Lamda所有的Capture均是引用

【Lamda所有的Capture均是引用】

　　下面的程序，两个lambda 引用的实际上是同一个a、b。连int都能引用了，说明Lambda对所有类型都是以引用来处理。

 int a = ;
         int b = ;
         Func<int> exe = ()=>{
             int tmp = a;
             a = b;
             b = tmp+b;
             return a;
         };
         Debug.Log("a1 = " + exe());
         Debug.Log("a2 = " + exe());
         Debug.Log("a3 = " + exe());
         Debug.Log("a4 = " + exe());
         Debug.Log("a5 = " + exe());
 
         Func<int> exe2 = ()=>{
             int tmp = a;
             a = b;
             b = tmp+b;
             return a;
         };
         Debug.Log("a1 = " + exe2());
         Debug.Log("a2 = " + exe2());
         Debug.Log("a3 = " + exe2());
         Debug.Log("a4 = " + exe2());
         Debug.Log("a5 = " + exe2());

　　结果为：