原题地址:https://oj.leetcode.com/problems/path-sum/

题意:

Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

For example:
Given the below binary tree and sum = 22,

              5
/ \
4 8
/ / \
11 13 4
/ \ \
7 2 1

return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.

解题思路:使用递归解决。

代码:

# Definition for a  binary tree node
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None class Solution:
# @param root, a tree node
# @param sum, an integer
# @return a boolean
def hasPathSum(self, root, sum):
if root == None:
return False
if root.left == None and root.right == None:
return root.val == sum
return self.hasPathSum(root.left, sum - root.val) or self.hasPathSum(root.right, sum - root.val)

[leetcode]Path Sum @ Python的更多相关文章

  1. LeetCode:Path Sum I II

    LeetCode:Path Sum Given a binary tree and a sum, determine if the tree has a root-to-leaf path such ...

  2. [leetcode]Binary Tree Maximum Path Sum @ Python

    原题地址:https://oj.leetcode.com/problems/binary-tree-maximum-path-sum/ 题意: Given a binary tree, find th ...

  3. [LeetCode] Path Sum III 二叉树的路径和之三

    You are given a binary tree in which each node contains an integer value. Find the number of paths t ...

  4. [LeetCode] Path Sum II 二叉树路径之和之二

    Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given su ...

  5. [LeetCode] Path Sum 二叉树的路径和

    Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all ...

  6. [LeetCode] Path Sum IV 二叉树的路径和之四

    If the depth of a tree is smaller than 5, then this tree can be represented by a list of three-digit ...

  7. LeetCode Path Sum IV

    原题链接在这里:https://leetcode.com/problems/path-sum-iv/description/ 题目: If the depth of a tree is smaller ...

  8. [leetcode]Path Sum II

    Path Sum II Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals ...

  9. LeetCode: Path Sum II 解题报告

    Path Sum II Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals ...

随机推荐

  1. HTTP协议-缓存

    HTTP 协议中,缓存更多关心的文档资源的再利用.其目的是减少数据传输,加快相应速度等等.而对于缓存采用的是什么方案,也就是存在内存中还是硬盘中之类的问题,就属于另外的内容了. 假设,我身在广东,但是 ...

  2. VA插件突然不能使用,彈出“the security key for....”

    昨天打開VS莫名其妙地彈出下面的錯誤框: "the security key for this program currently stored on your system does no ...

  3. Codeforces Round #370 (Div. 2) A. Memory and Crow 水题

    A. Memory and Crow 题目连接: http://codeforces.com/contest/712/problem/A Description There are n integer ...

  4. CentOS的epel源rpm最新下载地址获取技巧

    最近发现以前的的脚本上安装epel不起作用,最后发现是官方更新了,且每次更新都会把以前旧的删除. 鉴于上面这种情况,不建议安装rpm包,直接转投阿里云的镜像站点,下载文件替换,阿里云的好处是不改文件名 ...

  5. Android中使用隐藏API(大量图解)

    Android SDK的很多API是隐藏的,我无法直接使用.但是我们通过编译Android系统源码可以得到完整的API. 编译Android系统源码后可以在out\target\common\obj\ ...

  6. C#快速找出磁盘内的所有文件

    本文只针对NTFS格式化的磁盘文件快速检索,速度不是非常快,是让你震惊. 一般用文件遍历的方法检索一个50G的文件夹需要几十分钟甚至一个小时的时间,而用本方法只需几秒. using System; u ...

  7. Cloud Foundry中DEA启动应用实例时环境变量的使用

    在Cloud Foundry v2中,当应用用户须要启动应用的实例时.用户通过cf CLI向cloud controller发送请求,而cloud controller通过NATS向DEA转发启动请求 ...

  8. Word中如何从某一页重新开始页码

  9. Vue 插件写法

    都说Vue2简单,上手容易,但小马过河,自己试了才晓得,除了ES6语法和webpack的配置让你感到陌生,重要的是思路的变换,以前随便拿全局变量和修改dom的锤子不能用了,变换到关注数据本身.vue的 ...

  10. ASP.NET Web API实践系列11,如何设计出优秀的API

    本篇摘自:InfoQ的微信公众号 在设计API的时候考虑的问题包括:API所使用的传输协议.支持的消息格式.接口的控制.名称.关联.次序,等等.我们很难始终作出正确的决策,很可能是在多次犯错之后,并从 ...