Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s = "Hello World",
return 5.

 class Solution {
public:
int lengthOfLastWord(const char *s) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
int len = strlen(s);
if(==len) return ; int last = len;
int first = ;
while(last> && s[last-]==' '){
last--;
}
while(first<last && s[first]==' '){
first++;
}
if(==last) return ; int i;
for(i=last-;i>=first;i--){
if(s[i]==' ') break;
}
return (last-i-);
}
};

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