Problem Description

The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter'e'. He was a member of the Oulipo group. A quote from the book:

Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…

Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces.

So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A''B''C', …,'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.

Input

The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:

  • One line with the word W, a string over {'A''B''C', …, 'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
  • One line with the text T, a string over {'A''B''C', …, 'Z'}, with |W| ≤ |T| ≤ 1,000,000.

Output

For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T.

Sample Input

3
BAPC
BAPC
AZA
AZAZAZA
VERDI
AVERDXIVYERDIAN

Sample Output

1

题意:

给出T组数据,每组数据有两个字符串,让我们查找第一个字符串在第二个字符串中出现的次数,可重叠;

思路:kmp;

注意:使用C++中cin、cout作为输入输出语句将导致超时,也是怪坑的

具体代码如下:

#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
#define maxx 2000100
char a[maxx],b[];
int n,m;
int p[maxx];
void pre()
{
int i=,j=-;
p[]=-;
while(i<m)
{
if(j==-||b[i]==b[j])
{
j++,i++;
p[i]=j;
}
else
j=p[j];
}
}
void kmp()
{
int i=,j=,ans=;
while(i<n)
{
if(j==-||a[i]==b[j])
{
i++,j++;
if(j==m)
{
ans++;
j=p[j];
}
}
else
j=p[j];
}
printf("%d\n",ans);
}
int main()
{
int t;
scanf("%d",&t);
while(t--)
{
scanf("%s%s",b,a);
n=strlen(a);//
m=strlen(b);
pre();
kmp();
}
return ;
}

下面来一道求不重叠部分的题目

剪花布条 HDU - 2087(kmp,求不重叠匹配个数)

Oulipo POJ - 3461(kmp,求重叠匹配个数)的更多相关文章

  1. 剪花布条 HDU - 2087(kmp,求不重叠匹配个数)

    Problem Description 一块花布条,里面有些图案,另有一块直接可用的小饰条,里面也有一些图案.对于给定的花布条和小饰条,计算一下能从花布条中尽可能剪出几块小饰条来呢? Input 输入 ...

  2. HDU 1686 Oulipo / POJ 3461 Oulipo / SCU 2652 Oulipo (字符串匹配,KMP)

    HDU 1686 Oulipo / POJ 3461 Oulipo / SCU 2652 Oulipo (字符串匹配,KMP) Description The French author George ...

  3. POJ 3978 Primes(求范围素数个数)

    POJ 3978 Primes(求范围素数个数) id=3978">http://poj.org/problem? id=3978 题意: 给你一个区间范围A和B,要你求出[A,B]内 ...

  4. (KMP)Oulipo -- poj --3461

    http://acm.hust.edu.cn/vjudge/contest/view.action?cid=92486#problem/B http://poj.org/problem?id=3461 ...

  5. Match:Oulipo(POJ 3461)

     Oulipo 题目大意:给你一个字符串,要你找到字符串包含指定子串的个数 只要你知道了KMP,这一题简直不要太简单,注意STL的string是会超时的,还是乖乖用char吧 #include < ...

  6. POJ 3461 kmp 应用

    题意:求匹配串在文本中出现次数,KMP应用,理解了就OK了,每次匹配成功就累加次数,开始的时候超时, 由于在处理每次成功的时候让i=i-len2+1,相当于回溯了,后来一想,本次成功,相当于" ...

  7. AC日记——Oulipo poj 3461

    Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 37958   Accepted: 15282 Description The ...

  8. POJ 3461 kmp

    Oulipo Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 40168   Accepted: 16135 Descript ...

  9. POJ 2752 (kmp求所有公共前后缀长度)

    <题目链接> <转载于> 题目大意:  给出一个字符串str,求出str中存在多少子串,使得这些子串既是str的前缀,又是str的后缀.从小到大依次输出这些子串的长度.即输出该 ...

随机推荐

  1. array_merge与array+array的区别

    结果:

  2. Echarts——关系图(人民的名义为例,简化)源码

    参考博文:https://www.cnblogs.com/emrys5/p/echart-relationship-map.html <!DOCTYPE html> <html> ...

  3. java试题复盘——11月13日

    上: 10. AccessViolationException异常触发后,下列程序的输出结果为(   A   ) 1 2 3 4 5 6 7 8 9 10 11 12 13 14 AccessViol ...

  4. PHP 之实现按日期进行分组、分页

    一.效果图 二.原始数据 array(6) { [0]=> array(8) { ["id"]=> string(1) "6" ["use ...

  5. python3 django连接mysql数据库

    在django中将模型类中的数据迁移到mysql数据库中,首先使用pip install pymysql安装pymysql库, 然后在项目中的__init__.py中添加 import pymysql ...

  6. PHP学习之文件上传类

    <?php $up = new Upload(); $newPath = $up->uploadFile('fm'); if ($newPath === false) { var_dump ...

  7. python 获取昨天的日期

    from datetime import timedelta, datetime yesterday = datetime.today()+timedelta(-1) yesterday_format ...

  8. 08ListView动态列表组件 以及循环动态数据

    效果: main.dart import 'package:flutter/material.dart'; import 'res/listData.dart'; /* ListView:参数 scr ...

  9. 一百三十一:CMS系统之轮播图上传图片功能

    将七牛js放到common下 把获取uptoken的接口放到common视图中 把初始化七牛放到banners.js中 //初始化七牛$(function () { qiniujs.setUp({ ' ...

  10. HDFS数据定期清理

    HDFS数据清理一些办法: datanode数据做reblance清理临时目录.日志目录文件全量分区表历史分区清理使用lzo,orc格式进行数据压缩清理或者归档历史冷数据增加datanode横向扩容附 ...