UVa 12299 线段树 单点更新 RMQ with Shifts

因为shift操作中的数不多，所以直接用单点更新模拟一下就好了。

太久不写线段树，手好生啊，不是这错一下就是那错一下。

PS：输入写的我有点蛋疼，不知道谁有没有更好的写法。

 #include <iostream>
 #include <cstdio>
 #include <cstring>
 #include <algorithm>
 #include <vector>
 using namespace std;

 const int maxn =  + ;
 const int maxnode = (maxn << );
 const int INF = 0x3f3f3f3f;

 void scan(int& x)
 {
     x = ;
     char c = ' ';
     while(c < '' || c > '') c = getchar();
     while(c >= '' && c <= '') { x = x *  + c - ''; c = getchar(); }
 }

 int qL, qR;
 int p, v;
 int n, Q;
 int minv[maxnode];

 int a[maxn];

 void build(int o, int L, int R)
 {
     if(L == R) { scan(a[L]); minv[o] = a[L]; return ; }
     int M = (L + R) / ;
     build(o<<, L, M);
     build(o<<|, M+, R);
     minv[o] = min(minv[o<<], minv[o<<|]);
 }

 void update(int o, int L, int R)
 {
     //if(v >= minv[o]) return ;
     if(L == R) { minv[o] = v; return ; }

     int M = (L + R) / ;
     if(p <= M) update(o<<, L, M);
     else update(o<<|, M+, R);
     minv[o] = min(minv[o<<], minv[o<<|]);
 }

 int query(int o, int L, int R)
 {
     if(qL <= L && R <= qR) return minv[o];
     int ans = INF;
     int M = (L + R) / ;
     if(qL <= M) ans = min(ans, query(o<<, L, M));
     if(qR > M) ans = min(ans, query(o<<|, M+, R));
     return ans;
 }

 char op[];

 int main()
 {
     while(scanf("%d%d", &n, &Q) ==  && n)
     {
         build(, , n);
         while(Q--)
         {
             scanf("%s", op);
             int l = strlen(op);
             if(op[] == 'q')
             {
                 int i = ;
                 qL = ;
                 while(i < l && op[i] >= '' && op[i] <= '') { qL = qL *  + op[i] - ''; i++; }
                 while(i < l && (op[i] < '' || op[i] > '')) i++;
                 qR = ;
                 while(i < l && op[i] >= '' && op[i] <= '') { qR = qR *  + op[i] - ''; i++; }
                 printf("%d\n", query(, , n));
             }
             else
             {
                 vector<int> hehe;

                 for(int i = ; i < l;)
                 {
                     while(i < l && (op[i] < '' || op[i] > '')) i++;
                     if(i >= l) break;
                     int x = ;
                     while(i < l && op[i] >= '' && op[i] <= '') { x = x *  + op[i] - ''; i++; }
                     hehe.push_back(x);
                 }

                 int sz = hehe.size();
                 for(int i = ; i < sz - ; i++)
                 {
                     v = a[hehe[i + ]];
                     p = hehe[i];
                     update(, , n);
                 }
                 v = a[hehe[]];
                 p = hehe[sz - ];
                 update(, , n);

                 int t = a[hehe[]];
                 for(int i = ; i < sz - ; i++) a[hehe[i]] = a[hehe[i+]];
                 a[hehe[sz - ]] = t;
             }
         }
     }

     return ;
 }

代码君