Educational Codeforces Round 74 (Rated for Div. 2) A. Prime Subtraction
链接:
https://codeforces.com/contest/1238/problem/A
题意:
You are given two integers x and y (it is guaranteed that x>y). You may choose any prime integer p and subtract it any number of times from x. Is it possible to make x equal to y?
Recall that a prime number is a positive integer that has exactly two positive divisors: 1 and this integer itself. The sequence of prime numbers starts with 2, 3, 5, 7, 11.
Your program should solve t independent test cases.
思路:
考虑大于1的素数可以用素数补充, 合数都是素数的倍数也可以.
代码:
#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
LL x, y;
int main()
{
int t;
cin >> t;
while (t--)
{
cin >> x >> y;
if (x-y == 1)
puts("NO");
else
puts("YES");
}
return 0;
}
Educational Codeforces Round 74 (Rated for Div. 2) A. Prime Subtraction的更多相关文章
- Educational Codeforces Round 74 (Rated for Div. 2) D. AB-string
链接: https://codeforces.com/contest/1238/problem/D 题意: The string t1t2-tk is good if each letter of t ...
- Educational Codeforces Round 74 (Rated for Div. 2) C. Standard Free2play
链接: https://codeforces.com/contest/1238/problem/C 题意: You are playing a game where your character sh ...
- Educational Codeforces Round 74 (Rated for Div. 2) B. Kill 'Em All
链接: https://codeforces.com/contest/1238/problem/B 题意: Ivan plays an old action game called Heretic. ...
- Educational Codeforces Round 74 (Rated for Div. 2)
传送门 A. Prime Subtraction 判断一下是否相差为\(1\)即可. B. Kill 'Em All 随便搞搞. C. Standard Free2play 题意: 现在有一个高度为\ ...
- Educational Codeforces Round 74 (Rated for Div. 2)【A,B,C【贪心】,D【正难则反的思想】】
A. Prime Subtractiontime limit per test2 secondsmemory limit per test256 megabytesinputstandard inpu ...
- Educational Codeforces Round 74 (Rated for Div. 2)补题
慢慢来. 题目册 题目 A B C D E F G 状态 √ √ √ √ × ∅ ∅ //√,×,∅ 想法 A. Prime Subtraction res tp A 题意:给定\(x,y(x> ...
- Educational Codeforces Round 74 (Rated for Div. 2)E(状压DP,降低一个m复杂度做法含有集合思维)
#define HAVE_STRUCT_TIMESPEC#include<bits/stdc++.h>using namespace std;char s[100005];int pos[ ...
- Educational Codeforces Round 39 (Rated for Div. 2) B. Weird Subtraction Process[数论/欧几里得算法]
https://zh.wikipedia.org/wiki/%E8%BC%BE%E8%BD%89%E7%9B%B8%E9%99%A4%E6%B3%95 取模也是一样的,就当多减几次. 在欧几里得最初的 ...
- Educational Codeforces Round 60 (Rated for Div. 2) - C. Magic Ship
Problem Educational Codeforces Round 60 (Rated for Div. 2) - C. Magic Ship Time Limit: 2000 mSec P ...
随机推荐
- Git在新电脑拉github 上的项目
非小白教程.多少有点了解的才能看懂. 1,安装git 忽略,任意i找一个图文教程即可 2,在命令行模式 输入 cd ~/.ssh/ 进入c:administrator的文件下的.ssh文件夹: 或者 ...
- canvas与svg的区别
1.历史: canvas是html5提供的新元素. 而svg存在的历史要比canvas久远,已经有十几年了.svg并不是html5专有的标签,最初svg是用xml技术(超文本扩展语言,可以自定义标签或 ...
- mysql常用操作及常见问题
常用操作 mysql备份: --整库备份 docker exec 容器ID mysqldump -uroot -p密码 --databases 库名 > 库名.sql --仅导出表和数据 mys ...
- java中内存泄露有几种?如何分析泄露原因
一.Java内存回收机制 不论哪种语言的内存分配方式,都需要返回所分配内存的真实地址,也就是返回一个指针到内存块的首地址.Java中对象是采用new或者反射的方法创建的,这些对象的创建都是在堆(Hea ...
- 希尔排序——C语言
希尔排序 希尔排序是插入排序的一种,又称“缩小增量排序”,希尔排序是直接插入排序算法的一种更高效的改进版本,关于插入排序可以看下这篇随笔:插入排序——C语言 (图片来源:https://www.cnb ...
- win8系统安装.net Framework3.5
Win8 离线安装 .Net Framework 3.5(工具+方法)(支持Win8.1) 微软在最新的 Win8 / Win8.1 系统中没有集成 .NET 3.5,如果安装的话,必须是在线安装,甚 ...
- c# 163网易发送邮件
是4.0的,说以添加包是 代码: public class SendEmailInfo { /// <summary> /// 发送邮件 /// </summary> /// ...
- 清空windows系统网络配置
清空windows系统网络配置 来源 https://www.cnblogs.com/lemon-rain/p/9569990.html 具体描述:qq,微信可用网,但其他不能用. 一.win+r ...
- 冒泡(bubblesort)、选择排序、插入排序、快速排序
冒泡排序(bubblesort) 特点:通过换位置的方式,一直向上冒泡 package main import "fmt" func bubbleSortAsc(arrayA [] ...
- SIP协议参数详解
1.1 SIP消息分类 SIP协议是以层协议的形式组成的,就是说它的行为是以一套相对独立的处理阶段来描述的,每个阶段之间的关系不是很密切. SIP协议将Server和User Agent之间的通讯的 ...