从反汇编看待C++ new

首先来看最简单的new操作

int main()
{
	int *temp = new int;
	delete temp;
}

反汇编结果:调用了operator new

00311C9E  push        4  
00311CA0  call        operator new (0311438h)  
00311CA5  add         esp,4  

进入operator new中查看

void* __CRTDECL operator new(size_t const size)
{
00315320  push        ebp  
00315321  mov         ebp,esp  
00315323  push        ecx  
    for (;;)
    {
       if (void* const block = malloc(size))
00315324  mov         eax,dword ptr [size]  
00315327  push        eax  
00315328  call        _malloc (03111B3h)  
0031532D  add         esp,4  
00315330  mov         dword ptr [ebp-4],eax  
00315333  cmp         dword ptr [ebp-4],0  
00315337  je          operator new+1Eh (031533Eh)  
            return block;
省略..................

发现其底层也调用了malloc函数