题意:

输入两个正整数N和M(N<=10000,M<=10000),接着输入N个正整数。输出最小的序列满足序列和为M。

AAAAAccepted code:

 #define HAVE_STRUCT_TIMESPEC
#include<bits/stdc++.h>
using namespace std;
int a[];
int dp[];
int vis[][];
int main(){
ios::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int n,m;
cin>>n>>m;
for(int i=;i<=n;++i)
cin>>a[i];
sort(a+,a++n);
for(int i=n;i;--i)
for(int j=m;j>=a[i];--j)
if(dp[j]<=dp[j-a[i]]+a[i]){
dp[j]=dp[j-a[i]]+a[i];
vis[i][j]=;
}
if(dp[m]<m)
cout<<"No Solution";
else{
int i=,j=m;
while(){
if(vis[i][j]){
cout<<a[i];
j-=a[i];
if(j)
cout<<" ";
}
++i;
if(!j)
break;
}
}
return ;
}

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