poj 3468 线段树成段更新

A Simple Problem with Integers

Time Limit: 5000MS		Memory Limit: 131072K
Total Submissions: 54012		Accepted: 16223
Case Time Limit: 2000MS

Description

You have N integers, A₁, A₂, ... , A_N. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interval. The other is to ask for the sum of numbers in a given interval.

Input

The first line contains two numbers N and Q. 1 ≤ N,Q ≤ 100000.
The second line contains N numbers, the initial values of A₁, A₂, ... , A_N. -1000000000 ≤ A_i ≤ 1000000000.
Each of the next Q lines represents an operation.
"C a b c" means adding c to each of A_a, A_a+1, ... , A_b. -10000 ≤ c ≤ 10000.
"Q a b" means querying the sum of A_a, A_a+1, ... , A_b.

Output

You need to answer all Q commands in order. One answer in a line.

Sample Input

10 5
1 2 3 4 5 6 7 8 9 10
Q 4 4
Q 1 10
Q 2 4
C 3 6 3
Q 2 4

Sample Output

4
55
9
15

Hint

The sums may exceed the range of 32-bit integers.

 

#include<iostream>
#include<cstdio>
using namespace std;

#define lson left,mid,i<<1
#define rson mid+1,right,i<<1|1

typedef __int64 LL;
int a[];

struct IntervalTree
{
    int left,right;
    LL sum,add;
}f[];

void pushdown(int i)
{
    if(f[i].add != )
    {
        f[i<<].add+=f[i].add;
        f[i<<|].add+=f[i].add;
        f[i<<].sum+=(f[i<<].right-f[i<<].left+)*f[i].add;
        f[i<<|].sum+=(f[i<<|].right-f[i<<|].left+)*f[i].add;
        f[i].add=;
    }
}

void pushup(int i)
{
    f[i].sum=f[i<<].sum+f[i<<|].sum;
}

void bulid(int left,int right,int i)
{
    f[i].left=left,f[i].right=right,f[i].add=;
    if(left==right)
    {
        f[i].sum=a[left];return ;
    }
    int mid=(left+right)>>;
    bulid(lson);
    bulid(rson);
    pushup(i);
    return ;
}

void update(int left,int right,int add,int i)
{
    if(f[i].left==left && f[i].right==right)
    {
        f[i].add+=add;
        f[i].sum+=(right-left+)*add;
        return ;
    }
    pushdown(i);
    if(f[i<<].right>=right) update(left,right,add,i<<);
    else if(f[i<<|].left<=left) update(left,right,add,i<<|);
    else { update(left,f[i<<].right,add,i<<);update(f[i<<|].left,right,add,i<<|);}
    pushup(i);
    return ;
}

LL query(int left,int right,int i)
{
    if(f[i].left==left && f[i].right==right) return f[i].sum;
    pushdown(i);
    if(f[i<<].right>=right) return query(left,right,i<<);
    else if (f[i<<|].left<=left) return query(left,right,i<<|);
    else return query(left,f[i<<].right,i<<)+query(f[i<<|].left,right,i<<|);
}

int main()
{
    int i,n,m,ai,bi,d;
    char ch[];
    while(~scanf("%d %d",&n,&m))
    {
        for(i=;i<=n;i++) scanf("%d",a+i);
        bulid(,n,);
        while(m--)
        {
            scanf("%s",ch);
            if(strcmp(ch,"C")==)
            {
                scanf("%d %d %d",&ai,&bi,&d);
                update(ai,bi,d,);
            }
            else
            {
                scanf("%d %d",&ai,&bi);
                printf("%I64d\n",query(ai,bi,));
            }
        }
    }
    return ;
}