Chess Placing
time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

You are given a chessboard of size 1 × n. It is guaranteed that n is even. The chessboard is painted like this: "BWBW...BW".

Some cells of the board are occupied by the chess pieces. Each cell contains no more than one chess piece. It is known that the total number of pieces equals to .

In one step you can move one of the pieces one cell to the left or to the right. You cannot move pieces beyond the borders of the board. You also cannot move pieces to the cells that are already occupied.

Your task is to place all the pieces in the cells of the same color using the minimum number of moves (all the pieces must occupy only the black cells or only the white cells after all the moves are made).

Input

The first line of the input contains one integer n (2 ≤ n ≤ 100, n is even) — the size of the chessboard.

The second line of the input contains  integer numbers  (1 ≤ pi ≤ n) — initial positions of the pieces. It is guaranteed that all the positions are distinct.

Output

Print one integer — the minimum number of moves you have to make to place all the pieces in the cells of the same color.

Examples
input

Copy
6
1 2 6
output

Copy
2
input

Copy
10
1 2 3 4 5
output

Copy
10
Note

In the first example the only possible strategy is to move the piece at the position 6 to the position 5 and move the piece at the position 2 to the position 3. Notice that if you decide to place the pieces in the white cells the minimum number of moves will be 3.

In the second example the possible strategy is to move  in 4 moves, then  in 3 moves,  in 2 moves and  in 1 move.

两种情况分别跑一遍,求最少

#include <iostream>
#include<cstring>
#include<string>
#include<cstdio>
#include<algorithm>
#include<cmath>
#include<deque>
#include<vector>
#define ll long long
#define inf 0x3f3f3f3f
#define mod 1000000007;
using namespace std;
int main()
{
int n;
std::cin>>n;
int a[];
for(int i=;i<=n/;i++)
{
std::cin>>a[i];
}
sort(a+,a++n/);
int s1=;
int s2=;
int c1=;
int c2=;
for(int i=;i<=n/;i++,c1+=,c2+=)
{
s1+=abs(a[i]-c1);
s2+=abs(a[i]-c2);
}
s1=min(s2,s1);
std::cout<<s1;
return ;
}

codeforce 985A Chess Placing(暴力)的更多相关文章

  1. codeforces 985A Chess Placing

    题意: 移动最少的步数,使得所有的棋子在同一颜色的格子中. 每次一个棋子只能向左或者向右移动一步,不能移到有棋子的格子中. 思路: 枚举全黑和全白的情况. 对于每一个需要移动的棋子,它移动到的位置一定 ...

  2. A - Chess Placing CodeForces - 985A

    You are given a chessboard of size 1 × n. It is guaranteed that n is even. The chessboard is painted ...

  3. codeforce Number of Ways(暴力)

    #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #d ...

  4. A. Chess Placing

    链接 [https://codeforces.com/contest/985/problem/A] 题意 给你一个偶数n,输入n/2个数,代表棋子的位置,有一个1*n的棋盘是黑白相间的 问你使得所有棋 ...

  5. CF985A Chess Placing【思维】

    [链接]:CF985A [题意]:给你n和n/2个数ai,每个ai和奇数.偶数比较距离(注意选了奇数,偶数的距离就不要算了,反之同理),求最小的答案. [代码]: #include <iostr ...

  6. Educational Codeforces Round 44 (Rated for Div. 2)

    题目链接:https://codeforces.com/contest/985 ’A.Chess Placing 题意:给了一维的一个棋盘,共有n(n必为偶数)个格子.棋盘上是黑白相间的.现在棋盘上有 ...

  7. 逆向暴力求解 538.D Weird Chess

    11.12.2018 逆向暴力求解 538.D Weird Chess New Point: 没有读好题 越界的情况无法判断,所以输出任何一种就可以 所以他给你的样例输出完全是误导 输出还搞错了~ 输 ...

  8. CodeForce 855B 暴力or线段树

    CodeForce 855B 暴力or线段树 题意 给你一串数,然后找出三个数,他们的前后关系和原来一样,可以相同,然后分别乘p,q,r,求他们积的和最大,并且输出这个数. 解题思路 这个可以使用线段 ...

  9. codeforce 429D. Tricky Function (思维暴力过)

    题目描述 Iahub and Sorin are the best competitive programmers in their town. However, they can't both qu ...

随机推荐

  1. python学习笔记(生成xml)

    想着给框架加些功能 首先想到的是生成测试报告 这里就涉及到了生成什么格式的文件 我这边就准备生成 xml 格式的文件 自己先学习了整理了下 代码如下: #!/usr/bin/env python # ...

  2. Selenium学习笔记(1) - 自动化测试体系与原理

    技术体系 基于代码的测试(Code-Based Testing) 基于协议的测试(Protocol-Based Testing) 基于界面的测试(GUI-Based Testing) 工作原理 基于代 ...

  3. 51nod-1201-数位dp

    http://www.51nod.com/onlineJudge/questionCode.html#!problemId=1201 1201 整数划分 基准时间限制:1 秒 空间限制:131072 ...

  4. 【河南省第十届ACM 省赛 A-谍报分析】

    题目描述 “八一三”淞沪抗战爆发后,*几次准备去上海前线视察和指挥作战.但都因为宁沪之间的铁路和公路遭到了敌军的严密封锁,狂轰滥炸,一直未能成行. 特科组织,其主要任务是保卫的安全,了解和掌握敌方的动 ...

  5. hdu4715

    题解: 二分图判断 建立原图的补图 判断是否是二分图 代码: #include<cstdio> #include<cmath> #include<cstring> ...

  6. LRU与LFU比较

    提到缓存,有两点是必须要考虑的:(1)缓存数据和目标数据的一致性问题.(2)缓存的过期策略(机制).     其中,缓存的过期策略涉及淘汰算法.常用的淘汰算法有下面几种:(1)FIFO:First I ...

  7. [置顶] 长谈:关于 View Measure 测量机制,让我一次把话说完

    <倚天屠龙记中>有这么一处:张三丰示范自创的太极剑演示给张无忌看,然后问他记住招式没有.张无忌说记住了一半.张三丰又慢吞吞使了一遍,问他记住多少,张无忌说只记得几招了.张三丰最后又示范了一 ...

  8. B. Clique Problem(贪心)

    题目链接: B. Clique Problem time limit per test 2 seconds memory limit per test 256 megabytes input stan ...

  9. InnoSetup使用笔记

    今天用InnoSetup做安装包时,因为要装的驱动区分32位.64位,64位系统中要安装32位+64位驱动. 想在脚本中进行判断.折腾一阵,终于搞定: 参考了:http://379910987.blo ...

  10. C# 程序部署、调试时间长的解决办法

    最近在做数控折弯机项目时,VS2008环境下采用C#..NET Compact Framework开发WinCE.Windows Mobile程序时,编译项目非常慢,看着进度条慢慢刷,有时候需要几分钟 ...