Description

Find the first unique character in a given string. You can assume that there is at least one unique character in the string.

Example

For "abaccdeff", return 'b'.

解题:返回仅出现一次,并且排在最前面的那个元素,而不是返回第一个不同的元素,一开始理解错了。如果仅仅对于ASCII中的256个字符,可以用数组来保存每个元素出现的次数。而对于Unicode中的元素,最好用HashMap来做。代码如下:

 public class Solution {
/**
* @param str: str: the given string
* @return: char: the first unique character in a given string
*/
public char firstUniqChar(String str) {
// Write your code here
HashMap<Character, Integer>map = new HashMap<Character, Integer>();
for(int i = 0; i < str.length(); i++){
char temp = str.charAt(i);
if(map.containsKey(temp)){
map.put(temp, map.get(temp) + 1);
}else{
map.put(temp, 1);
}
}
for(int i = 0; i < str.length(); i++)
if(map.get(str.charAt(i)) == 1)
return str.charAt(i); return str.charAt(0); }
}

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