题目描述:

Given an integer, convert it to a roman numeral.

Input is guaranteed to be within the range from 1 to 3999.

解题思路:

这道题没什么技术含量,一个一个除10以及取模运算就行。

代码如下:

public class Solution {
public String intToRoman(int num) {
String Roman[][] = {
{"", "I", "II", "III", "IV", "V", "VI", "VII", "VIII", "IX"},
{"", "X", "XX", "XXX", "XL", "L", "LX", "LXX", "LXXX", "XC"},
{"", "C", "CC", "CCC", "CD", "D", "DC", "DCC", "DCCC", "CM"},
{"", "M", "MM", "MMM"}
};
int remainder;
int carry = num;
int index = 0;
String result = new String();
while(carry != 0){
remainder = carry % 10;
result = Roman[index][remainder] + result;
index++;
carry = carry / 10;
}
return result;
}
}

Java [leetcode 12] Integer to Roman的更多相关文章

  1. Leetcode 12——Integer to Roman

    12.Integer to Roman Given an integer, convert it to a roman numeral. Input is guaranteed to be withi ...

  2. Leetcode 12. Integer to Roman(打表,水)

    12. Integer to Roman Medium Roman numerals are represented by seven different symbols: I, V, X, L, C ...

  3. [LeetCode] 12. Integer to Roman 整数转化成罗马数字

    Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 ...

  4. [LeetCode] 12. Integer to Roman 整数转为罗马数字

    Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 ...

  5. [LeetCode] 12. Integer to Roman ☆☆

    Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 t ...

  6. [leetcode]12. Integer to Roman整数转罗马数字

    Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 ...

  7. LeetCode——12. Integer to Roman

    一.题目链接:https://leetcode.com/problems/integer-to-roman/ 二.题目大意: 给定一个整数,返回它的罗马数字的形式. 三.题解: 要想做出这道题目,首先 ...

  8. LeetCode 12 Integer to Roman (整数转罗马数字)

    题目链接: https://leetcode.com/problems/integer-to-roman/?tab=Description   String M[] = {"", ...

  9. [leetcode] 12. Integer to Roman

    关于罗马数字: I: 1V: 5X: 10L: 50C: 100D: 500M: 1000字母可以重复,但不超过三次,当需要超过三次时,用与下一位的组合表示:I: 1, II: 2, III: 3, ...

随机推荐

  1. CodeBlocks去掉拼写检查

    打开: 选择Compiler... 将红框里面的勾都点掉即可!

  2. UITableView自定义单元格

    随手笔记: RootViewController代码 #import "RootViewController.h" #import "AddressContact.h&q ...

  3. Spring Aop实例之xml配置

    AOP的配置方式有2种方式:xml配置和AspectJ注解方式.今天我们就来实践一下xml配置方式. 我采用的jdk代理,所以首先将接口和实现类代码附上 package com.tgb.aop; pu ...

  4. Visual Studio 中TODO List的使用

    http://msdn.microsoft.com/en-us/library/txtwdysk.aspx 工欲善其事,必先利其器 When the Task List is open, you ca ...

  5. 1025: [SCOI2009]游戏 - BZOJ

    Description windy学会了一种游戏.对于1到N这N个数字,都有唯一且不同的1到N的数字与之对应.最开始windy把数字按顺序1,2,3,……,N写一排在纸上.然后再在这一排下面写上它们对 ...

  6. 1014: [JSOI2008]火星人prefix - BZOJ

    Description 火星人最近研究了一种操作:求一个字串两个后缀的公共前缀.比方说,有这样一个字符串:madamimadam,我们将这个字符串的各个字符予以标号:序号: 1 2 3 4 5 6 7 ...

  7. 【数位DP】Hdu 3652:B-number

    B-number Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Su ...

  8. SDK更新问题解决

    更新C:\WINDOWS\system32\drivers\etc\host文件百试不爽 第一步 打开SDK Manager下Tools->Options,选中“Force https://… ...

  9. hdu 1176

    简单DP  类似于在一个矩形中求最长路径 /************************************************************************* > ...

  10. hdu 1085

    额    母函数 #include <cstdio> #include <cstring> int a[3],b[3]= {1,2,5}; int c1[10001],c2[1 ...