请定义一个函数quadratic(a, b, c)，接收3个参数，返回一元二次方程 ax^2+bx+c=0ax 2 +bx+c=0 的两个解。

#!/usr/bin/python

# 导入math包

import math

def quadratic(a, b, c):

if not isinstance(a, (int, float))and isinstance(a, (int, float)) and isinstance(a, (int, float)):

raise TypeError('a or b or c must be a number')

dt = int(b) ** 2-(4*int(a)*int(c))

if a == 0:

if b == 0:

if c == 0:

return'all real number'

else:

return 'a can\'t be 0,该方程没有实数解'

else:

x1 = -c/b

x2 = x1

return x1, x2

else:

if dt < 0:

return '该方程没有实数解'

elif dt == 0:

x = -b/(2*a)

return x

else:

x3 = (-b+math.sqrt(dt))/(2*a)

x4 = (-b-math.sqrt(dt))/(2*a)

return x3, x4

a1 = input('a=',)

b1 = input('b=',)

c1 = input('c=',)

print('ax^2+bx+c=0的解为：', quadratic(a1, b1, c1))