133. Clone Graph
题目:
Clone an undirected graph. Each node in the graph contains a label
and a list of its neighbors
.
Nodes are labeled uniquely.
We use #
as a separator for each node, and ,
as a separator for node label and each neighbor of the node.
As an example, consider the serialized graph {0,1,2#1,2#2,2}
.
The graph has a total of three nodes, and therefore contains three parts as separated by #
.
- First node is labeled as
0
. Connect node0
to both nodes1
and2
. - Second node is labeled as
1
. Connect node1
to node2
. - Third node is labeled as
2
. Connect node2
to node2
(itself), thus forming a self-cycle.
Visually, the graph looks like the following:
1
/ \
/ \
0 --- 2
/ \
\_/
题解:
拷贝图。图的遍历,主要就是DFS和BFS, 这道题考察基本功。需要注意的地点是如何建立visited数组,这道题因为lable unique,所以可以建立Map<Integer, UndirectedGraphNode>,假如lable有重复值,则建立Map的时候要使用Map<UndirectedGraphNode, UndirectedGraphNode>。 基本题目要多练习,这样拓展到难题以后才能借鉴思路。二刷的时候要注意recursive和iterative。
DFS:
Time Complexity - O(n), Space Complexity - O(n)
/**
* Definition for undirected graph.
* class UndirectedGraphNode {
* int label;
* List<UndirectedGraphNode> neighbors;
* UndirectedGraphNode(int x) { label = x; neighbors = new ArrayList<UndirectedGraphNode>(); }
* };
*/
public class Solution {
HashMap<Integer, UndirectedGraphNode> visited = new HashMap<>(); public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {
if(node == null)
return node;
if(visited.containsKey(node.label))
return visited.get(node.label); UndirectedGraphNode clone = new UndirectedGraphNode(node.label);
visited.put(clone.label, clone); for(UndirectedGraphNode neighbor : node.neighbors)
clone.neighbors.add(cloneGraph(neighbor)); return clone;
}
}
BFS:
Time Complexity - O(n), Space Complexity - O(n)
/**
* Definition for undirected graph.
* class UndirectedGraphNode {
* int label;
* List<UndirectedGraphNode> neighbors;
* UndirectedGraphNode(int x) { label = x; neighbors = new ArrayList<UndirectedGraphNode>(); }
* };
*/
public class Solution {
public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {
if(node == null)
return node; Queue<UndirectedGraphNode> q = new LinkedList<>();
q.offer(node);
HashMap<Integer, UndirectedGraphNode> visited = new HashMap<>();
visited.put(node.label, new UndirectedGraphNode(node.label)); while(!q.isEmpty()) {
UndirectedGraphNode newNode = q.poll(); for(UndirectedGraphNode neighbor : newNode.neighbors) {
if(!visited.containsKey(neighbor.label)) {
q.offer(neighbor);
visited.put(neighbor.label, new UndirectedGraphNode(neighbor.label));
}
visited.get(newNode.label).neighbors.add(visited.get(neighbor.label));
}
} return visited.get(node.label);
}
}
二刷:
Java:
DFS:
/**
* Definition for undirected graph.
* class UndirectedGraphNode {
* int label;
* List<UndirectedGraphNode> neighbors;
* UndirectedGraphNode(int x) { label = x; neighbors = new ArrayList<UndirectedGraphNode>(); }
* };
*/
public class Solution {
Map<Integer, UndirectedGraphNode> map = new HashMap<>(); public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {
if (node == null) return null;
if (map.containsKey(node.label)) return map.get(node.label);
UndirectedGraphNode newNode = new UndirectedGraphNode(node.label);
map.put(newNode.label, newNode); for (UndirectedGraphNode neighbor : node.neighbors) {
newNode.neighbors.add(cloneGraph(neighbor));
}
return newNode;
}
}
BFS:
/**
* Definition for undirected graph.
* class UndirectedGraphNode {
* int label;
* List<UndirectedGraphNode> neighbors;
* UndirectedGraphNode(int x) { label = x; neighbors = new ArrayList<UndirectedGraphNode>(); }
* };
*/
public class Solution {
public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {
if (node == null) return null;
Queue<UndirectedGraphNode> q = new LinkedList<>();
q.offer(node);
Map<Integer, UndirectedGraphNode> visited = new HashMap<>();
visited.put(node.label, new UndirectedGraphNode(node.label)); while (!q.isEmpty()) {
UndirectedGraphNode oldNode = q.poll();
for (UndirectedGraphNode neighbor : oldNode.neighbors) {
if (!visited.containsKey(neighbor.label)) {
q.offer(neighbor);
visited.put(neighbor.label, new UndirectedGraphNode(neighbor.label));
}
visited.get(oldNode.label).neighbors.add(visited.get(neighbor.label));
}
}
return visited.get(node.label);
}
}
Reference:
http://www.cnblogs.com/springfor/p/3874591.html
http://blog.csdn.net/linhuanmars/article/details/22715747
http://blog.csdn.net/fightforyourdream/article/details/17497883
http://www.programcreek.com/2012/12/leetcode-clone-graph-java/
https://leetcode.com/discuss/26988/depth-first-simple-java-solution
https://leetcode.com/discuss/44330/java-bfs-solution
https://leetcode.com/discuss/14969/simple-java-iterative-bfs-solution-with-hashmap-and-queue
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