python字典练习题

写代码：有如下字典
按照要求实现每一个功能
dict = {"k1":"v1","k2":"v2","k3":"v3"}
1、请循环遍历出所有的key

dict = {"k1":"v1","k2":"v2","k3":"v3"}

#1、请循环遍历出所有的key

for k in dict:

    print(k)

[root@webserver test]# cat loop_dict_keys.py
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
#1、请循环遍历出所有的key
dict = {"k1":"v1","k2":"v2","k3":"v3"}
for k in dict:
print(k)
[root@webserver test]# python3 loop_dict_keys.py
k1
k2
k3
[root@webserver test]#

2、请循环遍历出所有的value

#2、请循环遍历出所有的value

for k in dict:

    print(dict[k])

[root@webserver test]# cat loop_dict_values.py
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
#2、请循环遍历出所有的value
dict = {"k1":"v1","k2":"v2","k3":"v3"}
for k in dict:
print(dict[k])

[root@webserver test]# python3 loop_dict_values.py
v1
v2
v3
[root@webserver test]#

3、请循环遍历出所有的key和value

#3、请循环遍历出所有的key和value

for k in dict:

    print(k,dict[k])

[root@webserver test]# cat loop_dict_kv.py
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
#1、请循环遍历出所有的key
dict = {"k1":"v1","k2":"v2","k3":"v3"}
for k in dict:
print(k,dict[k])
[root@webserver test]# python3 loop_dict_kv.py
k1 v1
k2 v2
k3 v3
[root@webserver test]#

4、请在字典中增加一个键值对,"k4":"v4"，输出添加后的字典

#4、请在字典中增加一个键值对,"k4":"v4"，输出添加后的字典

dict = {"k1":"v1","k2":"v2","k3":"v3"}

print("dict原来的值: ",dict)

dict["k4"] = "v4"

print("dict新增\"k4\":\"v4\"后的值: ",dict)

[root@webserver test]# cat insert_dict.py
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
#4、请在字典中增加一个键值对,"k4":"v4"，输出添加后的字典
dict = {"k1":"v1","k2":"v2","k3":"v3"}
print("dict原来的值: ",dict)
dict["k4"] = "v4"
print("dict新增\"k4\":\"v4\"后的值: ",dict)
[root@webserver test]# python3 insert_dict.py
dict原来的值: {'k1': 'v1', 'k2': 'v2', 'k3': 'v3'}
dict新增"k4":"v4"后的值: {'k1': 'v1', 'k2': 'v2', 'k3': 'v3', 'k4': 'v4'}
[root@webserver test]#

5、请删除字典中键值对"k1":"v1",并输出删除后的结果

#5、请删除字典中键值对"k1":"v1",并输出删除后的结果

dict = {"k1":"v1","k2":"v2","k3":"v3","k4":"v4"}

print("dict删除k1前的值: ",dict)

dict.pop("k1")

print("dict删除k1后的值: ",dict)

[root@webserver test]# cat delete.dict.py
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
#5、请删除字典中键值对"k1":"v1",并输出删除后的结果
dict = {"k1":"v1","k2":"v2","k3":"v3","k4":"v4"}
print("dict删除k1前的值: ",dict)
dict.pop("k1")
print("dict删除k1后的值: ",dict)
[root@webserver test]# python3 delete.dict.py
dict删除k1前的值: {'k1': 'v1', 'k2': 'v2', 'k3': 'v3', 'k4': 'v4'}
dict删除k1后的值: {'k2': 'v2', 'k3': 'v3', 'k4': 'v4'}
[root@webserver test]#

6、请删除字典中键"k5"对应的键值对，如果字典中不存在键"k5",则不报错，返回None

dict = {"k1":"v1","k2":"v2","k3":"v3","k4":"v4"}
print(dict)
print("删除不存在的k5,不报错，返回值: ",dict.pop("k5",None))

[root@webserver test]# cat not_dict_k.py
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
#6、请删除字典中键"k5"对应的键值对，如果字典中不存在键"k5",则不报错，返回None
dict = {"k1":"v1","k2":"v2","k3":"v3","k4":"v4"}
print(dict)
print("删除不存在的k5,不报错，返回值: ",dict.pop("k5",None))

[root@webserver test]# python3 not_dict_k.py
{'k1': 'v1', 'k2': 'v2', 'k3': 'v3', 'k4': 'v4'}
删除不存在的k5,不报错，返回值: None
[root@webserver test]#

7、请获取字典中"k2"对应的值

# 7、请获取字典中"k2"对应的值

dict = {"k1":"v1","k2":"v2","k3":"v3","k4":"v4"}

print(dict["k2"])

[root@webserver test]# cat get_exist.py
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
# 7、请获取字典中"k2"对应的值
dict = {"k1":"v1","k2":"v2","k3":"v3","k4":"v4"}
print(dict["k2"])
[root@webserver test]# python3 get_exist.py
v2
[root@webserver test]#

8、请获取字典中"k6"对应的值,如果不存在，则不报错，并且让其返回None。

#8、请获取字典中"k6"对应的值,如果不存在，则不报错，并且让其返回None。

dict = {"k1":"v1","k2":"v2","k3":"v3","k4":"v4"}

print("dict值: ",dict)

print(dict.get("k6",None))

#8、请获取字典中"k6"对应的值,如果不存在，则不报错，并且让其返回None。
dict = {"k1":"v1","k2":"v2","k3":"v3","k4":"v4"}
print("dict值: ",dict)
print(dict.get("k6",None))
[root@webserver test]# python3 get_not_exist.py
dict值: {'k1': 'v1', 'k2': 'v2', 'k3': 'v3', 'k4': 'v4'}
None
[root@webserver test]#

9、现有dict2 = {"k1":"v11","a":"b"},通过一行操作使dict2 = {"k1":"v1","k2":"v2","k3":"v3","a":"b"}

#9、现有dict2 = {"k1":"v11","a":"b"},通过一行操作使dict2 = {"k1":"v1","k2":"v2","k3":"v3","a":"b"}

dict = {"k1":"v1","k2":"v2","k3":"v3"}

dict2 = {"k1":"v11","a":"b"}

dict2.update(dict)

print("dict: ",dict)

print("dict2: ",dict2)

[root@webserver test]# cat update_dict_union.py
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
#9、现有dict2 = {"k1":"v11","a":"b"},通过一行操作使dict2 = {"k1":"v1","k2":"v2","k3":"v3","a":"b"}
dict = {"k1":"v1","k2":"v2","k3":"v3"}
dict2 = {"k1":"v11","a":"b"}
dict2.update(dict)
print("dict: ",dict)
print("dict2: ",dict2)
[root@webserver test]# python3 update_dict_union.py
dict: {'k1': 'v1', 'k2': 'v2', 'k3': 'v3'}
dict2: {'k1': 'v1', 'a': 'b', 'k2': 'v2', 'k3': 'v3'}
[root@webserver test]#

10、组合嵌套题。写代码，有如下列表，按照要求实现每一个功能

"""
lis = [["k",["qwe",20,{"k1":["tt",3,"1"]},89],"ab"]]
10.1、将列表中的数字变成字符串"100"(用两种方法)
10.2、将列表中的字符串"1"变成数字101(用两种方法)
"""

# 10.1 方法1:

print(lis[0][1][2].get("k1")[0].upper())

# 10.1 方法2:

print(lis[0][1][2].get("k1")[0].swapcase())

# 10.2 方法1:

lis[0][1][2]["k1"][2] = 101

# 10.2 方法2:

lis[0][1][2].get("k1")[2]=101

11、

按照要求，实现如下功能：

"""

现有一个列表li = [1,2,3,'a',4,'c'],有一个字典(此字典是动态生成的，你并不知道他里面有多少

键值对，所以用dic={}模拟字典；现在需要完成这样的操作：如果该字典没有"k1"这个键，那就创建

这个"k1"键和对应的值(该键对应的值为空列表)，并将列表li中的索引位为奇数对应的元素，添加到

"k1"这个键对应的空列表中。如果该字典中有"k1"这个键，且k1对应的value是列表类型。那就将该列表li

中的索引位为奇数对应的元素，添加到"k1"，这个键对应的值中。

"""

dic = {}

li = [1,2,3,'a',4,'c']

if "k1" not in dic:

    dic.setdefault("k1",[])

    for i in li:

        if li.index(i)%2 == 1:

            dic["k1"].append(i)

        else:

            if type(dic["k1"]) == type([]):

                for i in li:

                    if li.index(i)%2 == 1:

                        dic["k1"].append(i)

            else:

                print("字典K1，VALUE不是列表，无法追加")

print(dic)

[root@webserver test]# cat union_dic_lis.py
#!/usr/bin/env python3
# -*- coding:utf-8 -*-
dic = {}
li = [1,2,3,'a',4,'c']
if "k1" not in dic:
dic.setdefault("k1",[])
for i in li:
if li.index(i)%2 == 1:
dic["k1"].append(i)
else:
if type(dic["k1"]) == type([]):
for i in li:
if li.index(i)%2 == 1:
dic["k1"].append(i)
else:
print("字典K1，VALUE不是列表，无法追加")
print(dic)
[root@webserver test]# python3 union_dic_lis.py
{'k1': [2, 'a', 'c', 2, 2, 'a', 'c', 'a', 2, 'a', 'c', 'c']}
[root@webserver test]#