PAT_A1050#String Subtraction
Source:
Description:
Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1−S2 for any given strings. However, it might not be that simple to do it fast.
Input Specification:
Each input file contains one test case. Each case consists of two lines which gives S1 and S2, respectively. The string lengths of both strings are no more than 1. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.
Output Specification:
For each test case, print S1−S2 in one line.
Sample Input:
They are students.
aeiou
Sample Output:
Thy r stdnts.
Keys:
Code:
/*
Data: 2019-07-21 19:47:24
Problem: PAT_A1050#String Subtraction
AC: 08:34 题目大意:
给定字符串S和T,把T中的字符从S中删去
*/ #include<cstdio>
#include<string>
#include<iostream>
using namespace std;
char mp[]={}; int main()
{
#ifdef ONLINE_JUDGE
#else
freopen("Test.txt", "r", stdin);
#endif string s,t;
getline(cin,s);
getline(cin,t);
for(int i=; i<t.size(); i++)
mp[t[i]]=;
for(int i=; i<s.size(); i++)
if(mp[s[i]]==)
printf("%c", s[i]); return ;
}
Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1−S2 for any given strings. However, it might not be that simple to do it fast.
Input Specification:
Each input file contains one test case. Each case consists of two lines which gives S1 and S2, respectively. The string lengths of both strings are no more than 1. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.
Output Specification:
For each test case, print S1−S2 in one line.
Sample Input:
They are students.
aeiou
Sample Output:
Thy r stdnts.
PAT_A1050#String Subtraction的更多相关文章
- PAT 解题报告 1050. String Subtraction (20)
1050. String Subtraction (20) Given two strings S1 and S2, S = S1 - S2 is defined to be the remainin ...
- PAT 1050 String Subtraction
1050 String Subtraction (20 分) Given two strings S1 and S2, S=S1−S2 is defined to be t ...
- 1050 String Subtraction (20 分)
1050 String Subtraction (20 分) Given two strings S1 and S2, S=S1−S2 is defined to be the ...
- pat1050. String Subtraction (20)
1050. String Subtraction (20) 时间限制 10 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Giv ...
- pat 1050 String Subtraction(20 分)
1050 String Subtraction(20 分) Given two strings S1 and S2, S=S1−S2 is defined to be the ...
- PAT 甲级 1050 String Subtraction (20 分) (简单送分,getline(cin,s)的使用)
1050 String Subtraction (20 分) Given two strings S1 and S2, S=S1−S2 is defined to be t ...
- PAT甲级——1050 String Subtraction
1050 String Subtraction Given two strings S1 and S2, S=S1−S2 is defined to be the remain ...
- 1050. String Subtraction (20)
this problem is from PAT, which website is http://pat.zju.edu.cn/contests/pat-a-practise/1050. firs ...
- String Subtraction
Given two strings S1 and S2, S = S1 - S2 is defined to be the remaining string after taking all the ...
随机推荐
- centos svn 安装
#检查是否安装了低版本的SVN [root@zck /]# rpm -qa subversion #卸载旧版本SVN [root@zck modules]# yum remove subversion ...
- Webx.0-Web4.0:Web4.0
ylbtech-Webx.0-Web4.0:Web4.0 Web系统是人类迄今最伟大的发明之一,也是计算机影响人类最深远的表现. 1.返回顶部 1. Web系统是人类迄今最伟大的发明之一,也是计算机影 ...
- libVEX学习
VEX IR是一种更加接近于compiler使用的中间语言/中间表示,它是不依赖于特定体系架构的. 1. Code Blocks code blocks是VEX处理代码的一个单元,使用IRSB结构体表 ...
- upc组队赛6 Greeting Card【打表】
Greeting Card 题目描述 Quido plans to send a New Year greeting to his friend Hugo. He has recently acqui ...
- Node.js、vue.js的使用
Vue.js的使用 1.下载Node.js 2.打开cmd 3.执行命令 npm i 4.输入命令 npm run serve 5.浏览器打开 http://localhost:8080
- fedora 25重新安装引导
引导区被其他系统给覆盖了,重新安装引导 grub2-install /dev/sdb GRUB_SAVEDEFAULT=true BIOS grub2-mkconfig -o /boot/grub2/ ...
- 用java api 实现查询 Hive 数据
版本:cdh5.4.7, hive1.1.0 pom文件 <dependency> <groupId>org.apache.hive</groupId> <a ...
- 还在用 KPI 管研发团队?用 OKR 倍儿爽!
近几年,经常能听到不少技术管理者在倡导:用 OKR 来管理及打造一个高执行力的研发团队. 据我了解,OKR 最成功的落地公司是在 Google --一家有着非常浓厚工程师文化的公司,后来陆续在 Fac ...
- CF1223D
CF1223D 不需要动的一定值域连续 #include<iostream> #include<cstring> #include<cstdio> #include ...
- android中的Serveice组件
创建 配置 Service: 1.定义一个继承了Service类的子类 2.在 AndroidManifest.xml清单文件中对开发的Service进行配置 Service和Activity很相似, ...