Google Code Jam 2009 Qualification Round Problem C. Welcome to Code Jam
本题的 Large dataset 本人尚未解决。
https://code.google.com/codejam/contest/90101/dashboard#s=p2
Problem
So you've registered. We sent you a welcoming email, to welcome you to code jam. But it's possible that you still don't feel welcomed to code jam. That's why we decided to name a problem "welcome to code jam." After solving this problem, we hope that you'll feel very welcome. Very welcome, that is, to code jam.
If you read the previous paragraph, you're probably wondering why it's there. But if you read it very carefully, you might notice that we have written the words "welcome to code jam" several times: 400263727 times in total. After all, it's easy to look through the paragraph and find a 'w'; then find an 'e' later in the paragraph; then find an 'l' after that, and so on. Your task is to write a program that can take any text and print out how many times that text contains the phrase "welcome to code jam".
To be more precise, given a text string, you are to determine how many times the string "welcome to code jam" appears as a sub-sequence of that string. In other words, find a sequence s of increasing indices into the input string such that the concatenation of input[s[0]], input[s[1]], ..., input[s[18]] is the string "welcome to code jam".
The result of your calculation might be huge, so for convenience we would only like you to find the last 4 digits.
Input
The first line of input gives the number of test cases, N. The next N lines of input contain one test case each. Each test case is a single line of text, containing only lower-case letters and spaces. No line will start with a space, and no line will end with a space.
Output
For each test case, "Case #x: dddd", where x is the case number, and dddd is the last four digits of the answer. If the answer has fewer than 4 digits, please add zeroes at the front of your answer to make it exactly 4 digits long.
Limits
1 ≤ N ≤ 100
Small dataset
Each line will be no longer than 30 characters.
Large dataset
Each line will be no longer than 500 characters.
Sample
Input |
Output |
3 |
Case #1: 0001 |
Solution (For small dataset only):
string welcome = string("welcome to code jam");
int tc = ;
int fo[], cp[];
string input;
int inlen; void radd(int begin_chr, int last_pos) {
if (begin_chr > ) return; int cp = fo[begin_chr];
if (last_pos > cp) cp = last_pos; while (cp < inlen) {
if (input[cp] == welcome[begin_chr]) {
if(begin_chr == ) {
tc++;
if (tc == ) tc = ;
} radd(begin_chr + , cp);
} cp++;
} return;
} int solve()
{ int wlen = ;
inlen = (int)input.length(); tc = ; for (int wi = ; wi < wlen; wi++) {
char chr = welcome[wi];
bool found = false;
for (int ii = wi; ii < inlen; ii++) {
if (chr == input[ii]) {
fo[wi] = cp[wi] = ii;
found = true;
break;
}
}
if (!found)
return ;
} radd(, ); return tc;
} int main()
{
freopen("in.in", "r", stdin);
freopen("out.out", "w", stdout); int T;
scanf("%d\n", &T);
if (!T) {
cerr << "Check input!" << endl;
exit();
} for (int t = ; t <= T; t++) {
cerr << "solving: #" << t << " / " << T << endl; getline(cin, input); auto result = solve();
printf("Case #%d: %04d\n", t, result);
} fclose(stdin);
fclose(stdout);
return ;
}
Google Code Jam 2009 Qualification Round Problem C. Welcome to Code Jam的更多相关文章
- Google Code Jam 2009 Qualification Round Problem B. Watersheds
https://code.google.com/codejam/contest/90101/dashboard#s=p1 Problem Geologists sometimes divide an ...
- Google Code Jam 2009 Qualification Round Problem A. Alien Language
https://code.google.com/codejam/contest/90101/dashboard#s=p0 Problem After years of study, scientist ...
- Google Code Jam Africa 2010 Qualification Round Problem B. Reverse Words
Google Code Jam Africa 2010 Qualification Round Problem B. Reverse Words https://code.google.com/cod ...
- Google Code Jam Africa 2010 Qualification Round Problem A. Store Credit
Google Code Jam Qualification Round Africa 2010 Problem A. Store Credit https://code.google.com/code ...
- [C++]Infinite House of Pancakes——Google Code Jam 2015 Qualification Round
Problem It’s opening night at the opera, and your friend is the prima donna (the lead female singer) ...
- [C++]Standing Ovation——Google Code Jam 2015 Qualification Round
Problem It’s opening night at the opera, and your friend is the prima donna (the lead female singer) ...
- Google APAC----Africa 2010, Qualification Round(Problem C. T9 Spelling)----Perl 解法
原题地址链接:https://code.google.com/codejam/contest/351101/dashboard#s=p2 问题描述: Problem The Latin alphabe ...
- Google APAC----Africa 2010, Qualification Round(Problem B. Reverse Words)----Perl 解法
原题地址链接:https://code.google.com/codejam/contest/351101/dashboard#s=p1 问题描述: Problem Given a list of s ...
- Google APAC----Africa 2010, Qualification Round(Problem A. Store Credit)----Perl 解法
原题地址链接:https://code.google.com/codejam/contest/351101/dashboard#s=p0 问题描述: Problem You receive a cre ...
随机推荐
- Html form 表单提交前验证
可以使用form表单的onsubmit方法,在提交表单之前,对表单或者网页中的数据进行检验. onsubmit指定的方法返回true,则提交数据:返回false不提交数据. 直接看下面的代码: 1 & ...
- oracle10G/11G官方下载地址集合 直接迅雷下载
Oracle Database 11g Release 2 (11.2.0.1.0) for Microsoft Windows (64-bit) http://download.oracle.c ...
- MySQL数据丢失情况分析
一.存储引擎层面丢失数据 由于在实际项目中,我们往往使用支持事务的InnoDB存储引擎.我们 ...
- Greedy:Yogurt factory(POJ 2393)
酸奶工厂 题目大意:酸奶工厂每个星期都要制造酸奶,成本每单位x,然后每个星期要生产y,然后酸奶厂有个巨大的储存室,可以无限储存酸奶,而且酸奶的品质不会变坏,每天储存要每单位花费S,求最小的成本. 简直 ...
- javaScript中利用ActiveXObject来创建FileSystemObject操作文件
注:如果用javascript读本地文件,遇到安全问题. 需在浏览器中进行设置,如下: 工具—> Internet选项->安全->自定义级别->启用“没有标识为安全的A ...
- 解决页面插入HTML代码后错位(HTML代码里的标签不完整导致错位)
这个的例子是从数据库读取出来的数据内容包含HTML导致页面错位问题! 解决办法如下: 首先过滤掉会跟JS冲突的字符,C#代码如下: string htmlc = Model.HtmlContents. ...
- Linux创建用户并赋予Root权限
添加普通用户 [root@server ~]# useradd test //添加一个名为test的用户[root@server ~]# passwd test //修改密码Changing pass ...
- mysql中char,varchar,text区别总结
具体对这三种类型的说明不做阐述可以查看mysql帮助文档. char的总结: char最大长度是255字符,注意是字符数和字符集没关系.可以有默认值,尾部有空格会被截断.varchar的总结 ...
- javascript集合的交,并,补,子集的操作实现
可能新的ECMA规范里已有了这些的实现, 但能自己从头开始实现,感觉也非常不错的哟... function Set() { var items = {}; this.has = function(va ...
- js 事件监听 兼容浏览器
js 事件监听 兼容浏览器 ie 用 attachEvent w3c(firefox/chrome) 用 addEventListener 删除事件监听 ie 用 detachEven ...