Linked List & List Node All In One

链表 & 节点

链表类型

  1. 单链表
  2. 双链表
  3. 环形链表 / 循环链表

Singly Linked List (Uni-directional)

Doubly Linked List (Bi-directional)

Circular Linked List

js 实现 Linked List


"use strict"; /**
*
* @author xgqfrms
* @license MIT
* @copyright xgqfrms
* @created 2020-11-17
* @modified
*
* @description 链表 & 节点
* @difficulty Easy Medium Hard
* @complexity O(n)
* @augments
* @example
* @link
* @solutions
*
* @best_solutions
*
*/ const log = console.log; // 节点
function ListNode(val, next) {
this.val = 0 || val;
this.next = null || next;
} // 链表
function LinkedList(value) {
const node = new ListNode(value, ``);
if(!head) {
head = node;
} else {
let current = head;
while(current.next) {
current = current.next;
}
current.next = node;
}
};
function LinkedList () {
// init & 闭包 closure
let length = 0;
let head = null;
// methods
this.append = function(value) {
const node = new ListNode(value, ``);
if(!head) {
head = node;
} else {
let current = head;
while(current.next) {
current = current.next;
}
current.next = node;
}
// log(`head =\n`, head)
length += 1;
}
this.getList = function() {
// log(`head =`, head)
return head;
}
} const test = new LinkedList(); test.append(1);
test.append(2);
// test.append(3); reverseList(test.getList()) /* head = ListNode { val: 1, next: ListNode { val: 2, next: ListNode { val: 3, next: '' } } }
*/

反转链表

https://leetcode.com/problems/reverse-linked-list/


/**
* Definition for singly-linked list.
* function ListNode(val) {
* this.val = val;
* this.next = null;
* }
*/
/**
* @param {ListNode} head
* @return {ListNode}
*/
var reverseList = function(head) {
let [prev, curr] = [null, head];
while (curr) {
let tmp = curr.next; // 1. 临时存储当前指针后续内容
curr.next = prev; // 2. 反转链表
prev = curr; // 3. 接收反转结果
curr = tmp; // 4. 接回临时存储的后续内容
}
return prev;
};

var reverseList = function(head) {
let [prev, curr] = [null, head];
while (curr) {
// swap
[curr.next, prev, curr] = [prev, curr, curr.next];
}
return prev;
};

refs

https://www.educative.io/edpresso/what-is-a-linked-list

https://people.engr.ncsu.edu/efg/210/s99/Notes/LinkedList.1.html

PPT

https://www.slideshare.net/sshinchan/single-linked-list



xgqfrms 2012-2020

www.cnblogs.com 发布文章使用:只允许注册用户才可以访问!


Linked List & List Node All In One的更多相关文章

  1. [LeetCode] Linked List Random Node 链表随机节点

    Given a singly linked list, return a random node's value from the linked list. Each node must have t ...

  2. Leetcode 382. Linked List Random Node

    本题可以用reservoir sampling来解决不明list长度的情况下平均概率选择元素的问题. 假设在[x_1,...,x_n]只选一个元素,要求每个元素被选中的概率都是1/n,但是n未知. 其 ...

  3. 382. Linked List Random Node

    Given a singly linked list, return a random node's value from the linked list. Each node must have t ...

  4. [Swift]LeetCode382. 链表随机节点 | Linked List Random Node

    Given a singly linked list, return a random node's value from the linked list. Each node must have t ...

  5. Reservoir Sampling-382. Linked List Random Node

    Given a singly linked list, return a random node's value from the linked list. Each node must have t ...

  6. [LeetCode] 382. Linked List Random Node ☆☆☆

    Given a singly linked list, return a random node's value from the linked list. Each node must have t ...

  7. Linked List Random Node -- LeetCode

    Given a singly linked list, return a random node's value from the linked list. Each node must have t ...

  8. [LeetCode] 382. Linked List Random Node 链表随机节点

    Given a singly linked list, return a random node's value from the linked list. Each node must have t ...

  9. 【LeetCode】382. Linked List Random Node 解题报告(Python & C++)

    作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 数组保存再随机选择 蓄水池抽样 日期 题目地址:ht ...

随机推荐

  1. moco框架实现重定向

    一.重定向到百度 1.代码 2.运行结果 因为没哟填写别的,浏览器输入路径: localhost:8888/redirect 点击回车,跳转到百度 二.跳转到自己的网站 1.代码 2.运行结果 输入准 ...

  2. 丢包 ICMP

    小结: 1.ICMP 常见网络丢包故障分析及处理 云极安 云极安 2019-12-25 我们在管理维护网络的过程中经常会遇到数据包丢失的现象.使用Ping命令进行连通性测试,则会发现Ping包延时远远 ...

  3. based on Greenlets (via Eventlet and Gevent) fork 孙子worker 比较 gevent不是异步 协程原理 占位符 placeholder (Future, Promise, Deferred) 循环引擎 greenlet 没有显式调度的微线程,换言之 协程

    gevent GitHub - gevent/gevent: Coroutine-based concurrency library for Python https://github.com/gev ...

  4. LOJ2125

    LOJ2125 树上操作 题目描述 有一棵点数为 N 的树,以点 1 为根,且树有点权.然后有 M 个操作,分为三种: 把某个节点 x 的点权增加 aa . 把某个节点 x 为根的子树中所有点的点权都 ...

  5. Spring 动态代理时是如何解决循环依赖的?为什么要使用三级缓存?

    前言 在研究 『 Spring 是如何解决循环依赖的 』 的时候,了解到 Spring 是借助三级缓存来解决循环依赖的. 同样在上一节留下了疑问: 循环依赖为什么要使用三级缓存?而不是使用二级缓存? ...

  6. php中一种单引号逃逸造成的注入

    demo如下: $post = $_POST; $sql=''; $array['name'] = $post['name']; $array['age'] = 18; $array['addr'] ...

  7. Docker+Prometheus+Alertmanager+Webhook钉钉告警

    Docker+Prometheus+Alertmanager+Webhook钉钉告警 1.环境部署 1.1 二进制部署 1.2 docker部署 1.2.1 webhook 1.2.2 alertma ...

  8. Redis-设置Key的过期时间及相关策略

    Redis-设置Key的过期时间及相关策略 1.设置key的过期时间 1.1expire key second:设置key的过期时间(秒) 1.2ttl key:查看key的有效期 1.3persis ...

  9. Python遍历目录下xlsx文件

    对指定目录下的指定类型文件进行遍历,可对文件名关键字进行条件筛选 返回值为文件地址的列表 import os # 定义一个函数,函数名字为get_all_excel,需要传入一个目录 def get_ ...

  10. 使用VMware WorkStation虚拟机软件安装CentOS 8

    使用VMware WorkStation虚拟机软件安装CentOS 8 说明:本章我们使用的虚拟机软件是VMware WorkStation15.5 PRO,镜像包是CentOS-8.2.2004-x ...