Problem Description

The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter'e'. He was a member of the Oulipo group. A quote from the book:

Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…

Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces.

So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A''B''C', …,'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.

Input

The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:

  • One line with the word W, a string over {'A''B''C', …, 'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
  • One line with the text T, a string over {'A''B''C', …, 'Z'}, with |W| ≤ |T| ≤ 1,000,000.

Output

For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T.

Sample Input

3
BAPC
BAPC
AZA
AZAZAZA
VERDI
AVERDXIVYERDIAN

Sample Output

1

题意:

给出T组数据,每组数据有两个字符串,让我们查找第一个字符串在第二个字符串中出现的次数,可重叠;

思路:kmp;

注意:使用C++中cin、cout作为输入输出语句将导致超时,也是怪坑的

具体代码如下:

#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
#define maxx 2000100
char a[maxx],b[];
int n,m;
int p[maxx];
void pre()
{
int i=,j=-;
p[]=-;
while(i<m)
{
if(j==-||b[i]==b[j])
{
j++,i++;
p[i]=j;
}
else
j=p[j];
}
}
void kmp()
{
int i=,j=,ans=;
while(i<n)
{
if(j==-||a[i]==b[j])
{
i++,j++;
if(j==m)
{
ans++;
j=p[j];
}
}
else
j=p[j];
}
printf("%d\n",ans);
}
int main()
{
int t;
scanf("%d",&t);
while(t--)
{
scanf("%s%s",b,a);
n=strlen(a);//
m=strlen(b);
pre();
kmp();
}
return ;
}

下面来一道求不重叠部分的题目

剪花布条 HDU - 2087(kmp,求不重叠匹配个数)

Oulipo POJ - 3461(kmp,求重叠匹配个数)的更多相关文章

  1. 剪花布条 HDU - 2087(kmp,求不重叠匹配个数)

    Problem Description 一块花布条,里面有些图案,另有一块直接可用的小饰条,里面也有一些图案.对于给定的花布条和小饰条,计算一下能从花布条中尽可能剪出几块小饰条来呢? Input 输入 ...

  2. HDU 1686 Oulipo / POJ 3461 Oulipo / SCU 2652 Oulipo (字符串匹配,KMP)

    HDU 1686 Oulipo / POJ 3461 Oulipo / SCU 2652 Oulipo (字符串匹配,KMP) Description The French author George ...

  3. POJ 3978 Primes(求范围素数个数)

    POJ 3978 Primes(求范围素数个数) id=3978">http://poj.org/problem? id=3978 题意: 给你一个区间范围A和B,要你求出[A,B]内 ...

  4. (KMP)Oulipo -- poj --3461

    http://acm.hust.edu.cn/vjudge/contest/view.action?cid=92486#problem/B http://poj.org/problem?id=3461 ...

  5. Match:Oulipo(POJ 3461)

     Oulipo 题目大意:给你一个字符串,要你找到字符串包含指定子串的个数 只要你知道了KMP,这一题简直不要太简单,注意STL的string是会超时的,还是乖乖用char吧 #include < ...

  6. POJ 3461 kmp 应用

    题意:求匹配串在文本中出现次数,KMP应用,理解了就OK了,每次匹配成功就累加次数,开始的时候超时, 由于在处理每次成功的时候让i=i-len2+1,相当于回溯了,后来一想,本次成功,相当于" ...

  7. AC日记——Oulipo poj 3461

    Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 37958   Accepted: 15282 Description The ...

  8. POJ 3461 kmp

    Oulipo Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 40168   Accepted: 16135 Descript ...

  9. POJ 2752 (kmp求所有公共前后缀长度)

    <题目链接> <转载于> 题目大意:  给出一个字符串str,求出str中存在多少子串,使得这些子串既是str的前缀,又是str的后缀.从小到大依次输出这些子串的长度.即输出该 ...

随机推荐

  1. Dubbo——配置

    一.配置原则 JVM 启动 -D 参数优先,这样可以使用户在部署和启动时进行参数重写,比如在启动时需改变协议的端口. XML 次之,如果在 XML 中有配置,则 dubbo.properties 中的 ...

  2. 数据分析之matplotlib使用

    绘制折线图 参数详情 from matplotlib import pyplot as plt # 设置图片大小,dpi图片放大缩小时可以让其更清晰 plt.figure(figsize=(20,8) ...

  3. ROS indigo下Kinect v1的驱动安装与调试

    ROS indigo下Kinect v1的驱动安装与调试 本文简要叙述了在ROS indigo版本下Kinect v1的驱动安装与调试过程. 1. 实验环境 (1)硬件:  台式机和Kinect v1 ...

  4. DQL:查询表中数据

    1. 基础查询 (1) 查询整表 SELECT * FROM 表名; -- 不推荐使用"*",不方便阅读 (2) 选择性查询 SELECT 列名,列名,列名 FROM 表名; (3 ...

  5. Maven的New中没有Servlet问题(IDEA)

    1.问题 第一次使用Maven骨架创建Web项目的时候,遇到了 New 里面没有 servlet 的问题. 2.原因 经过查询,是因为IDEA检测到项目中没有导入相关的 jar 包导致. 3.解决方法 ...

  6. SpringBoot2.0 Actuator 监控参数说明

    主要内容更 监控参数说明 Maven坐标 <dependency> <groupId>org.springframework.boot</groupId> < ...

  7. [Oracle]察看一张表的约束 和 察看一张表的索引

    --察看一张表的约束select table_name,constraint_name,constraint_type from user_constraints where table_name=u ...

  8. as 什么意思?

    You can denote particular console messages and variable values as having different types using four ...

  9. Kinect关节数据

    3 -0.118269 0.655295 1.7431 930.03 139.5962 -0.124249 0.506111 1.79473 926.387 239.42820 -0.122777 0 ...

  10. 查看oracle数据库的链接数和用户

    http://www.cnblogs.com/is1988/archive/2012/11/21/2780067.html 1.查询oracle的连接数select count(*) from v$s ...