Description:

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will automatically contact the police if two adjacent houses were broken into on the same night.

Given a list of non-negative integers representing the amount of money of each house, determine the maximum amount of money you can rob tonight without alerting the police.

求数组中不相邻两个数组合的最大值。

ps.难道这就是传说中的DP

public class Solution {
public int rob(int[] nums) { if(nums.length == 0)
return 0;
if(nums.length == 1)
return nums[0];
if(nums.length == 2)
return Math.max(nums[0], nums[1]);
int[] res = new int[nums.length];
res[0] = nums[0];
res[1] = nums[1];
res[2] = nums[0] + nums[2];
for(int i=3; i<nums.length; i++) {
res[i] = Math.max(res[i-2],res[i-3]) + nums[i];
}
return Math.max(res[nums.length-1], res[nums.length-2]);
}
}

LeetCode——House Robber的更多相关文章

  1. [LeetCode] House Robber III 打家劫舍之三

    The thief has found himself a new place for his thievery again. There is only one entrance to this a ...

  2. [LeetCode] House Robber II 打家劫舍之二

    Note: This is an extension of House Robber. After robbing those houses on that street, the thief has ...

  3. [LeetCode] House Robber 打家劫舍

    You are a professional robber planning to rob houses along a street. Each house has a certain amount ...

  4. LeetCode House Robber III

    原题链接在这里:https://leetcode.com/problems/house-robber-iii/ 题目: The thief has found himself a new place ...

  5. LeetCode House Robber

    原题链接在这里:https://leetcode.com/problems/house-robber/ 题目: You are a professional robber planning to ro ...

  6. Leetcode House Robber II

    本题和House Robber差不多,分成两种情况来解决.第一家是不是偷了,如果偷了,那么最后一家肯定不能偷. class Solution(object): def rob(self, nums): ...

  7. [LeetCode]House Robber II (二次dp)

    213. House Robber II     Total Accepted: 24216 Total Submissions: 80632 Difficulty: Medium Note: Thi ...

  8. LeetCode House Robber 家庭劫犯(dp)

    题意:有一个整数序列,从中挑出一些数字,使得总和是最大,前提是,相邻的两个数字中只能挑其一.比如1 2 3 就只能挑2或者1和3. 思路:很直观的题,dp思想.降低规模,从小规模开始考虑.如果只有两个 ...

  9. Solution to LeetCode Problem Set

    Here is my collection of solutions to leetcode problems. Related code can be found in this repo: htt ...

随机推荐

  1. 指针的引用(*&)与指针的指针(**)

    指针的引用(*&)与指针的指针(**) 在下列函数声明中,为什么要同时使用*和&符号?以及什么场合使用这种声明方式? void func1( MYCLASS *&pBuildi ...

  2. pthread_cond_wait()函数的详解

    http://hi.baidu.com/tjuer/item/253cc6d66b921317d90e4483 了解 pthread_cond_wait() 的作用非常重要 -- 它是 POSIX 线 ...

  3. vm虚拟化问题积累

    EXSi是什么?答:是一个独立的系统,承载了虚拟机管理台,虚拟机存储设备等核心要件的一个系统,需要靠客户机通过vsphere连接后进行管理. 问题集:一.建立桌面池找不到模板机问题: 目前因为此问题已 ...

  4. java-jdbc循环设置sql参数

    PreparedStatement sta=null; Connection conn=null; @Test public void Test2() { //获取连接池 ComboPooledDat ...

  5. 手工配置oracle数据库

    手工配置Oracle 10G Enterprise Manager今天安装oracle,反复装了几遍都报下面错误:试了几种方法都不行:由于以下错误,Enterprise Manager配置失败启动Da ...

  6. TensorFlow基础笔记(13) tf.name_scope tf.variable_scope学习

    转载http://blog.csdn.net/jerr__y/article/details/60877873 1. 首先看看比较简单的 tf.name_scope(‘scope_name’). tf ...

  7. 【转】【C#】全局键盘监听

    using System; using System.Collections.Generic; using System.Text; using System.Runtime.InteropServi ...

  8. (转)SDL2.0在mfc窗口中显示yuv的一种方法

    DWORD ThreadFun() {    //用mfc窗口句柄创建一个sdl window    SDL_Window * pWindow = SDL_CreateWindowFrom( (voi ...

  9. linux -- Ubuntu查看修改mysql的登录名和密码、安装phpmyadmin

    安装好mysql后,在终端输入 mysql -u root -p 按回车,输入密码后提示access denied......ues password YES/NO的错误 原因是用户名或密码不对! 查 ...

  10. 查看CentOS的网络带宽出口

    检查维护系统的时候,经常会要查看服务器的网络端口是多大的,所以需要用到Linux的一个命令. 如何查看CentOS的网络带宽出口多大?可以用下面的命令来查看. # ethtool eth0 前面是命令 ...