1107. Social Clusters (30)
When register on a social network, you are always asked to specify your hobbies in order to find some potential friends with the same hobbies. A "social cluster" is a set of people who have some of their hobbies in common. You are supposed to find all the clusters.
Input Specification:
Each input file contains one test case. For each test case, the first line contains a positive integer N (<=1000), the total number of people in a social network. Hence the people are numbered from 1 to N. Then N lines follow, each gives the hobby list of a person in the format:
Ki: hi[1] hi[2] ... hi[Ki]
where Ki (>0) is the number of hobbies, and hi[j] is the index of the j-th hobby, which is an integer in [1, 1000].
Output Specification:
For each case, print in one line the total number of clusters in the network. Then in the second line, print the numbers of people in the clusters in non-increasing order. The numbers must be separated by exactly one space, and there must be no extra space at the end of the line.
Sample Input:
8
3: 2 7 10
1: 4
2: 5 3
1: 4
1: 3
1: 4
4: 6 8 1 5
1: 4
Sample Output:
3
4 3 1
#include<stdio.h>
#include<vector>
#include<algorithm>
#include<math.h>
using namespace std;
int ans[][]; bool cmp(int a,int b)
{
return a > b;
} struct node
{
vector<int> child;
}; node Tree[]; int MIN = ;
int cnt = ;
bool vis[];
vector<int> Fun[];
vector<int> stu[];
void DFS(int root,int& sum)
{
for(int i = ;i < stu[root].size();++i)
{
for(int k = ;k < Fun[ stu[root][i] ].size();++k)
{
if(!vis[Fun[ stu[root][i] ][k]])
{
++sum;
vis[Fun[ stu[root][i] ][k]] = ;
DFS(Fun[ stu[root][i] ][k],sum);
}
}
}
} int main()
{
int n,num,tem;
double pri,rate;
scanf("%d",&n);
for(int i = ;i <= n ;++i)
{
scanf("%d",&num);
getchar();
for(int k = ;k < num;++k)
{
scanf("%d",&tem);
Fun[tem].push_back(i);
stu[i].push_back(tem);
}
}
vector<int> vv;
int cnt = ;;
for(int i = ;i <= n ;++i)
{
if(!vis[i])
{
int sum = ;
++cnt;
DFS(i,sum);
vv.push_back(sum);
}
}
sort(vv.begin(),vv.end(),cmp);
printf("%d\n",vv.size());
for(int i = ;i < vv.size();++i)
{
if(i == ) printf("%d",vv[]);
else printf(" %d",vv[i]);
}
printf("\n");
return ;
}
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