Time Limit: 1000MS   Memory Limit: 262144KB   64bit IO Format: %I64d & %I64u

Submit Status

Description

Inna loves sleeping very much, so she needs n alarm clocks in total to wake up. Let's suppose that Inna's room is a 100 × 100 square with the lower left corner at point (0, 0) and with the upper right corner at point (100, 100). Then the alarm clocks are points with integer coordinates in this square.

The morning has come. All n alarm clocks in Inna's room are ringing, so Inna wants to turn them off. For that Inna has come up with an amusing game:

  • First Inna chooses a type of segments that she will use throughout the game. The segments can be either vertical or horizontal.
  • Then Inna makes multiple moves. In a single move, Inna can paint a segment of any length on the plane, she chooses its type at the beginning of the game (either vertical or horizontal), then all alarm clocks that are on this segment switch off. The game ends when all the alarm clocks are switched off.

Inna is very sleepy, so she wants to get through the alarm clocks as soon as possible. Help her, find the minimum number of moves in the game that she needs to turn off all the alarm clocks!

Input

The first line of the input contains integer n(1 ≤ n ≤ 105) — the number of the alarm clocks. The next n lines describe the clocks: the i-th line contains two integers xiyi — the coordinates of the i-th alarm clock (0 ≤ xi, yi ≤ 100).

Note that a single point in the room can contain any number of alarm clocks and the alarm clocks can lie on the sides of the square that represents the room.

Output

In a single line print a single integer — the minimum number of segments Inna will have to draw if she acts optimally.

Sample Input

Input
4
0 0
0 1
0 2
1 0
Output
2
Input
4
0 0
0 1
1 0
1 1
Output
2
Input
4
1 1
1 2
2 3
3 3
Output
3

Hint

In the first sample, Inna first chooses type "vertical segments", and then she makes segments with ends at : (0, 0), (0, 2); and, for example,(1, 0), (1, 1). If she paints horizontal segments, she will need at least 3 segments.

In the third sample it is important to note that Inna doesn't have the right to change the type of the segments during the game. That's why she will need 3 horizontal or 3 vertical segments to end the game.

Source

题意:一个二维矩阵,每个格子都有一个数,每次可以让一列或者一行的数全变成0。目的是让他们全变成0,问最少需要几步。
题解:选择行和列中有数的条数小的那一个,只关行或者只关列的,如果该行或者该列全都为0则不计入次数,就是全是0的条不用关。
#include <iostream>
#include <stdlib.h>
#include <stdio.h>
#include <algorithm>
#include <string.h>
#include <math.h>
using namespace std;
typedef long long ll;
int main()
{
int i,j,m,n,sum1,sum2,x,y,a[],b[];
while (cin>>n)
{
sum1=;
sum2=;
memset(a,,sizeof(a));
memset(b,,sizeof(b));
for (i=;i<n;i++)
{
cin>>x>>y;
a[x]=;
b[y]=;
}
for (i=;i<;i++)
if (a[i])
sum1++;
for (i=;i<;i++)
if (b[i])
sum2++;
if (sum1<sum2)
cout<<sum1<<endl;
else
cout<<sum2<<endl;
}
return ;
}

Codeforces 390A( 模拟题)的更多相关文章

  1. CodeForces - 427B (模拟题)

    Prison Transfer Time Limit: 1000MS   Memory Limit: 262144KB   64bit IO Format: %I64d & %I64u Sub ...

  2. CodeForces - 404B(模拟题)

    Marathon Time Limit: 1000MS   Memory Limit: 262144KB   64bit IO Format: %I64d & %I64u Submit Sta ...

  3. CodeForces - 404A(模拟题)

    Valera and X Time Limit: 1000MS   Memory Limit: 262144KB   64bit IO Format: %I64d & %I64u Submit ...

  4. CodeForces 1B 模拟题。

    H - 8 Time Limit:10000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Statu ...

  5. Educational Codeforces Round 2 A. Extract Numbers 模拟题

    A. Extract Numbers Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/600/pr ...

  6. Codeforces 767B. The Queue 模拟题

    B. The Queue time limit per test:1 second memory limit per test:256 megabytes input:standard input o ...

  7. Codeforces Beta Round #7 B. Memory Manager 模拟题

    B. Memory Manager 题目连接: http://www.codeforces.com/contest/7/problem/B Description There is little ti ...

  8. Codeforces Beta Round #5 B. Center Alignment 模拟题

    B. Center Alignment 题目连接: http://www.codeforces.com/contest/5/problem/B Description Almost every tex ...

  9. Codeforces Beta Round #3 C. Tic-tac-toe 模拟题

    C. Tic-tac-toe 题目连接: http://www.codeforces.com/contest/3/problem/C Description Certainly, everyone i ...

随机推荐

  1. 洛谷P1202 [USACO1.1]黑色星期五Friday the Thirteenth

    题目描述 13号又是一个星期五.13号在星期五比在其他日子少吗?为了回答这个问题,写一个程序,要求计算每个月的十三号落在周一到周日的次数.给出N年的一个周期,要求计算1900年1月1日至1900+N- ...

  2. Operating System Memory Management、Page Fault Exception、Cache Replacement Strategy Learning、LRU Algorithm

    目录 . 引言 . 页表 . 结构化内存管理 . 物理内存的管理 . SLAB分配器 . 处理器高速缓存和TLB控制 . 内存管理的概念 . 内存覆盖与内存交换 . 内存连续分配管理方式 . 内存非连 ...

  3. 关于bash的shellshock漏洞

    这一漏洞的描述如下: Shellshock (CVE-2014-6271, CVE-2014-6277, CVE-2014-6278, CVE-2014-7169, CVE-2014-7186, CV ...

  4. Linux中的TUN/TAP设备

    今天才发现这家伙...怎么讲...深以为耻.晚上的任务是加深对它的了解,就这么定了. 1. General questions.1.1 What is the TUN ?  The TUN is Vi ...

  5. eclipse中新建python项目报错:Project interpreter not specified

    eclipse-windows-preferences-python

  6. shell脚本等的操作

    1.命令替换:`` 反向单引号,也称重音符.键盘上和~键在一起的那个键呦,千万不要敲成单引号. A. 使用了``后,shell首先替换输出中``括起来的date命令,然后执行整个输出命令. B.命令替 ...

  7. MyEclipse------如何在特定目录下创建文件夹

    Directory.jsp <%@ page language="java" import="java.util.*" pageEncoding=&quo ...

  8. js中对象概念的声明

  9. ECSHOP用户协议字体颜色更改

    ECSHOP用户协议字体颜色更改 ECSHOP教程/ ecshop教程网(www.ecshop119.com) 2013-11-12   ECSHOP用户协议模板文件article_pro.dwt 这 ...

  10. C#实现eval 进行四则运算

    昨天在园子里看到有园友,写了相同标题的一篇文章.重点讲的是中缀表达式转换为后缀表达式的算法,但是实现的四则运算 有bug.其实我没看之前也不懂什么是 中缀和后缀表达式,之前有用过js eval 内置函 ...