这个异常的出现往往是因为非法使用了某些方法引起的。

从字面意思上是说这个特定的child已经有一个parent了,你必须在这个parent中首先调用removeView()方法,才能继续你的内容。这里很明显这个child是一个View,一个子(child)View必须依赖于父(parent)View,如果你要使用这个child,则必须通过parent,而你如果就是硬想使用这个child,那么就得让这个child与parent脱离父子关系(即removeView())

何时会出现这种异常呢,典型的是在使用Fragment的时候,在Fragment的onCreateView中有这样一段代码:

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@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
        Bundle savedInstanceState) {
    LinearLayout drawerListViewContainer = (LinearLayout) inflater.inflate(
            R.layout.fragment_navigation_drawer, container, false);
    mDrawerListView = (ListView)drawerListViewContainer.findViewById(R.id.drawer_list);
    mDrawerListView
            .setOnItemClickListener(new AdapterView.OnItemClickListener() {
                @Override
                public void onItemClick(AdapterView<?> parent, View view,
                        int position, long id) {
                    selectItem(position);
                }
            });
                                                                                                                                                                                                                                                                                                                                                                                                                                                                        
    SimpleAdapter mDrawerAdapter =  new SimpleAdapter(getActivity(),getDrawerItems(),R.layout.drawer_item,new String[]{"img","title"},new int[]{R.id.item_icon,R.id.item_name});
    mDrawerListView.setAdapter(mDrawerAdapter);
    mDrawerListView.setItemChecked(mCurrentSelectedPosition, true);
    return mDrawerListView;
}

这段代码运行之后即会报出这样的错误

这是因为,返回的mDrawerListView他有一个parent,正确的做法是返回drawerListViewContainer,其实这也是我的本意,因为大意才写成了返回mDrawerListView

不过仔细想想,为什么就不能返回mDrawerListView呢,都是view 没有本质区别啊,这还得看出现这个异常信息的地方发生了什么事,从上面的log中我们知道这个异常产生在ViewGroup的addViewInner方法中。addViewInner的代码如下(部分):

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    private void addViewInner(View child, int index, LayoutParams params,
            boolean preventRequestLayout) {
        if (mTransition != null) {
            // Don't prevent other add transitions from completing, but cancel remove
            // transitions to let them complete the process before we add to the container
            mTransition.cancel(LayoutTransition.DISAPPEARING);
        }
        if (child.getParent() != null) {
            throw new IllegalStateException("The specified child already has a parent. " +
                    "You must call removeView() on the child's parent first.");
        }
......

原来在addViewInner中判断了child的parentview 必须为null,否则抛出一个异常。 也就是框架的设计者希望这里必须是一个没有parent的view,如果你不这么做,那么只好给你抛出个异常了,强制这样做也许是为了防止某些问题产生。

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