https://pintia.cn/problem-sets/994805342720868352/problems/994805343979159552

A clique is a subset of vertices of an undirected graph such that every two distinct vertices in the clique are adjacent. A maximal clique is a clique that cannot be extended by including one more adjacent vertex. (Quoted from https://en.wikipedia.org/wiki/Clique_(graph_theory))

Now it is your job to judge if a given subset of vertices can form a maximal clique.

Input Specification:

Each input file contains one test case. For each case, the first line gives two positive integers Nv (≤ 200), the number of vertices in the graph, and Ne, the number of undirected edges. Then Ne lines follow, each gives a pair of vertices of an edge. The vertices are numbered from 1 to Nv.

After the graph, there is another positive integer M (≤ 100). Then M lines of query follow, each first gives a positive number K (≤ Nv), then followed by a sequence of K distinct vertices. All the numbers in a line are separated by a space.

Output Specification:

For each of the M queries, print in a line Yes if the given subset of vertices can form a maximal clique; or if it is a clique but not a maximal clique, print Not Maximal; or if it is not a clique at all, print Not a Clique.

Sample Input:

8 10
5 6
7 8
6 4
3 6
4 5
2 3
8 2
2 7
5 3
3 4
6
4 5 4 3 6
3 2 8 7
2 2 3
1 1
3 4 3 6
3 3 2 1

Sample Output:

Yes
Yes
Yes
Yes
Not Maximal
Not a Clique

代码:

#include <bits/stdc++.h>
using namespace std; int N, M, K;
int mp[220][220];
int vis[220]; int main() {
scanf("%d%d", &N, &M);
memset(mp, 0, sizeof(mp));
while(M --) {
int a, b;
scanf("%d%d", &a, &b);
mp[a][b] = mp[b][a] = 1;
}
scanf("%d", &K);
while(K --) {
int T;
vector<int> v;
memset(vis, 0, sizeof(vis));
scanf("%d", &T);
v.resize(T);
for(int i = 0; i < T; i ++) {
scanf("%d", &v[i]);
vis[v[i]] = 1;
} bool isclique = true;
for(int i = 0; i < T - 1; i ++) {
for(int j = i + 1; j < T; j ++) {
if(mp[v[i]][v[j]] == 0) {
isclique = false;
printf("Not a Clique\n");
break;
}
}
if(!isclique) break;
} if(!isclique) continue; bool ismax = true;
for(int i = 1; i <= N; i ++) {
if(vis[i] == 0) {
for(int j = 0; j < T; j ++) {
if(mp[v[j]][i] == 0) break;
if(j == T - 1) ismax = false;
}
}
if(!ismax) {
printf("Not Maximal\n");
break;
}
}
if(ismax) printf("Yes\n");
}
return 0;
}

  简单图论

FHFHFH

PAT 甲级 1142 Maximal Clique的更多相关文章

  1. PAT 1142 Maximal Clique[难]

    1142 Maximal Clique (25 分) A clique is a subset of vertices of an undirected graph such that every t ...

  2. [PAT] 1142 Maximal Clique(25 分)

    1142 Maximal Clique(25 分) A clique is a subset of vertices of an undirected graph such that every tw ...

  3. PAT 1142 Maximal Clique

    A clique is a subset of vertices of an undirected graph such that every two distinct vertices in the ...

  4. 1142. Maximal Clique (25)

    A clique is a subset of vertices of an undirected graph such that every two distinct vertices in the ...

  5. 1142 Maximal Clique

    题意:给出一个图,定义这样一个结点子集subset,若subset中的任意两结点不都相邻,则称之为Not a Clique:若subset中的任意两结点都相邻,则称之为Clique:若subset中的 ...

  6. PAT甲级目录

    树(23) 备注 1004 Counting Leaves   1020 Tree Traversals   1043 Is It a Binary Search Tree 判断BST,BST的性质 ...

  7. PAT甲级 图 相关题_C++题解

    图 PAT (Advanced Level) Practice 用到图的存储方式,但没有用到图的算法的题目 目录 1122 Hamiltonian Cycle (25) 1126 Eulerian P ...

  8. PAT A1142 Maximal Clique (25 分)——图

    A clique is a subset of vertices of an undirected graph such that every two distinct vertices in the ...

  9. PAT甲级考前整理(2019年3月备考)之三,持续更新中.....

    PAT甲级考前整理一:https://www.cnblogs.com/jlyg/p/7525244.html,主要讲了131题的易错题及坑点 PAT甲级考前整理二:https://www.cnblog ...

随机推荐

  1. Velocity学习2

    Velocity是一个基于java的模板引擎(template engine).它允许任何人仅仅简单的使用模板语言(template language)来引用由java代码定义的对象. 当Veloci ...

  2. Deep Learning 资料总结

    http://colah.github.io/posts/2014-03-NN-Manifolds-Topology/ : 理解神经网络   ELU:

  3. (转)为什么所有浏览器的user-agent都是Mozilla

    最早的时候有一个浏览器叫NCSA Mosaic,把自己标称为NCSA_Mosaic/2.0 (Windows 3.1),它支持文字显示的同时还支持图片,于是Web开始好玩起来. 然后出现了一个新的网页 ...

  4. Kali Linux 下安装中文版输入法

    1.更新软件源: 修改sources.list文件: vim /etc/apt/sources.list 或者 leafpad /etc/apt/sources.list 然后选择添加以下源: deb ...

  5. CentOS安装log.io

    官网 http://logio.org/ log.io是运行在node.js之上的 可通过浏览器访问服务器日志 类似于tail -f命令 它只负责实时传输数据 而不会去存储历史数据 npm insta ...

  6. Python 循环的技巧

    当在字典中循环时,用 items() 方法可将关键字和对应的值同时取出 >>> knights = {'gallahad': 'the pure', 'robin': 'the br ...

  7. 我看微软收购GitHub

    今天是微软收购GitHub的第三天,之前很多人担心被微软收购的GitHub会步Skype,诺基亚等企业的后尘,凡此种种我觉得更多人的担心是:GitHub不再开源免费罢了. GitHub今年4月刚成立十 ...

  8. LeetCode-63.不同路径Ⅱ

    一个机器人位于一个 m x n 网格的左上角 (起始点在下图中标记为“Start” ). 机器人每次只能向下或者向右移动一步.机器人试图达到网格的右下角(在下图中标记为“Finish”). 现在考虑网 ...

  9. 从一个简单的寻路问题深入Q-learning

    这第一篇随笔实际上在我的科学网博客上是首发,我重新拿到博客园再发一次是希望以此作为我学习Q-learning的一个新的开始.以后这边主技术,科学网博客主理论.我也会将科学网那边技术类的文章转过来的.希 ...

  10. python常用模块目录

    博客目录总纲首页 python其他知识目录 random  hashlib  os  sys  json __name__ shutil  xlrd  xlwt   xlutils 核心模块:os s ...