HDU 4696 Answers （2013多校10,1001题 ）

Answers

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)
Total Submission(s): 25    Accepted Submission(s): 16

Problem Description

 

Sample Input

2 4
2 2
2 1
0 1 2 3

 

Sample Output

NO
YES
YES
YES

 

Source

2013 Multi-University Training Contest 10

 

Recommend

zhuyuanchen520

 

分容易发现规律。

如果M<=0 肯定不行。

如果没有1，只能弄出偶数。

其余都可以

 /* ***********************************************
 Author        :kuangbin
 Created Time  :2013/8/22 13:25:04
 File Name     :F:\2013ACM练习\2013多校10\1001.cpp
 ************************************************ */
 
 #include <stdio.h>
 #include <string.h>
 #include <iostream>
 #include <algorithm>
 #include <vector>
 #include <queue>
 #include <set>
 #include <map>
 #include <string>
 #include <math.h>
 #include <stdlib.h>
 #include <time.h>
 using namespace std;
 const int MAXN = ;
 int T[MAXN],C[MAXN];
 int M;
 int main()
 {
     //freopen("in.txt","r",stdin);
     //freopen("out.txt","w",stdout);
     int N,Q;
     while(scanf("%d%d",&N,&Q) == )
     {
         for(int i = ;i <= N;i++)
             scanf("%d",&T[i]);
         bool flag = false;
         for(int i = ;i <= N;i++)
         {
             scanf("%d",&C[i]);
             if(C[i] == )
                 flag = true;
         }
         while(Q--)
         {
             scanf("%d",&M);
             if(M <= )
                 printf("NO\n");
             else
             {
                 if(flag)printf("YES\n");
                 else if(M%)printf("NO\n");
                 else printf("YES\n");
             }
         }
     }
     return ;
 }