uva116

这题是一道dp的水题，类似于数塔，从右向左倒着加上去，找到最小值，然后在从左到右输出路径。

#include"iostream"
#include"stdio.h"
#include"algorithm"
#include"string.h"
#include"string"
#include"cmath"
#include"queue"
#include"stack"
#include"map"
using namespace std;
const int mx=;
const int inf=;
int n,m;
int maze[mx][mx];
int MIN(int a,int b,int c)
{
    int d=a<b?a:b;
    return  c<d?c:d;
}
void DP()
{
    int i,j;
    for(j=m-;j>=;j--)
    {
        for(i=;i<n;i++)
        {
            maze[i][j-]+=MIN(maze[(i+n-)%n][j],maze[i][j],maze[(i+)%n][j]);
        }
    }
}
void OUTPUT()
{
    int i,j,min_length=inf,path;
    for(i=;i<n;i++)
    {
        if(maze[i][]<min_length)
        {
            min_length=maze[i][];
            path=i;
        }
    }
    cout<<path+;
    for(j=;j<m;j++)
    {
        int r=path;
        int min_num=maze[path][j];
        if(maze[(path+n-)%n][j]==min_num)
        {
            if((path+n-)%n<r) r=(path+n-)%n;
        }
        else  if(maze[(path+n-)%n][j]<min_num)
        {
            min_num=maze[(path+n-)%n][j];
            r=(path+n-)%n;
        }

        if(maze[(path+)%n][j]==min_num)
        {
            if((path+)%n<r) r=(path+)%n;
        }
        else if(maze[(path+)%n][j]<min_num)
        {
            r=(path+)%n;
            min_num=maze[(path+)%n][j];
        }
        path=r;
        cout<<" "<<path+;
    }
    cout<<endl<<min_length<<endl;
}
int main()
{
 //   freopen("E:\\in.txt","r",stdin);
    int i,j;
    while(scanf("%d%d",&n,&m)==)
    {
        for(i=;i<n;i++)
        {
            for(j=;j<m;j++)
            {
                scanf("%d",&maze[i][j]);
            }
        }
        DP();
        OUTPUT();
    }
    return ;
}