Source:

PAT A1050 String Subtraction (20 分)

Description:

Given two strings S​1​​ and S​2​​, S=S​1​​−S​2​​ is defined to be the remaining string after taking all the characters in S​2​​ from S​1​​. Your task is simply to calculate S​1​​−S​2​​ for any given strings. However, it might not be that simple to do it fast.

Input Specification:

Each input file contains one test case. Each case consists of two lines which gives S​1​​ and S​2​​, respectively. The string lengths of both strings are no more than 1. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.

Output Specification:

For each test case, print S​1​​−S​2​​ in one line.

Sample Input:

They are students.
aeiou

Sample Output:

Thy r stdnts.

Keys:

Code:

 /*
Data: 2019-07-21 19:47:24
Problem: PAT_A1050#String Subtraction
AC: 08:34 题目大意:
给定字符串S和T,把T中的字符从S中删去
*/ #include<cstdio>
#include<string>
#include<iostream>
using namespace std;
char mp[]={}; int main()
{
#ifdef ONLINE_JUDGE
#else
freopen("Test.txt", "r", stdin);
#endif string s,t;
getline(cin,s);
getline(cin,t);
for(int i=; i<t.size(); i++)
mp[t[i]]=;
for(int i=; i<s.size(); i++)
if(mp[s[i]]==)
printf("%c", s[i]); return ;
}

Given two strings S​1​​ and S​2​​, S=S​1​​−S​2​​ is defined to be the remaining string after taking all the characters in S​2​​ from S​1​​. Your task is simply to calculate S​1​​−S​2​​ for any given strings. However, it might not be that simple to do it fast.

Input Specification:

Each input file contains one test case. Each case consists of two lines which gives S​1​​ and S​2​​, respectively. The string lengths of both strings are no more than 1. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.

Output Specification:

For each test case, print S​1​​−S​2​​ in one line.

Sample Input:

They are students.
aeiou

Sample Output:

Thy r stdnts.

PAT_A1050#String Subtraction的更多相关文章

  1. PAT 解题报告 1050. String Subtraction (20)

    1050. String Subtraction (20) Given two strings S1 and S2, S = S1 - S2 is defined to be the remainin ...

  2. PAT 1050 String Subtraction

    1050 String Subtraction (20 分)   Given two strings S​1​​ and S​2​​, S=S​1​​−S​2​​ is defined to be t ...

  3. 1050 String Subtraction (20 分)

    1050 String Subtraction (20 分) Given two strings S​1​​ and S​2​​, S=S​1​​−S​2​​ is defined to be the ...

  4. pat1050. String Subtraction (20)

    1050. String Subtraction (20) 时间限制 10 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Giv ...

  5. pat 1050 String Subtraction(20 分)

    1050 String Subtraction(20 分) Given two strings S​1​​ and S​2​​, S=S​1​​−S​2​​ is defined to be the ...

  6. PAT 甲级 1050 String Subtraction (20 分) (简单送分,getline(cin,s)的使用)

    1050 String Subtraction (20 分)   Given two strings S​1​​ and S​2​​, S=S​1​​−S​2​​ is defined to be t ...

  7. PAT甲级——1050 String Subtraction

    1050 String Subtraction Given two strings S​1​​ and S​2​​, S=S​1​​−S​2​​ is defined to be the remain ...

  8. 1050. String Subtraction (20)

    this problem  is from PAT, which website is http://pat.zju.edu.cn/contests/pat-a-practise/1050. firs ...

  9. String Subtraction

    Given two strings S1 and S2, S = S1 - S2 is defined to be the remaining string after taking all the ...

随机推荐

  1. 屏蔽浏览器默认样式 user agent stylesheet

    user agent stylesheet <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" &q ...

  2. 使用js在页面上新建文件夹

    使用js在页面上新建文件夹 <!DOCTYPE html> <html lang="en"> <head> <meta charset=& ...

  3. JavaFX教程

    JavaFX是Java的下一代图形用户界面工具包.JavaFX是一组图形和媒体API,我们可以用它们来创建和部署富客户端应用程序. JavaFX允许开发人员快速构建丰富的跨平台应用程序.JavaFX通 ...

  4. Tomcat启动脚本(1)startup.bat

    @echo off rem Licensed to the Apache Software Foundation (ASF) under one or more rem contributor lic ...

  5. __user表示是一个user mode的pointer,所以kernel不可能直接使用。

    __user表示是一个用户空间的指针,所以kernel不可能直接使用. #ifdef __CHECKER__# define __user __attribute__((noderef, addres ...

  6. 【牛客网-剑指offer】跳台阶

    题目: 一只青蛙一次可以跳上1级台阶,也可以跳上2级.求该青蛙跳上一个n级的台阶总共有多少种跳法(先后次序不同算不同的结果). 考点: 递归和循环 思路: 1)利用二叉树,左孩子为跳一级,右孩子为跳两 ...

  7. 微信小程序のwxs语言

    一.wxs介绍 wxs是微信小程序自身的脚本语言,用来过滤和计算.wxs可以通过文件可模块标签来定义 文件需要.wxs后缀文件 二.实例 <wxs module="test1" ...

  8. 根据ThinkPHP官方文档学习opensns框架

    根据ThinkPHP官方文档学习opensns框架 1.解读Application下各个Controller文件夹下的作用 控制器类的命名方式是:控制器名(驼峰法,首字母大写)+Controller ...

  9. shell浮点数运算

  10. RK3288编译 Android 5.1 固件

    1 准备工作 编译 Android 对机器的配置要求较高: 64 位 CPU 16GB 物理内存+交换内存 30GB 空闲的磁盘空间用于构建,源码树另外占用大约 25GB Ubuntu 14.04 操 ...