Codeforces 113C
C. Double Happinesstime limit per test5 seconds
memory limit per test128 megabytes
inputstandard input
outputstandard output
On the math lesson a teacher asked each pupil to come up with his own lucky numbers. As a fan of number theory Peter chose prime numbers. Bob was more original. He said that number t is his lucky number, if it can be represented as:
t = a2 + b2, where a, b are arbitrary positive integers.
Now, the boys decided to find out how many days of the interval [l, r] (l ≤ r) are suitable for pair programming. They decided that the day i (l ≤ i ≤ r) is suitable for pair programming if and only if the number i is lucky for Peter and lucky for Bob at the same time. Help the boys to find the number of such days.
InputThe first line of the input contains integer numbers l, r (1 ≤ l, r ≤ 3·108).
OutputIn the only line print the number of days on the segment [l, r], which are lucky for Peter and Bob at the same time.
Sample test(s)input3 5output1input6 66output7
/*************************************************************************
> File Name: 113C.cpp
> Author: Stomach_ache
> Mail: sudaweitong@gmail.com
> Created Time: 2014年07月20日 星期日 13时34分53秒
> Propose:
************************************************************************/ #include <cmath>
#include <string>
#include <bitset>
#include <cstdio>
#include <fstream>
#include <cstring>
#include <iostream>
#include <algorithm>
using namespace std; const int maxn = 1e8+1e8+1e8;
bitset<maxn> p; int
main(void) {
int L, R;
scanf("%d %d\n", &L, &R);
p.set();
for (int i = ; i*i <= R; i+=) if (p[i]) for (int j = i*i; j <= R; j+=*i) p[j] = false;
int ans = ;
for (int i = ; i <= R; i+=) if (p[i] && i >= L) ans++;
ans += (L <= && R >= ) ? : ;
printf("%d\n", ans); return ;
}
Codeforces 113C的更多相关文章
- python爬虫学习(5) —— 扒一下codeforces题面
上一次我们拿学校的URP做了个小小的demo.... 其实我们还可以把每个学生的证件照爬下来做成一个证件照校花校草评比 另外也可以写一个物理实验自动选课... 但是出于多种原因,,还是绕开这些敏感话题 ...
- 【Codeforces 738D】Sea Battle(贪心)
http://codeforces.com/contest/738/problem/D Galya is playing one-dimensional Sea Battle on a 1 × n g ...
- 【Codeforces 738C】Road to Cinema
http://codeforces.com/contest/738/problem/C Vasya is currently at a car rental service, and he wants ...
- 【Codeforces 738A】Interview with Oleg
http://codeforces.com/contest/738/problem/A Polycarp has interviewed Oleg and has written the interv ...
- CodeForces - 662A Gambling Nim
http://codeforces.com/problemset/problem/662/A 题目大意: 给定n(n <= 500000)张卡片,每张卡片的两个面都写有数字,每个面都有0.5的概 ...
- CodeForces - 274B Zero Tree
http://codeforces.com/problemset/problem/274/B 题目大意: 给定你一颗树,每个点上有权值. 现在你每次取出这颗树的一颗子树(即点集和边集均是原图的子集的连 ...
- CodeForces - 261B Maxim and Restaurant
http://codeforces.com/problemset/problem/261/B 题目大意:给定n个数a1-an(n<=50,ai<=50),随机打乱后,记Si=a1+a2+a ...
- CodeForces - 696B Puzzles
http://codeforces.com/problemset/problem/696/B 题目大意: 这是一颗有n个点的树,你从根开始游走,每当你第一次到达一个点时,把这个点的权记为(你已经到过不 ...
- CodeForces - 148D Bag of mice
http://codeforces.com/problemset/problem/148/D 题目大意: 原来袋子里有w只白鼠和b只黑鼠 龙和王妃轮流从袋子里抓老鼠.谁先抓到白色老鼠谁就赢. 王妃每次 ...
随机推荐
- Spring MVC(十二)--使用ModelView实现重定向
上一篇总结了使用返回字符串的方式实现重定向以及重定向过程中传递字符串参数和pojo参数的过程,本篇总结另一种重定向的实现方式--返回ModelAndView 这次的场景是这样的:在页面输入一些信息添加 ...
- linux命令快速手记 — 让手指跟上思考的速度(四)
pm2 list:列出pm2方式启动的所有程序 pm2 monit:显示每个应用程序的CPU和内存占用情况 scp:远程复制和本地上传,适用于本地ssh登录到远程服务器 scp root@10.10. ...
- <每日一题>题目29:五个数字能组成多少互不重复的四位数
#有五个数字:1.2.3.4.5,能组成多少个互不相同且无重复数字的四位数?各是多少? e =[] for a in range(1,6): for b in range(1,6): for c in ...
- vue表格之@row-click="handleSelect" 与setCurrentRow
作用:表格行点击触发的事件 注意与@change.@selection-change事件的区分 <el-table ref="RoomTable" @row-click=&q ...
- python 拷贝某个文件到另一个目录下
python的shutil包含有很多文件拷贝的函数,各种各样的,要实现我文章题目的目的,使用shutil.copy函数即可 shutil.copy(文件的路径,另一个目录)
- Leetcode942. DI String Match增减字符串
给定只含 "I"(增大)或 "D"(减小)的字符串 S ,令 N = S.length. 返回 [0, 1, ..., N] 的任意排列 A 使得对于所有 i ...
- 前缀数组O(n^3)做法
前缀数组O(n^3)做法 s.substr()的应用非常方便 令string s = "; ); //只有一个数字5表示从下标为5开始一直到结尾:sub1 = "56789&quo ...
- LOJ#3119 随机立方体
解:极大值至少为1.我们尝试把最大那个数的影响去掉. 最大那个数所在的一层(指一个三维十字架)都是不可能成为最大值的. 考虑容斥.我们试图求除了最大值以外至少有k个极大值的概率. 我们钦定某k个位置是 ...
- jeecmsv8 shiro 分析
源代码注释可见 https://github.com/chenbo19867758/jeecmsV8-BoBo.git 1.后台登录页面 /jeeadmin/jeecms/login.do 1 w ...
- MyBatis-Spring(一)--搭建步骤
MyBatis-Spring项目不是Sring项目的子框架,而是由MyBatis社区开发的,所以在使用之前首先要导入mybatis-spring包,我是通过maven添加的依赖: <depend ...