传送门:

http://acm.hdu.edu.cn/showproblem.php?pid=1110

Equipment Box

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 2989    Accepted Submission(s): 759

Problem Description
There is a large room in the Pyramid called Room-of-No-Return. Its floor is covered by rectangular tiles of equal size. The name of the room was chosen because of the very high number of traps and mechanisms in it. The ACM group has spent several years studying the secret plan of this room. It has made a clever plan to avoid all the traps. A specially trained mechanic was sent to deactivate the most feared trap called Shattered Bones. After deactivating the trap the mechanic had to escape from the room. It is very important to step on the center of the tiles only; he must not touch the edges. One wrong step and a large rock falls from the ceiling squashing the mechanic like a pancake. After deactivating the trap, he realized a horrible thing: the ACM plan did not take his equipment box into consideration. The box must be laid onto the ground because the mechanic must have both hands free to prevent contact with other traps. But when the box is laid on the ground, it could touch the line separating the tiles. And this is the main problem you are to solve.
 
Input
The input consists of T test cases. The number of them (T) is given on the first line of the input. Each test case consists of a single line. The line contains exactly four integer numbers separated by spaces: A, B, X and Y. A and Bindicate the dimensions of the tiles, X and Y are the dimensions of the equipment box (1 <= A, B, X, Y <= 50000).
 
Output
Your task is to determine whether it is possible to put the box on a single tile -- that is, if the whole box fits on a single tile without touching its border. If so, you are to print one line with the sentence "Escape is possible.". Otherwise print the sentence "Box cannot be dropped.".
 
Sample Input
2
10 10 8 8
8 8 10 10
 
Sample Output
Escape is possible.
Box cannot be dropped.
 
Source
分析:
题目意思:
问你一个大矩形里面能不能放一个小矩形
 思路:
1.大矩形长边大于小矩形长边并且大矩形短边大于小矩形短边 肯定可以放进
 
2.小矩形面积大于大矩形或者小矩形最短边大于大矩形最短边 肯定放不下
 
3.画图。。。(图片拖起来看,文本格式问题。。。。。。。。。)

code:

#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
#define max_v 25
bool f(double A,double B,double a,double b)
{
double d=sqrt(a*a+b*b);
double a1=asin(A/d);
double a2=asin(b/d)*2.0;
double h=cos(a1-a2)*d;
if(B>h)
return true;
else
return false;
}
int main()
{
int t;
bool flag;
scanf("%d",&t);
while(t--)
{
double A,B,a,b;
scanf("%lf %lf %lf %lf",&A,&B,&a,&b);
if(A<B)
swap(A,B);
if(a<b)
swap(a,b);
if(A>a&&B>b)//大矩形长边大于小矩形长边并且大矩形短边大于小矩形短边 肯定可以放进
{
flag=true;
}
else if(A*B<=a*b||b>=B)//小矩形面积大于大矩形或者小矩形最短边大于大矩形最短边 肯定放不下
{
flag=false;
}else
{
flag=f(A,B,a,b);
}
if(flag)
{
cout << "Escape is possible." << endl; }else
{
cout << "Box cannot be dropped." << endl; }
}
return ;
}

HDU 1110 Equipment Box (判断一个大矩形里面能不能放小矩形)的更多相关文章

  1. java 坐标系运算 判断一个地理坐标是否在电子围栏 圆、矩形、多边形区域内

    转载自:https://blog.csdn.net/Deepak192/article/details/79402694 测试没问题,我用的是原始坐标:要注意的是坐标转换问题,要看当前是属于什么坐标系 ...

  2. 判断一个面(Polygon)是不是矩形

    判断一个面是不是矩形在GIS中很长用的功能,那么怎么判断一个面是不是矩形呢. 这里先要弄懂一些概念,面是什么,先看OGC标准的定义. 我的英文水平有限,(有翻译更好的请留言,如果翻译的准确将被采纳)大 ...

  3. 判断大文件是否上传成功(一个大文件上传到ftp,判断是否上传完成)

    大文件上传ftp,不知道有没有上传完成,如果没有上传完成另一个程序去下载这个文件,导致下载不完整. 判断一个文件是否上传完成的方法: /** * 间隔一段时间去计算文件的长度来判断文件是否写入完成 * ...

  4. 图论期末大作业编程题(如何判断一个4连通4正则图为无爪、无K4图)

    博士期间估计这可能是唯一一个要编程的作业,搞了半天弄出这个东西,放这里为以后用到的时候查找方便. 说来也是可笑,读博士期间发现大家对上课也都没什么兴趣,老师也是那么回事,都说博士期间学的课程是要有助于 ...

  5. HDU 1756 Cupid's Arrow 计算几何 判断一个点是否在多边形内

    LINK:Cupid's Arrow 前置函数 atan2 返回一个向量的幅角.范围为[Pi,-Pi) 值得注意的是 返回的是 相对于x轴正半轴的辐角. 而判断一个点是否在一个多边形内 通常有三种方法 ...

  6. POJ 1380 Equipment Box (暴力枚举)

    Equipment Box 题目链接: http://acm.hust.edu.cn/vjudge/contest/130510#problem/B Description There is a la ...

  7. Android 判断一个 View 是否可见 getLocalVisibleRect(rect) 与 getGlobalVisibleRect(rect)

    Android 判断一个 View 是否可见 getLocalVisibleRect(rect) 与 getGlobalVisibleRect(rect) [TOC] 这两个方法的区别 View.ge ...

  8. C#算法之判断一个字符串是否是对称字符串

    记得曾经一次面试时,面试官给我电脑,让我现场写个算法,判断一个字符串是不是对称字符串.我当时用了几分钟写了一个很简单的代码. 这里说的对称字符串是指字符串的左边和右边字符顺序相反,如"abb ...

  9. [译] AlphaGo 的确是一个大事件

    [译] AlphaGo 的确是一个大事件 转自:http://www.jianshu.com/p/157a15de47df 字数3797 阅读696 评论0 喜欢4 作者:Michael Nielse ...

随机推荐

  1. matlab中如何根据t检验参数查找t检验值

    这个问题花了一些时间.先看图 这个是t检验里面的公式,但是如何在matlab中找到该式子对应的值,我现在才知道. 就是这样:x=tinv(1-α/2,n-1)----t(n)分布的上侧α分位数     ...

  2. java并发编程 - Exexctor简介

    Exexctor 常用类关系图 Executor 接口 Excutor 接口定义如下 ExecutorService ExecutorService 是一个比 Executor 使用更广泛的子类接口, ...

  3. 《Python编程从入门到实践》_第七章_用户输入和whlie循环

    函数input()的工作原理 函数input()让程序暂停运行,等待用户输入一些文本.获取用户输入后,python将其存储在一个变量中,以方便你使用. #输入用户名 username = input( ...

  4. ubuntu遇到了 dpkg was interrupted, you must manually run 'dpkg..的问题

    dpkg was interrupted, you must manually run 'dpkg --configure -a' to correct the problem. E: _cache- ...

  5. Nginx的各种报错总结

    1.Nginx安装过程报错 错误一:软件依赖包未正确安装问题---PCRE依赖包没有安装 ./configure: error: the HTTP rewrite module requires th ...

  6. bootstrap dialog对话框,完成操作提示框

    1. 依赖文件: bootstrap.js bootstrap-dialog.js bootstrap.css bootstrap-dialog.css 2.代码 BootstrapDialog.co ...

  7. sql查询结果多对多转为一对多返回前端

    企业表 ent_EnterpriseArchives  有id,企业名称 entName veh_Vehicle 车辆表,有所属企业id  companyId,车辆id,车牌号licPlate 目的是 ...

  8. HTML 5中的新特性

    HTML 5中的新特性 html5新增了一些语义化更好的标签元素.首先,让我们来了解一下HTML语义化. 1.什么是HTML语义化? 根据内容的结构化(内容语义化),选择合适的标签(代码语义化)便于开 ...

  9. 提交自己的包到 npm 中

    npm npm全称Node Package Manager,是node.js的模块依赖管理工具.使用github管理NPM包的代码,并定期提交至NPM服务器:npm官网 提交自己开发的NPM包 创建p ...

  10. 纯CSS实现Tab切换标签效果代码

    在线演示地址如下: http://demo.jb51.net/js/2015/css-tab-bq-style-cha-codes/ <!DOCTYPE html PUBLIC "-/ ...