Lightoj 1023 - Discovering Permutations
| Time Limit: 0.5 second(s) | Memory Limit: 32 MB |
In this problem you have to find the permutations using the first N English capital letters. Since there can be many permutations, you have to print the first K permutations.
Input
Input starts with an integer T (≤ 100), denoting the number of test cases.
Each case contains two integers N, K (1 ≤ N ≤ 26, 1 ≤ K ≤ 30).
Output
For each case, print the case number in a line. Then print the first K permutations that contain the first N English capital letters in alphabetical order. If there are less than K permutations then print all of them.
Sample Input |
Output for Sample Input |
|
2 3 8 10 10 |
Case 1: ABC ACB BAC BCA CAB CBA Case 2: ABCDEFGHIJ ABCDEFGHJI ABCDEFGIHJ ABCDEFGIJH ABCDEFGJHI ABCDEFGJIH ABCDEFHGIJ ABCDEFHGJI ABCDEFHIGJ ABCDEFHIJG |
水dfs
/* ***********************************************
Author :guanjun
Created Time :2016/6/28 14:50:20
File Name :1023.cpp
************************************************ */
#include <iostream>
#include <cstring>
#include <cstdlib>
#include <stdio.h>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <string>
#include <math.h>
#include <stdlib.h>
#include <iomanip>
#include <list>
#include <deque>
#include <stack>
#define ull unsigned long long
#define ll long long
#define mod 90001
#define INF 0x3f3f3f3f
#define maxn 10010
#define cle(a) memset(a,0,sizeof(a))
const ull inf = 1LL << ;
const double eps=1e-;
using namespace std;
priority_queue<int,vector<int>,greater<int> >pq;
struct Node{
int x,y;
};
struct cmp{
bool operator()(Node a,Node b){
if(a.x==b.x) return a.y> b.y;
return a.x>b.x;
}
}; bool cmp(int a,int b){
return a>b;
}
char s[];
int n,k,num,mark;
int vis[];
void dfs(string s,int cnt){
if(cnt==n){
num++;
cout<<s<<endl;
if(num==k)mark=;
return ;
}
if(mark)return ;
for(int i=;i<n;i++){
if(!vis[i]){
vis[i]=;
dfs(s+char(i+'A'),cnt+);
vis[i]=;
}
}
}
int main()
{
#ifndef ONLINE_JUDGE
freopen("in.txt","r",stdin);
#endif
//freopen("out.txt","w",stdout);
int T;
cin>>T;
for(int t=;t<=T;t++){
printf("Case %d:\n",t);
cin>>n>>k;
cle(vis);
num=mark=;
dfs("",);
}
return ;
}
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