5C - A == B ?

Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".

Input

each test case contains two numbers A and B.

Output

for each case, if A is equal to B, you should print "YES", or print "NO".

Sample Input

1 2
2 2
3 3
4 3

Sample Output

NO
YES
YES
NO

// too young

 #include<stdio.h>
 int main()
 {
     int a, b;
     while(scanf("%d %d", &a, &b)!=EOF)
     {
         if(a==b) printf("YES\n");
         else printf("NO\n");
     }
     return ;
 }

Output Limit Exceeded

// double只能表示15或16位有效数字，而这道题数字可能会十分长
// 传送门：准确详解：C/C++ float、double数据类型的表示范围及精度

 #include<stdio.h>
 #include<stdlib.h>
 int main()
 {
     double a,b;
     char num1[], num2[];
     while(scanf("%s %s", num1, num2)!=EOF)
     {
         a=atof(num1); b=atof(num2);
         if(a==b) printf("YES\n");
         else printf("NO\n");
     }
     return ;
 }

WA

// 小数点后无意义的零要删去

 #include<stdio.h>
 #include<string.h>
 char a[], b[];
 void process(char *num)
 {
     int len=strlen(num);
     if(strstr(num,".")!=NULL)
     {
         while(num[--len]=='');
         if(num[len]=='.')
             num[len]='\0';
     }
 }
 int main()
 {
     while(scanf(" %s %s", a, b)!=EOF)
     {
         process(a); process(b);
         if(strcmp(a,b)) printf("NO\n");
         else printf("YES\n");
     }
     return ;
 }

WA*2

// 

 #include<stdio.h>
 #include<string.h>
 char a[], b[];
 void process(char *num)
 {
     int len=strlen(num);
     if(strstr(num,".")!=NULL)
     {
         while(num[--len]=='');
         if(num[len]=='.')
             len--;
         num[++len]='\0';
     }
 }
 int main()
 {
     while(scanf(" %s %s", a, b)!=EOF)
     {
         process(a); process(b);
         if(strcmp(a,b)) printf("NO\n");
         else printf("YES\n");
     }
     return ;
 }

AC

// 判断两数是否相等还可用strcmp
// char *strstr(char *str1, char *str2); 寻找str2在str1中第一次出现的位置，返回位置指针