模拟 2015百度之星资格赛 1003 IP聚合

题目传送门

 /*
     模拟水题，排序后找出重复的ip就可以了
 */
 #include <cstdio>
 #include <iostream>
 #include <algorithm>
 #include <cstring>
 #include <string>
 #include <cmath>
 using namespace std;
 const int MAXN = 1e3 + ;
 const int INF = 0x3f3f3f3f;
 struct Ip
 {
     int a, b, c, d;
 }ip[MAXN];
 struct H
 {
     int a, b, c, d;
 }h[MAXN];
 int ans[];
 bool cmp(H x, H y)
 {
     if (x.a == y.a)
     {
         if (x.b == y.b)
         {
             if (x.c == y.c)    return x.d < y.d;
             else    return x.c < y.c;
         }
         else    return x.b < y.b;
     }
     else    return x.a < y.a;
 }
 int main(void)        //2015百度之星资格赛 1003 IP聚合
 {
     int t, cas = ;
     scanf ("%d", &t);
     while (t--)
     {
         int n, m;    scanf ("%d%d", &n, &m);
         for (int i=; i<=n; ++i)
             scanf ("%d.%d.%d.%d", &ip[i].a, &ip[i].b, &ip[i].c, &ip[i].d);
         memset (ans, , sizeof (ans));
         for (int i=; i<=m; ++i)
         {
             int u, v, w, x;
             scanf ("%d.%d.%d.%d", &u, &v, &w, &x);
             for (int j=; j<=n; ++j)
             {
                 h[j].a = (ip[j].a & u);    h[j].b = (ip[j].b & v);
                 h[j].c = (ip[j].c & w);    h[j].d = (ip[j].d & x);
             }
             sort (h+, h++n, cmp);
             int cnt = ;
             for (int k=; k<=n; ++k)
             {
                 if (h[k].a == h[k-].a &&
                     h[k].b == h[k-].b &&
                     h[k].c == h[k-].c &&
                     h[k].d == h[k-].d)    cnt++;
             }
             ans[i] = (n - cnt);
         }
         printf ("Case #%d:\n", ++cas);
         for (int i=; i<=m; ++i)    printf ("%d\n", ans[i]);
     }
     return ;
 }
 /*
 2
 5 2
 192.168.1.0
 192.168.1.101
 192.168.2.5
 192.168.2.7
 202.14.27.235
 255.255.255.0
 255.255.0.0
 4 2
 127.127.0.1
 10.134.52.0
 127.0.10.1
 10.134.0.2
 235.235.0.0
 1.57.16.0
 */