 5, -2, -1, 1, -4]; M = length(h); n = 0:M-1; [Hr, w, b, L] = Hr_Typ ...
- 接口测试基础——第6篇unittest模块(二)
通过上次的运行,大家应该已经发现了,就是我们写了三个用例,那么在测试报告中setUp和tearDown方法分别运行了三次.没错,这也就是说,每次运行用例之前都会运行setUp和tearDown方法.今 ...
- Sprint第一个冲刺(第十天)
一.Sprint介绍 更新工程部署文件:实现了云端登录:设计经营情况以及数据分析界面. 实验截图: 任务进度: 二.Sprint周期 看板: 燃尽图:
- WPF自定义控件之图形解锁控件 ScreenUnLock
ScreenUnLock 与智能手机上的图案解锁功能一样.通过绘制图形达到解锁或记忆图形的目的. 本人突发奇想,把手机上的图形解锁功能移植到WPF中.也应用到了公司的项目中. 在创建ScreenUnL ...