[ACM_水题] UVA 12502 Three Families [2人干3人的活后分钱，水]

  Three Families 

Three families share a garden. They usually clean the garden together at the end of each week, but last week, family C was on holiday, so family A spent 5 hours, family B spent 4 hours and had everything done. After coming back, family C is willing to pay $90 to the other two families. How much should family A get? You may assume both families were cleaning at the same speed.

$90/(5+4)*5=$50? No no no. Think hard. The correct answer is $60. When you figured out why, answer the following question: If family A and B spent x and y hours respectively, and family C paid $z, how much should family A get? It is guaranteed that both families should get non-negative integer dollars.

WARNING: Try to avoid floating-point numbers. If you really need to, be careful!

Input

The first line contains an integer T (   T100), the number of test cases. Each test case contains three integers x,    y,    z (   1x,    y10,    1z1000).

Output

For each test case, print an integer, representing the amount of dollars that family A should get.

Sample Input

2
5 4 90
8 4 123

Sample Output

60
123

题目大意：水题，不解释。推出计算公式瞬秒！

 #include<iostream>
 #include<cstdio>
 using namespace std;
 int main(){
     int T;cin>>T;
     while(T--){
         int x,y,z;
         cin>>x>>y>>z;
         cout<<(*x*z)/(x+y)-z<<'\n';
     }return ;
 }