62. Unique Paths

A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below).

The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in the diagram below).

How many possible unique paths are there?

Above is a 3 x 7 grid. How many possible unique paths are there?

Note: m and n will be at most 100.

Tips:机器人从左上一直走到右下,(只能走右与下)直到走到FInish的位置。

package medium;

import java.util.Arrays;

public class L62UniquePaths {
public int uniquePaths(int m, int n) {
int[][] visited = new int[m][n];
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
visited[i][j] = -1;
System.out.println(i + "," + j + ">" + visited[i][j]);
}
}
int count = movingCount(m, n, 0, 0, visited);
return count;
}
public int movingCount(int m, int n, int row, int col, int[][] visited) {
int count = 0;
if (row < 0 || col < 0 || row >= m || col >= n)
return 0;
if (row == m - 1 && col == n - 1)
return 1;
if (visited[row][col] != -1)
return visited[row][col];
count = movingCount(m, n, row + 1, col, visited) + movingCount(m, n, row, col + 1, visited);
visited[row][col] = count;
return count;
} //另外一种很快地方法。当前状态依赖于前一种状态
public int Solution2(int m, int n) {
int[] row = new int[n];
Arrays.fill(row,1);
for (int i = 1; i < m; i++) {
for (int j = 1; j < n; j++) {
row[j]+=row[j-1];
}
}
return row[n-1];
} public static void main(String[] args) {
L62UniquePaths cc = new L62UniquePaths();
int count = cc.uniquePaths(3, 4);
System.out.println(count);
}
}

 63. Unique Paths II

Follow up for "Unique Paths":

Now consider if some obstacles are added to the grids. How many unique paths would there be?

An obstacle and empty space is marked as 1 and 0 respectively in the grid.

For example,

There is one obstacle in the middle of a 3x3 grid as illustrated below.

[
[0,0,0],
[0,1,0],
[0,0,0]
]

The total number of unique paths is 2.

Note: m and n will be at most 100.

Tips:本题目是根据62题,稍作改变得来的,数组中1的位置不能走。

package medium;

public class L63UniquePaths2 {

	public int uniquePathsWithObstacles(int[][] obstacleGrid) {
if (obstacleGrid == null)
return 0;
int m = obstacleGrid.length;
int n = obstacleGrid[0].length;
int[][] visited = new int[m][n];
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
visited[i][j] = -1;
System.out.println(i + "," + j + ">" + visited[i][j]);
}
}
int count = movingCount(m, n, 0, 0, visited, obstacleGrid);
return count; } public int movingCount(int m, int n, int row, int col, int[][] visited, int[][] obstacleGrid) {
int count = 0;
if (row < 0 || col < 0 || row >= m || col >= n)
return 0;
if (obstacleGrid[row][col] == 0) {
if (row == m - 1 && col == n - 1)
return 1;
if (visited[row][col] != -1)
return visited[row][col];
count = movingCount(m, n, row + 1, col, visited, obstacleGrid)
+ movingCount(m, n, row, col + 1, visited, obstacleGrid);
visited[row][col] = count;
} return count;
} public static void main(String[] args) {
L63UniquePaths2 l63 = new L63UniquePaths2();
int[][] obstacleGrid = { { 0, 0, 0 }, { 0, 1, 0 }, { 0, 0, 0 } };
int[][] aa = { { 1 } };
int count = l63.uniquePathsWithObstacles(aa);
System.out.println(count); }
}

【leetcode】62.63 Unique Paths的更多相关文章

  1. &lt;LeetCode OJ&gt; 62. / 63. Unique Paths(I / II)

    62. Unique Paths My Submissions Question Total Accepted: 75227 Total Submissions: 214539 Difficulty: ...

  2. 【LeetCode】62. Unique Paths 解题报告(Python & C++)

    作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/unique-pa ...

  3. 【LeetCode】62. Unique Paths

    Unique Paths A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagra ...

  4. 【leetcode】62. Uniqe Paths

    题目 https://oj.leetcode.com/problems/unique-paths/   A robot is located at the top-left corner of a m ...

  5. 【LeetCode】387. First Unique Character in a String

    Difficulty:easy  More:[目录]LeetCode Java实现 Description https://leetcode.com/problems/first-unique-cha ...

  6. 62. 63. Unique Paths 64. Minimum Path Sum

    1. A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). ...

  7. LeetCode(62)Unique Paths

    题目 A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below). ...

  8. leetcode@ [62/63] Unique Paths II

    class Solution { public: int uniquePathsWithObstacles(vector<vector<int>>& obstacleG ...

  9. 【LeetCode】257. Binary Tree Paths 解题报告(java & python)

    作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 迭代 日期 题目地址:https://leet ...

随机推荐

  1. (数据科学学习手札51)用pymysql来操控MySQL数据库

    一.简介 pymysql是Python中专门用来操控MySQL数据库的模块,通过pymysql,可以编写简短的脚本来方便快捷地操控MySQL数据库,本文就将针对pymysql的基本功能进行介绍: 二. ...

  2. Noip 2016 Day 1 & Day 2

    Day 1 >>> T1 >> 水题直接模拟AC: 考察三个知识点:1.你能不能编程 2.你会不会取模 3.你脑子抽不抽 然而第一次评测还是90,因为当模运算时 “ en ...

  3. browser storage limation

    http://www.html5rocks.com/en/tutorials/offline/quota-research/?redirect_from_locale=zh

  4. 【课堂实践】Myod和Mycp

    实验内容 编写MyOD.java 用java MyOD XXX实现Linux下od -tx -tc XXX的功能 实验代码 od.java 截图 遇到的问题及解决办法 一开始想的方向是将得出的功能结果 ...

  5. 20145234黄斐《Java程序设计》第九周

    教材学习内容总结 整合数据库 JDBC入门 JDBC是用于执行SQL的解决方案,开发人员使用JDBC的标准接口,数据库厂商则对接口进行操作,开发人员无须接触底层数据库驱动程序的差异性,数据库本身是个独 ...

  6. 考研编程练习----swap

    void swap(int a ,int b) { a^=b; b^=a;  //b =b^a^b //b = b^b^a;//b = a;  按位异或满足交换律 a^=b; //a = a^b^a ...

  7. 【SQLSERVER】递归查询算法实例

    一.递归查询 1.结构: 递归CTE最少包含两个查询(也被称为成员). 第一个查询为定点成员,定点成员只是一个返回有效表的查询,用于递归的基础或定位点. 第二个查询被称为递归成员,使该查询称为递归成员 ...

  8. OpenCV参考手册之Mat类详解

    OpenCV参考手册之Mat类详解(一) OpenCV参考手册之Mat类详解(二) OpenCV参考手册之Mat类详解(三)

  9. JS基础,相亲,逻辑训练

    简单逻辑 <script> var a = prompt("有房么?"); // if(a == "有") { alert("结婚吧&qu ...

  10. python全栈开发-前方高能-函数进阶

    python_day_10 一.今日主要内容 1. 动态参数 位置参数的动态参数: *args 关键字参数的动态参数 : **kwargs 顺序: 位置,*args,默认值,**kwargs 在形参上 ...