219. Insert Node in Sorted Linked List【Naive】
Insert a node in a sorted linked list.
Given list = 1->4->6->8
and val = 5
.
Return 1->4->5->6->8
.
解法一:
/**
* Definition of ListNode
* class ListNode {
* public:
* int val;
* ListNode *next;
* ListNode(int val) {
* this->val = val;
* this->next = NULL;
* }
* }
*/ class Solution {
public:
/*
* @param head: The head of linked list.
* @param val: An integer.
* @return: The head of new linked list.
*/
ListNode * insertNode(ListNode * head, int val) {
ListNode * new_node = new ListNode(val);
if (head == NULL) {
return new_node;
} ListNode * dummy = new ListNode(-);
dummy->next = head;
head = dummy; while (head->next != NULL) {
if (val > head->next->val) {
head = head->next;
} else {
new_node->next = head->next;
head->next = new_node;
break;
}
} if (head->next == NULL) {
head->next = new_node;
} return dummy->next;
}
};
经典的构造dummy头节点问题
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