The Seven Percent Solution
|
Problem Description
Uniform Resource Identifiers (or URIs) are strings like http://icpc.baylor.edu/icpc/, mailto:foo@bar.org, ftp://127.0.0.1/pub/linux, or even just readme.txt that are used to identify a resource, usually on the Internet or a local computer. Certain characters are reserved within URIs, and if a reserved character is part of an identifier then it must be percent-encoded by replacing it with a percent sign followed by two hexadecimal digits representing the ASCII code of the character. A table of seven reserved characters and their encodings is shown below. Your job is to write a program that can percent-encode a string of characters.
Character Encoding |
|
Input
The input consists of one or more strings, each 1–79 characters
long and on a line by itself, followed by a line containing only "#" that signals the end of the input. The character "#" is used only as an end-of-input marker and will not appear anywhere else in the input. A string may contain spaces, but not at the beginning or end of the string, and there will never be two or more consecutive spaces. |
|
Output
For each input string, replace every occurrence of a reserved
character in the table above by its percent-encoding, exactly as shown, and output the resulting string on a line by itself. Note that the percent-encoding for an asterisk is %2a (with a lowercase "a") rather than %2A (with an uppercase "A"). |
|
Sample Input
Happy Joy Joy! |
|
Sample Output
Happy%20Joy%20Joy%21 |
#include<stdio.h>
void main()
{
char a[1000];
int n;
while(1)
{
gets(a);
//getchar();
if(a[0]=='#')
return;
for(int j=0;a[j]!='\0';j++);
j++; n=j;
for(int i=0;a[i]!='\0';i++)
{
switch(a[i])
{
case ' ' :
for(;j>i;j--)
a[j+2]=a[j];
a[i]='%';
a[i+1]='2';
a[i+2]='0';
i=i+2;
j=n=n+2;
break;
case '!':
for(;j>i;j--)
a[j+2]=a[j];
a[i]='%';
a[i+1]='2';
a[i+2]='1';
i=i+2;
j=n=n+2;
break;
case '$':
for(;j>i;j--)
a[j+2]=a[j];
a[i]='%';
a[i+1]='2';
a[i+2]='4';
i=i+2;
j=n=n+2;
break;
case '%':
for(;j>i;j--)
a[j+2]=a[j];
a[i]='%';
a[i+1]='2';
a[i+2]='5';
i=i+2;
j=n=n+2;
break;
case '(':
for(;j>i;j--)
a[j+2]=a[j];
a[i]='%';
a[i+1]='2';
a[i+2]='8';
i=i+2;
j=n=n+2;
break;
case ')':
for(;j>i;j--)
a[j+2]=a[j];
a[i]='%';
a[i+1]='2';
a[i+2]='9';
i=i+2;
j=n=n+2;
break;
case '*':
for(;j>i;j--)
a[j+2]=a[j];
a[i]='%';
a[i+1]='2';
a[i+2]='a';
i=i+2;
j=n=n+2;
break;
}
}
printf("%s\n",a);
}
}
The Seven Percent Solution的更多相关文章
- HDUOJ-------2719The Seven Percent Solution
The Seven Percent Solution Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Ja ...
- zoj 2932 The Seven Percent Solution
The Seven Percent Solution Time Limit: 2 Seconds Memory Limit: 65536 KB Uniform Resource Identi ...
- POJ 3650:The Seven Percent Solution
The Seven Percent Solution Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 7684 Accep ...
- HDU 2719 The Seven Percent Solution
#include <cstdio> #include <cstring> int main() { ]; ]!='#') { ; while (i<strlen(s)) ...
- HDU 2719 The Seven Percent Solution (水题。。。)
题意:把字符串中的一些特殊符号用给定的字符串代替. 析:没的说. 代码如下: #include <iostream> #include <cstdio> #include &l ...
- HDU题解索引
HDU 1000 A + B Problem I/O HDU 1001 Sum Problem 数学 HDU 1002 A + B Problem II 高精度加法 HDU 1003 Maxsu ...
- Enterprise Solution 3.1 企业应用开发框架 .NET ERP/CRM/MIS 开发框架,C/S架构,SQL Server + ORM(LLBL Gen Pro) + Infragistics WinForms
行业:基于数据库的制造行业管理软件,包含ERP.MRP.CRM.MIS.MES等企业管理软件 数据库平台:SQL Server 2005或以上 系统架构:C/S 开发技术 序号 领域 技术 1 数据库 ...
- Enterprise Solution 开源项目资源汇总 Visual Studio Online 源代码托管 企业管理软件开发框架
Enterprise Solution 是一套管理软件开发框架,在这个框架基础上开发出一套企业资源计划系统Enterprise Edition. 现将Enterprise Solution开发过程中遇 ...
- Windows 10 部署Enterprise Solution 5.5
Windows 10正式版发布以后,新操作系统带来了许多的变化.现在新购买的电脑安装的系统应该是Windows 10.与当初用户不习惯Windows 7,购买新电脑后第一个想做的事情就是重装成XP,估 ...
随机推荐
- socket网络编程扫盲篇
socket 是“套接字”的意思,是计算机之间进行通信的一种约定,也可以认为是一种技术.通过 socket 这种约定,一台计算机可以接收其他计算机的数据,也可以向其他计算机发送数据. socket 的 ...
- 大数java(pow)
Problems involving the computation of exact values of very large magnitude and precision are common. ...
- target runtime apache v6.0 not defined解决
在加载别人的一个项目时,会报该错误,需要先在buildpath中remove v6的版本,再点击add library,选择server runtime,如果eclipse配置过Tomcat,可以选择 ...
- 手机端适配方案 媒体查询和flexbale
方法一 flexible 一.npm 包安装 lib-flexible 淘宝适配方案 px2rem px自动转rem npm install lib-flexible --save npm insta ...
- AngularJS 高级程序设计
1.5.4 安装Web服务器 原来的: connect.static("../angularjs"); 报错.可以修改为: var connect = require('conne ...
- UOJ 67 新年的毒瘤 - Tarjan
Description 给出一个无向图, 要求找出某个点$u$, 去掉$u$和$u$所连的边, 所剩下的节点构成一棵树. Solution 首先, 割点肯定是不可能满足条件的, 因为去掉割点后会构成若 ...
- C++变量存储类别和内存四区
变量存储类别 变量声明/定义的一般形式: 存储类别 数据类型 变量名 存储类别指的是数据在内存中存储的方法.存储方法分为静态存储和动态存储两大类.标准C语言为变量.常量和函数定义了4种存储类型:ext ...
- 在 Ubuntu 上使用微信客户端
原文地址: http://www.myzaker.com/article/5979115d1bc8e08c30000071/ 在这个快速信息交互时代,无论是工作还是生活,都需要频繁的网络社交,而在中国 ...
- 如果CocoaPods 导入的库需要修改代码
如果经常要修改第三方框架的话,可以将需要修改的第三方库fork一份到自己的github,在里面做完修改之后,将podfile修改为: platform :ios, '7.0' pod '要导入的库 ...
- 使用Apache CXF和Spring集成创建Web Service(zz)
使用Apache CXF和Spring集成创建Web Service 您的评价: 还行 收藏该经验 1.创建HelloWorld 接口类 查看源码 打印? 1 package ...