Description

Sheryl works for a software company in the country of Brada. Her job is to develop a Windows operating system. People in Brada are incredibly conservative. They even never use graphical monitors! So Sheryl’s operating system has to run in text mode and windows in that system are formed by characters. Sheryl decides that every window has an ID which is a capital English letter (‘A’ to ‘Z’). Because every window had a unique ID, there can’t be more than 26 windows at the same time. And as you know, all windows are rectangular. 
On the screen of that ugly Windows system, a window’s frame is formed by its ID letters. Fig-1 shows that there is only one window on the screen, and that window’s ID is ‘A’. Windows may overlap. Fig-2 shows the situation that window B is on the top of window A. And Fig-3 gives a more complicated overlapping. Of course, if some parts of a window are covered by other windows, you can’t see those parts on the screen. 
.........................  ....AAAAAAAAAAAAA........  ....A...........A........  ....A...........A........  ....A...........A........  ....AAAAAAAAAAAAA........  ......................... 
Fig-1 
.........................  ....AAAAAAAAAAAAA........  ....A...........A........  ....A.......BBBBBBBBBB...  ....A.......B........B...  ....AAAAAAAAB........B...  ............BBBBBBBBBB...  ......................... 
Fig-2

..........................  ....AAAAAAAAAAAAA.........  ....A...........A.........  ....A.......BBBBBBBBBB....  ....A.......B........BCCC.  ....AAAAAAAAB........B..C.  .......C....BBBBBBBBBB..C.  .......CCCCCCCCCCCCCCCCCC.  .......................... 
Fig-3 
If a window has no parts covered by other windows, we call it a “top window” (The frame is also considered as a part of a window). Usually, the top windows are the windows that interact with user most frequently. Assigning top windows more CPU time and higher priority will result in better user experiences. Given the screen presented as Figs above, can you tell Sheryl which windows are top windows? 

 

Input

The input contains several test cases. 
Each test case begins with two integers, n and m (1 <= n, m <= 100), indicating that the screen has n lines, and each line consists of m characters. 
The following n lines describe the whole screen you see. Each line contains m characters. For characters which are not on any window frame, we just replace them with ‘.’ . 
The input ends with a line of two zeros. 
It is guaranteed that: 
1) There is at least one window on the screen.  2) Any window’s frame is at least 3 characters wide and 3 characters high.  3) No part of any window is outside the screen. 
 

Output

For each test case, output the IDs of all top windows in a line without blanks and in alphabet order. 

题目大意:给一个n*m的矩阵,每一个字母代表一个窗口的边框,问那些窗口在最顶端(这题太难描述了不管了……)

思路:这题数据范围很小,就不用那些很难写但速度可能比较快的算法了,因为是水题写得快和准更重要。首先枚举每一个字母,找出每一个字母最大和最小的x、y坐标,检查一下这个字母的窗口边框是不是都是那个字母,再检查一下这个窗口里面有没有被其他奇怪的东西覆盖(就是都要是'.'),就能AC了。

PS:把一个max_y打成了max_x又WA了一个>_<

代码(0MS):

 #include <cstdio>
#include <iostream>
#include <algorithm>
#include <cstring>
using namespace std; const int MAX = ; char mat[MAX][MAX];
int n, m; bool top(char c) {
int max_x = , min_x = MAX, max_y = , min_y = MAX;
for(int i = ; i <= n; ++i) {
for(int j = ; j <= m; ++j) {
if(mat[i][j] != c) continue;
max_x = max(max_x, j);
min_x = min(min_x, j);
max_y = max(max_y, i);
min_y = min(min_y, i);
}
}
if(max_x - min_x < || max_y - min_y < ) return false;
for(int i = min_y; i <= max_y; ++i)
if(mat[i][max_x] != c || mat[i][min_x] != c) return false;
for(int i = min_x; i <= max_x; ++i)
if(mat[max_y][i] != c || mat[min_y][i] != c) return false;
for(int i = min_y + ; i < max_y; ++i) {
for(int j = min_x + ; j < max_x; ++j)
if(mat[i][j] != '.') return false;
}
return true;
} int main() {
while(scanf("%d%d", &n, &m) != EOF) {
if(n == && m == ) break;
for(int i = ; i <= n; ++i) scanf("%s", &mat[i][]);
for(char c = 'A'; c <= 'Z'; ++c)
if(top(c)) printf("%c", c);
puts("");
}
}

HDU 2487 Ugly Windows(暴力)(2008 Asia Regional Beijing)的更多相关文章

  1. POJ 3923 HDU 2487 Ugly Windows 简单计算

    Ugly Windows Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Tot ...

  2. HDU 2489 Minimal Ratio Tree(暴力+最小生成树)(2008 Asia Regional Beijing)

    Description For a tree, which nodes and edges are all weighted, the ratio of it is calculated accord ...

  3. HDU 2494/POJ 3930 Elevator(模拟)(2008 Asia Regional Beijing)

    Description Too worrying about the house price bubble, poor Mike sold his house and rent an apartmen ...

  4. HDU 2487 Ugly Windows

    递归求解,代码不太好看,是2013年7月写的 代码: #include<stdio.h> #include<iostream> #include<string.h> ...

  5. HDU 2490 Parade(DPの单调队列)(2008 Asia Regional Beijing)

    Description Panagola, The Lord of city F likes to parade very much. He always inspects his city in h ...

  6. HDU 2492 Ping pong(数学+树状数组)(2008 Asia Regional Beijing)

    Description N(3<=N<=20000) ping pong players live along a west-east street(consider the street ...

  7. HDU 2491 Priest John's Busiest Day(贪心)(2008 Asia Regional Beijing)

    Description John is the only priest in his town. October 26th is the John's busiest day in a year be ...

  8. (并查集)Travel -- hdu -- 5441(2015 ACM/ICPC Asia Regional Changchun Online )

    http://acm.hdu.edu.cn/showproblem.php?pid=5441 Travel Time Limit: 1500/1000 MS (Java/Others)    Memo ...

  9. (二叉树)Elven Postman -- HDU -- 54444(2015 ACM/ICPC Asia Regional Changchun Online)

    http://acm.hdu.edu.cn/showproblem.php?pid=5444 Elven Postman Time Limit: 1500/1000 MS (Java/Others)  ...

随机推荐

  1. js浮点型,整型操作方法汇总(进行中)

    浮点数操作方法如下: 1. Math.ceil()用作向上取整.(ceil 天花板) 2. Math.floor()用作向下取整. (floor 地板) (js 中取整底层原理是位运算的取反~运算,运 ...

  2. 关于端口冲突的解决方式Error: listen EACCES 0.0.0.80

    笔者昨天下午临走前安装了vs 2017想要运行一下项目的NET后端来让本机的前端直接对接后端,但是没注意到运行vs后IIS直接占用了本机的80端口.第二天跑nodeJS的时候直接Error: list ...

  3. [SHELL]软件管理

  4. 利用clear清除浮动的一些问题

    下面这段代码是用来清除浮动带来的高度塌陷问题 .clearfix:before { content: "."; display: block; height: 0; clear: ...

  5. obfuscator-llvm Theos 集成配置

    之前我写过一篇文章是关于在 Xcode 里怎么集成配置 obfuscator-llvmobfuscator-llvm Xcode集成配置 有些情况下我们使用 Theos 开发 tweak,需要将 ob ...

  6. 【tp5.1】通过PHPExcel实现导入excel表格

    1.上github下载PHPExcel,链接:https://github.com/PHPOffice/PHPExcel 2.下载解压后,将Classes改名为PHPExcel如图 3.将文件夹复制到 ...

  7. Cab 安装不成功问题

    使用 iexpress.exe 成功打包了cab文件. 可下面问题来了,用静态的html调用,提示安装. 确认安装之后,却提示找不到相应的*.ocx,导致无法安装文件到系统 分析具体原因:*.ocx ...

  8. Hive(6)-DML数据操作

    一. 数据导入 1. 语法 load data [local] inpath 'path' [overwrite] into table table_name [partition (partcol1 ...

  9. IA64与x86-64的区别

    win7 sp1下载地址:https://download.microsoft.com/download/0/A/F/0AFB5316-3062-494A-AB78-7FB0D4461357/wind ...

  10. c语言指针的指针

    c语言在函数传递时常常使用如下的形式. void get(int **p) 对于这个形式,我想过为什么不能够使用 *p 作为形参呢.下面我们看一下代码和执行结果 void get(int **p) { ...