OpenJudge/Poj 2105 IP Address

1.链接地址：

http://poj.org/problem?id=2105

http://bailian.openjudge.cn/practice/2105

2.题目：

IP Address

Time Limit: 1000MS		Memory Limit: 30000K
Total Submissions: 18146		Accepted: 10456

Description

Suppose you are reading byte streams from any device, representing IP addresses. Your task is to convert a 32 characters long sequence of '1s' and '0s' (bits) to a dotted decimal format. A dotted decimal format for an IP address is form by grouping 8 bits at a time and converting the binary representation to decimal representation. Any 8 bits is a valid part of an IP address. To convert binary numbers to decimal numbers remember that both are positional numerical systems, where the first 8 positions of the binary systems are:

2

⁷

   2

⁶

  2

⁵

  2

⁴

  2

³

   2

²

  2

¹

  2

⁰

128 64  32  16  8   4   2   1 

Input

The input will have a number N (1<=N<=9) in its first line representing the number of streams to convert. N lines will follow.

Output

The output must have N lines with a doted decimal IP address. A dotted decimal IP address is formed by grouping 8 bit at the time and converting the binary representation to decimal representation.

Sample Input

4
00000000000000000000000000000000
00000011100000001111111111111111
11001011100001001110010110000000
01010000000100000000000000000001 

Sample Output

0.0.0.0
3.128.255.255
203.132.229.128
80.16.0.1

Source

México and Central America 2004

3.思路：

4.代码：

 #include "stdio.h"
 #include "stdlib.h"

 int f(char input[],int start)
 {
     int ans=;
     int i;
     for(i=;i<;i++)
     {
        ans=ans*+(input[i+start]-'');
     }
     return ans;
 }
 int main()
 {
     int a,b,c,d;
     int n;
     int i;
     char input[];
     scanf("%d\n",&n);
     for(i=;i<n;i++)
     {
         gets(input);
         a=f(input,);
         b=f(input,);
         c=f(input,);
         d=f(input,);
         printf("%d.%d.%d.%d\n",a,b,c,d);
     }
     //system("pause");
     return ;
 }